Displaying elements of a list, in columns
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I have a list of strings. I need to list them in rows and columns. Each row should not have more than "cols" number of values. Each of the values in a given row should be "step" away from the previous value. The values should appear only once in the output. Here is what I have. Any better way to write this code?
cols = 4
step = 10
vlist = ["Value" + str(i+1) for i in range(100)]
vlen = len(vlist)
start = 0
while start < vlen and start < step:
num = 0
for idx in range(start, vlen, step):
if num < cols:
print(vlist[idx], end=", ")
num += 1
print("n")
start += 1
python python-3.x formatting
New contributor
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add a comment |
$begingroup$
I have a list of strings. I need to list them in rows and columns. Each row should not have more than "cols" number of values. Each of the values in a given row should be "step" away from the previous value. The values should appear only once in the output. Here is what I have. Any better way to write this code?
cols = 4
step = 10
vlist = ["Value" + str(i+1) for i in range(100)]
vlen = len(vlist)
start = 0
while start < vlen and start < step:
num = 0
for idx in range(start, vlen, step):
if num < cols:
print(vlist[idx], end=", ")
num += 1
print("n")
start += 1
python python-3.x formatting
New contributor
$endgroup$
$begingroup$
Welcome to Code Review! IsEach [value] should be "step" away from the previous value
an "external" requirement? ((Block-) Quote the specification of the result to achieve.) Another interpretation is In a monospace font, each value shall be output 10 places to the right of the preceding one, the advantage being all values getting displayed.
$endgroup$
– greybeard
5 hours ago
add a comment |
$begingroup$
I have a list of strings. I need to list them in rows and columns. Each row should not have more than "cols" number of values. Each of the values in a given row should be "step" away from the previous value. The values should appear only once in the output. Here is what I have. Any better way to write this code?
cols = 4
step = 10
vlist = ["Value" + str(i+1) for i in range(100)]
vlen = len(vlist)
start = 0
while start < vlen and start < step:
num = 0
for idx in range(start, vlen, step):
if num < cols:
print(vlist[idx], end=", ")
num += 1
print("n")
start += 1
python python-3.x formatting
New contributor
$endgroup$
I have a list of strings. I need to list them in rows and columns. Each row should not have more than "cols" number of values. Each of the values in a given row should be "step" away from the previous value. The values should appear only once in the output. Here is what I have. Any better way to write this code?
cols = 4
step = 10
vlist = ["Value" + str(i+1) for i in range(100)]
vlen = len(vlist)
start = 0
while start < vlen and start < step:
num = 0
for idx in range(start, vlen, step):
if num < cols:
print(vlist[idx], end=", ")
num += 1
print("n")
start += 1
python python-3.x formatting
python python-3.x formatting
New contributor
New contributor
edited 5 hours ago
200_success
130k17153419
130k17153419
New contributor
asked 6 hours ago
RebornCodeLoverRebornCodeLover
61
61
New contributor
New contributor
$begingroup$
Welcome to Code Review! IsEach [value] should be "step" away from the previous value
an "external" requirement? ((Block-) Quote the specification of the result to achieve.) Another interpretation is In a monospace font, each value shall be output 10 places to the right of the preceding one, the advantage being all values getting displayed.
$endgroup$
– greybeard
5 hours ago
add a comment |
$begingroup$
Welcome to Code Review! IsEach [value] should be "step" away from the previous value
an "external" requirement? ((Block-) Quote the specification of the result to achieve.) Another interpretation is In a monospace font, each value shall be output 10 places to the right of the preceding one, the advantage being all values getting displayed.
$endgroup$
– greybeard
5 hours ago
$begingroup$
Welcome to Code Review! Is
Each [value] should be "step" away from the previous value
an "external" requirement? ((Block-) Quote the specification of the result to achieve.) Another interpretation is In a monospace font, each value shall be output 10 places to the right of the preceding one, the advantage being all values getting displayed.$endgroup$
– greybeard
5 hours ago
$begingroup$
Welcome to Code Review! Is
Each [value] should be "step" away from the previous value
an "external" requirement? ((Block-) Quote the specification of the result to achieve.) Another interpretation is In a monospace font, each value shall be output 10 places to the right of the preceding one, the advantage being all values getting displayed.$endgroup$
– greybeard
5 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Fancy iteration in Python is often made easier using the itertools
module. For this case, itertools.islice()
can help pick out the values for each row.
from itertools import islice
cols = 4
step = 10
vlist = ["Value" + str(i+1) for i in range(100)]
for row in (islice(vlist, i, cols * step, step) for i in range(step)):
print(', '.join(row), end=", nn")
$endgroup$
add a comment |
$begingroup$
The code can be made more understandable by:
- introducing row and column indices
- replace the while loop with a for loop
- calculate the index for
vlist
from the values of the row/col indices
This reduces the number of help variables needed and could result in something like this:
vlist = ["Value" + str(i+1) for i in range(100)]
cols = 4
rows = 10
for row_idx in range(rows):
for col_idx in range(cols):
idx = row_idx + rows * col_idx
print(vlist[idx], end=", ")
print("n")
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Fancy iteration in Python is often made easier using the itertools
module. For this case, itertools.islice()
can help pick out the values for each row.
from itertools import islice
cols = 4
step = 10
vlist = ["Value" + str(i+1) for i in range(100)]
for row in (islice(vlist, i, cols * step, step) for i in range(step)):
print(', '.join(row), end=", nn")
$endgroup$
add a comment |
$begingroup$
Fancy iteration in Python is often made easier using the itertools
module. For this case, itertools.islice()
can help pick out the values for each row.
from itertools import islice
cols = 4
step = 10
vlist = ["Value" + str(i+1) for i in range(100)]
for row in (islice(vlist, i, cols * step, step) for i in range(step)):
print(', '.join(row), end=", nn")
$endgroup$
add a comment |
$begingroup$
Fancy iteration in Python is often made easier using the itertools
module. For this case, itertools.islice()
can help pick out the values for each row.
from itertools import islice
cols = 4
step = 10
vlist = ["Value" + str(i+1) for i in range(100)]
for row in (islice(vlist, i, cols * step, step) for i in range(step)):
print(', '.join(row), end=", nn")
$endgroup$
Fancy iteration in Python is often made easier using the itertools
module. For this case, itertools.islice()
can help pick out the values for each row.
from itertools import islice
cols = 4
step = 10
vlist = ["Value" + str(i+1) for i in range(100)]
for row in (islice(vlist, i, cols * step, step) for i in range(step)):
print(', '.join(row), end=", nn")
edited 4 hours ago
answered 4 hours ago
200_success200_success
130k17153419
130k17153419
add a comment |
add a comment |
$begingroup$
The code can be made more understandable by:
- introducing row and column indices
- replace the while loop with a for loop
- calculate the index for
vlist
from the values of the row/col indices
This reduces the number of help variables needed and could result in something like this:
vlist = ["Value" + str(i+1) for i in range(100)]
cols = 4
rows = 10
for row_idx in range(rows):
for col_idx in range(cols):
idx = row_idx + rows * col_idx
print(vlist[idx], end=", ")
print("n")
$endgroup$
add a comment |
$begingroup$
The code can be made more understandable by:
- introducing row and column indices
- replace the while loop with a for loop
- calculate the index for
vlist
from the values of the row/col indices
This reduces the number of help variables needed and could result in something like this:
vlist = ["Value" + str(i+1) for i in range(100)]
cols = 4
rows = 10
for row_idx in range(rows):
for col_idx in range(cols):
idx = row_idx + rows * col_idx
print(vlist[idx], end=", ")
print("n")
$endgroup$
add a comment |
$begingroup$
The code can be made more understandable by:
- introducing row and column indices
- replace the while loop with a for loop
- calculate the index for
vlist
from the values of the row/col indices
This reduces the number of help variables needed and could result in something like this:
vlist = ["Value" + str(i+1) for i in range(100)]
cols = 4
rows = 10
for row_idx in range(rows):
for col_idx in range(cols):
idx = row_idx + rows * col_idx
print(vlist[idx], end=", ")
print("n")
$endgroup$
The code can be made more understandable by:
- introducing row and column indices
- replace the while loop with a for loop
- calculate the index for
vlist
from the values of the row/col indices
This reduces the number of help variables needed and could result in something like this:
vlist = ["Value" + str(i+1) for i in range(100)]
cols = 4
rows = 10
for row_idx in range(rows):
for col_idx in range(cols):
idx = row_idx + rows * col_idx
print(vlist[idx], end=", ")
print("n")
answered 5 hours ago
Jan KuikenJan Kuiken
86838
86838
add a comment |
add a comment |
RebornCodeLover is a new contributor. Be nice, and check out our Code of Conduct.
RebornCodeLover is a new contributor. Be nice, and check out our Code of Conduct.
RebornCodeLover is a new contributor. Be nice, and check out our Code of Conduct.
RebornCodeLover is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Welcome to Code Review! Is
Each [value] should be "step" away from the previous value
an "external" requirement? ((Block-) Quote the specification of the result to achieve.) Another interpretation is In a monospace font, each value shall be output 10 places to the right of the preceding one, the advantage being all values getting displayed.$endgroup$
– greybeard
5 hours ago