how to slice a string by characters in Python?












6















There is a string with one or more characters. I want to slice the list so that the adjoining same characters are in the same element. For example:



'a' -> ['a']
'abbbcc' -> ['a', 'bbb', 'cc']
'abcabc' -> ['a', 'b', 'c', 'a', 'b', 'c']


How to make this in Python?










share|improve this question


















  • 1





    FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.

    – Aran-Fey
    2 hours ago
















6















There is a string with one or more characters. I want to slice the list so that the adjoining same characters are in the same element. For example:



'a' -> ['a']
'abbbcc' -> ['a', 'bbb', 'cc']
'abcabc' -> ['a', 'b', 'c', 'a', 'b', 'c']


How to make this in Python?










share|improve this question


















  • 1





    FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.

    – Aran-Fey
    2 hours ago














6












6








6








There is a string with one or more characters. I want to slice the list so that the adjoining same characters are in the same element. For example:



'a' -> ['a']
'abbbcc' -> ['a', 'bbb', 'cc']
'abcabc' -> ['a', 'b', 'c', 'a', 'b', 'c']


How to make this in Python?










share|improve this question














There is a string with one or more characters. I want to slice the list so that the adjoining same characters are in the same element. For example:



'a' -> ['a']
'abbbcc' -> ['a', 'bbb', 'cc']
'abcabc' -> ['a', 'b', 'c', 'a', 'b', 'c']


How to make this in Python?







python






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 2 hours ago









Hank ChowHank Chow

391




391








  • 1





    FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.

    – Aran-Fey
    2 hours ago














  • 1





    FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.

    – Aran-Fey
    2 hours ago








1




1





FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.

– Aran-Fey
2 hours ago





FYI, if you google "python group identical elements" or something similar you'll find plenty of recipes that would help you get started.

– Aran-Fey
2 hours ago












4 Answers
4






active

oldest

votes


















9














Use itertools.groupby:



from itertools import groupby

s = 'abccbba'

print([''.join(v) for _, v in groupby(s)])
# ['a', 'b', 'cc', 'bb', 'a']





share|improve this answer

































    4














    Can be achieved with re.finditer()



    import re
    s='aabccdd'
    print([m.group(0) for m in re.finditer(r"(w)1*", s)])
    #['aa', 'b', 'cc', 'dd']





    share|improve this answer































      0














      Without any modules and using for loop also it can be done in interesting way:



      l=
      str="aabccc"
      s=str[0]
      for c in str[1:]:

      if(c!=s[-1]):
      l.append(s)
      s=c
      else:
      s=s+c
      l.append(s)
      print(l)





      share|improve this answer








      New contributor




      Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




























        0














        Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.



        from functools import reduce   # in python3
        s='aaabccdddddaa'
        reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, )





        share|improve this answer























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          4 Answers
          4






          active

          oldest

          votes








          4 Answers
          4






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          9














          Use itertools.groupby:



          from itertools import groupby

          s = 'abccbba'

          print([''.join(v) for _, v in groupby(s)])
          # ['a', 'b', 'cc', 'bb', 'a']





          share|improve this answer






























            9














            Use itertools.groupby:



            from itertools import groupby

            s = 'abccbba'

            print([''.join(v) for _, v in groupby(s)])
            # ['a', 'b', 'cc', 'bb', 'a']





            share|improve this answer




























              9












              9








              9







              Use itertools.groupby:



              from itertools import groupby

              s = 'abccbba'

              print([''.join(v) for _, v in groupby(s)])
              # ['a', 'b', 'cc', 'bb', 'a']





              share|improve this answer















              Use itertools.groupby:



              from itertools import groupby

              s = 'abccbba'

              print([''.join(v) for _, v in groupby(s)])
              # ['a', 'b', 'cc', 'bb', 'a']






              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited 2 hours ago









              Aran-Fey

              20.8k53671




              20.8k53671










              answered 2 hours ago









              AustinAustin

              12.2k3929




              12.2k3929

























                  4














                  Can be achieved with re.finditer()



                  import re
                  s='aabccdd'
                  print([m.group(0) for m in re.finditer(r"(w)1*", s)])
                  #['aa', 'b', 'cc', 'dd']





                  share|improve this answer




























                    4














                    Can be achieved with re.finditer()



                    import re
                    s='aabccdd'
                    print([m.group(0) for m in re.finditer(r"(w)1*", s)])
                    #['aa', 'b', 'cc', 'dd']





                    share|improve this answer


























                      4












                      4








                      4







                      Can be achieved with re.finditer()



                      import re
                      s='aabccdd'
                      print([m.group(0) for m in re.finditer(r"(w)1*", s)])
                      #['aa', 'b', 'cc', 'dd']





                      share|improve this answer













                      Can be achieved with re.finditer()



                      import re
                      s='aabccdd'
                      print([m.group(0) for m in re.finditer(r"(w)1*", s)])
                      #['aa', 'b', 'cc', 'dd']






                      share|improve this answer












                      share|improve this answer



                      share|improve this answer










                      answered 2 hours ago









                      denis_lordenis_lor

                      1,36111030




                      1,36111030























                          0














                          Without any modules and using for loop also it can be done in interesting way:



                          l=
                          str="aabccc"
                          s=str[0]
                          for c in str[1:]:

                          if(c!=s[-1]):
                          l.append(s)
                          s=c
                          else:
                          s=s+c
                          l.append(s)
                          print(l)





                          share|improve this answer








                          New contributor




                          Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.

























                            0














                            Without any modules and using for loop also it can be done in interesting way:



                            l=
                            str="aabccc"
                            s=str[0]
                            for c in str[1:]:

                            if(c!=s[-1]):
                            l.append(s)
                            s=c
                            else:
                            s=s+c
                            l.append(s)
                            print(l)





                            share|improve this answer








                            New contributor




                            Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.























                              0












                              0








                              0







                              Without any modules and using for loop also it can be done in interesting way:



                              l=
                              str="aabccc"
                              s=str[0]
                              for c in str[1:]:

                              if(c!=s[-1]):
                              l.append(s)
                              s=c
                              else:
                              s=s+c
                              l.append(s)
                              print(l)





                              share|improve this answer








                              New contributor




                              Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.










                              Without any modules and using for loop also it can be done in interesting way:



                              l=
                              str="aabccc"
                              s=str[0]
                              for c in str[1:]:

                              if(c!=s[-1]):
                              l.append(s)
                              s=c
                              else:
                              s=s+c
                              l.append(s)
                              print(l)






                              share|improve this answer








                              New contributor




                              Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.









                              share|improve this answer



                              share|improve this answer






                              New contributor




                              Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.









                              answered 1 hour ago









                              TojrahTojrah

                              1




                              1




                              New contributor




                              Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.





                              New contributor





                              Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.






                              Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                              Check out our Code of Conduct.























                                  0














                                  Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.



                                  from functools import reduce   # in python3
                                  s='aaabccdddddaa'
                                  reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, )





                                  share|improve this answer




























                                    0














                                    Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.



                                    from functools import reduce   # in python3
                                    s='aaabccdddddaa'
                                    reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, )





                                    share|improve this answer


























                                      0












                                      0








                                      0







                                      Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.



                                      from functools import reduce   # in python3
                                      s='aaabccdddddaa'
                                      reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, )





                                      share|improve this answer













                                      Just one more alternative solution. You need no import for it in python2. In python3 you need import from functools.



                                      from functools import reduce   # in python3
                                      s='aaabccdddddaa'
                                      reduce(lambda x,y:x[:-1]+[x[-1]+y] if len(x)>0 and x[-1][-1]==y else x+[y], s, )






                                      share|improve this answer












                                      share|improve this answer



                                      share|improve this answer










                                      answered 37 mins ago









                                      quantummindquantummind

                                      1,3341817




                                      1,3341817






























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