Unable to have a local variable with the same name as a global read-only variable
0
#!/bin/bash
readonly x=2
function test {
local x=1
echo ${x}
}
test
echo $x
The result is,
readonly-local-test.sh: line 6: local: x: readonly variable
2
2
When the variable is read-only this happens. However, if I remove the readonly restriction as below,
#!/bin/bash
x=2
function test {
local x=1
echo ${x}
}
test
echo $x
The result is,
1
2
Why read only global variables can't be shadowed?
bash shell-script
asked 9 mins ago
SnitchSnitch
1012
New contributor
Snitch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
0
#!/bin/bash
readonly x=2
function test {
local x=1
echo ${x}
}
test
echo $x
The result is,
readonly-local-test.sh: line 6: local: x: readonly variable
2
2
When the variable is read-only this happens. However, if I remove the readonly restriction as below,
#!/bin/bash
x=2
function test {
local x=1
echo ${x}
}
test
echo $x
The result is,
1
2
Why read only global variables can't be shadowed?
bash shell-script
asked 9 mins ago
SnitchSnitch
1012
New contributor
Snitch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
You just can't redefine thereadonlyvariables
– Inian
4 mins ago
add a comment |
0
0
0
#!/bin/bash
readonly x=2
function test {
local x=1
echo ${x}
}
test
echo $x
The result is,
readonly-local-test.sh: line 6: local: x: readonly variable
2
2
When the variable is read-only this happens. However, if I remove the readonly restriction as below,
#!/bin/bash
x=2
function test {
local x=1
echo ${x}
}
test
echo $x
The result is,
1
2
Why read only global variables can't be shadowed?
bash shell-script
asked 9 mins ago
SnitchSnitch
1012
New contributor
Snitch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
#!/bin/bash
readonly x=2
function test {
local x=1
echo ${x}
}
test
echo $x
The result is,
readonly-local-test.sh: line 6: local: x: readonly variable
2
2
When the variable is read-only this happens. However, if I remove the readonly restriction as below,
#!/bin/bash
x=2
function test {
local x=1
echo ${x}
}
test
echo $x
The result is,
1
2
Why read only global variables can't be shadowed?
bash shell-script
bash shell-script
asked 9 mins ago
SnitchSnitch
1012
New contributor
Snitch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 mins ago
SnitchSnitch
1012
New contributor
Snitch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 mins ago
SnitchSnitch
1012
New contributor
Snitch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 mins ago
SnitchSnitch
1012
asked 9 mins ago
SnitchSnitch
1012
1012
New contributor
Snitch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Snitch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Snitch is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
You just can't redefine thereadonlyvariables
– Inian
4 mins ago
add a comment |
You just can't redefine thereadonlyvariables
– Inian
4 mins ago
You just can't redefine the
readonly variables– Inian
4 mins ago
You just can't redefine the
readonly variables– Inian
4 mins ago
add a comment |
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You just can't redefine the
readonlyvariables– Inian
4 mins ago