Getting exit code from Curl input bash script
I want to take the output of simple.sh, a script from the internet and check its exit code.
#!/bin/bash
$(curl -s http://127.0.0.1:8000/simple.sh)
if [ -z "$?" ]; then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
simple.sh:
#!/bin/bash
exit 0
The problem I am getting is:
./test.sh: line 2: #!/bin/bash: No such file or directory
Bad
Any help is much appreciated.
Thank you
bash shell-script scripting curl
asked 1 hour ago
RiceRice
16610
add a comment |
I want to take the output of simple.sh, a script from the internet and check its exit code.
#!/bin/bash
$(curl -s http://127.0.0.1:8000/simple.sh)
if [ -z "$?" ]; then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
simple.sh:
#!/bin/bash
exit 0
The problem I am getting is:
./test.sh: line 2: #!/bin/bash: No such file or directory
Bad
Any help is much appreciated.
Thank you
bash shell-script scripting curl
asked 1 hour ago
RiceRice
16610
Try adding the full path tocurl, i.e. the output fromtype curl. Probably a path issue.
– datUser
1 hour ago
tryeval "$(curl ...)"
– Jonas
23 mins ago
add a comment |
I want to take the output of simple.sh, a script from the internet and check its exit code.
#!/bin/bash
$(curl -s http://127.0.0.1:8000/simple.sh)
if [ -z "$?" ]; then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
simple.sh:
#!/bin/bash
exit 0
The problem I am getting is:
./test.sh: line 2: #!/bin/bash: No such file or directory
Bad
Any help is much appreciated.
Thank you
bash shell-script scripting curl
asked 1 hour ago
RiceRice
16610
I want to take the output of simple.sh, a script from the internet and check its exit code.
#!/bin/bash
$(curl -s http://127.0.0.1:8000/simple.sh)
if [ -z "$?" ]; then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
simple.sh:
#!/bin/bash
exit 0
The problem I am getting is:
./test.sh: line 2: #!/bin/bash: No such file or directory
Bad
Any help is much appreciated.
Thank you
bash shell-script scripting curl
bash shell-script scripting curl
asked 1 hour ago
RiceRice
16610
asked 1 hour ago
RiceRice
16610
asked 1 hour ago
RiceRice
16610
asked 1 hour ago
RiceRice
16610
asked 1 hour ago
RiceRice
16610
16610
Try adding the full path tocurl, i.e. the output fromtype curl. Probably a path issue.
– datUser
1 hour ago
tryeval "$(curl ...)"
– Jonas
23 mins ago
add a comment |
Try adding the full path tocurl, i.e. the output fromtype curl. Probably a path issue.
– datUser
1 hour ago
tryeval "$(curl ...)"
– Jonas
23 mins ago
Try adding the full path to
curl, i.e. the output from type curl. Probably a path issue.– datUser
1 hour ago
Try adding the full path to
curl, i.e. the output from type curl. Probably a path issue.– datUser
1 hour ago
try
eval "$(curl ...)"– Jonas
23 mins ago
try
eval "$(curl ...)"– Jonas
23 mins ago
add a comment |
1 Answer
1
active
oldest
votes
Can't say it's elegant, but this is the way I would do it:#!/bin/bash
curl -s http://127.0.0.1:8000/simple.sh | /bin/bash -s >/dev/null 2>&1
rc=$?
if [ -z "$rc" ]
then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
Seems to me, the way you are doing it is similar to executing a here-file inside the $( ... ) construct. Never tried that, not sure bash works that way.
Letting curl echo the contents of the file and piping it to bash accounts for the text output of the curl command and allows bash to execute it.
I'll bet that, if you try this, you will get the same results:$( cat /[path]/simple.sh ); echo $?
answered 8 mins ago
Scottie HScottie H
326
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Can't say it's elegant, but this is the way I would do it:#!/bin/bash
curl -s http://127.0.0.1:8000/simple.sh | /bin/bash -s >/dev/null 2>&1
rc=$?
if [ -z "$rc" ]
then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
Seems to me, the way you are doing it is similar to executing a here-file inside the $( ... ) construct. Never tried that, not sure bash works that way.
Letting curl echo the contents of the file and piping it to bash accounts for the text output of the curl command and allows bash to execute it.
I'll bet that, if you try this, you will get the same results:$( cat /[path]/simple.sh ); echo $?
answered 8 mins ago
Scottie HScottie H
326
add a comment |
Can't say it's elegant, but this is the way I would do it:#!/bin/bash
curl -s http://127.0.0.1:8000/simple.sh | /bin/bash -s >/dev/null 2>&1
rc=$?
if [ -z "$rc" ]
then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
Seems to me, the way you are doing it is similar to executing a here-file inside the $( ... ) construct. Never tried that, not sure bash works that way.
Letting curl echo the contents of the file and piping it to bash accounts for the text output of the curl command and allows bash to execute it.
I'll bet that, if you try this, you will get the same results:$( cat /[path]/simple.sh ); echo $?
answered 8 mins ago
Scottie HScottie H
326
add a comment |
Can't say it's elegant, but this is the way I would do it:#!/bin/bash
curl -s http://127.0.0.1:8000/simple.sh | /bin/bash -s >/dev/null 2>&1
rc=$?
if [ -z "$rc" ]
then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
Seems to me, the way you are doing it is similar to executing a here-file inside the $( ... ) construct. Never tried that, not sure bash works that way.
Letting curl echo the contents of the file and piping it to bash accounts for the text output of the curl command and allows bash to execute it.
I'll bet that, if you try this, you will get the same results:$( cat /[path]/simple.sh ); echo $?
answered 8 mins ago
Scottie HScottie H
326
Can't say it's elegant, but this is the way I would do it:#!/bin/bash
curl -s http://127.0.0.1:8000/simple.sh | /bin/bash -s >/dev/null 2>&1
rc=$?
if [ -z "$rc" ]
then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
Seems to me, the way you are doing it is similar to executing a here-file inside the $( ... ) construct. Never tried that, not sure bash works that way.
Letting curl echo the contents of the file and piping it to bash accounts for the text output of the curl command and allows bash to execute it.
I'll bet that, if you try this, you will get the same results:$( cat /[path]/simple.sh ); echo $?
answered 8 mins ago
Scottie HScottie H
326
answered 8 mins ago
Scottie HScottie H
326
answered 8 mins ago
Scottie HScottie H
326
answered 8 mins ago
Scottie HScottie H
326
326
add a comment |
add a comment |
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Try adding the full path to
curl, i.e. the output fromtype curl. Probably a path issue.– datUser
1 hour ago
try
eval "$(curl ...)"– Jonas
23 mins ago