Are “sockets” addressing a display of a X server and connected to or created by X client the same...
A X server is said to be started in a display. The address of a display is specified as a socket by
$DISPLAY. For example if$DISPLAYis:40, it corresponds to a port 6040 or a unix domain socket named after 40.A X client and a X server communicate by sockets.
What does the socket specified by $DISPLAY in the first sentence mean?
Are "socket" addressing a display of a X server (in the first sentence) and "socket" created by a X server and connected to a X client (in the second sentence) the same "socket"?
But I don't think they are the same socket, because I think
X client <-> X server <-> display
so a X client and a display are not connected directly but indirectly via a X server. So a X client can't communicate directly with the display addressed by $DISPLAY?
Thanks.
display x-server
asked 42 mins ago
TimTim
27.7k78264483
add a comment |
A X server is said to be started in a display. The address of a display is specified as a socket by
$DISPLAY. For example if$DISPLAYis:40, it corresponds to a port 6040 or a unix domain socket named after 40.A X client and a X server communicate by sockets.
What does the socket specified by $DISPLAY in the first sentence mean?
Are "socket" addressing a display of a X server (in the first sentence) and "socket" created by a X server and connected to a X client (in the second sentence) the same "socket"?
But I don't think they are the same socket, because I think
X client <-> X server <-> display
so a X client and a display are not connected directly but indirectly via a X server. So a X client can't communicate directly with the display addressed by $DISPLAY?
Thanks.
display x-server
asked 42 mins ago
TimTim
27.7k78264483
unix.stackexchange.com/questions/503870/… So most phrases used in your question is meaningless. An X server is a display. Use the right syntax:40orHOSTNAME:40, not40. X client and X server communicates with X11 protocol(over TCP or UDS), not nessacarily sockets because some platform doesn't have it. For linux, sockets or any file can't be owned by a process, linux doesn't have this concept.
– 炸鱼薯条德里克
27 mins ago
add a comment |
A X server is said to be started in a display. The address of a display is specified as a socket by
$DISPLAY. For example if$DISPLAYis:40, it corresponds to a port 6040 or a unix domain socket named after 40.A X client and a X server communicate by sockets.
What does the socket specified by $DISPLAY in the first sentence mean?
Are "socket" addressing a display of a X server (in the first sentence) and "socket" created by a X server and connected to a X client (in the second sentence) the same "socket"?
But I don't think they are the same socket, because I think
X client <-> X server <-> display
so a X client and a display are not connected directly but indirectly via a X server. So a X client can't communicate directly with the display addressed by $DISPLAY?
Thanks.
display x-server
asked 42 mins ago
TimTim
27.7k78264483
A X server is said to be started in a display. The address of a display is specified as a socket by
$DISPLAY. For example if$DISPLAYis:40, it corresponds to a port 6040 or a unix domain socket named after 40.A X client and a X server communicate by sockets.
What does the socket specified by $DISPLAY in the first sentence mean?
Are "socket" addressing a display of a X server (in the first sentence) and "socket" created by a X server and connected to a X client (in the second sentence) the same "socket"?
But I don't think they are the same socket, because I think
X client <-> X server <-> display
so a X client and a display are not connected directly but indirectly via a X server. So a X client can't communicate directly with the display addressed by $DISPLAY?
Thanks.
display x-server
display x-server
asked 42 mins ago
TimTim
27.7k78264483
asked 42 mins ago
TimTim
27.7k78264483
edited 23 mins ago
Tim
asked 42 mins ago
TimTim
27.7k78264483
asked 42 mins ago
TimTim
27.7k78264483
asked 42 mins ago
TimTim
27.7k78264483
27.7k78264483
unix.stackexchange.com/questions/503870/… So most phrases used in your question is meaningless. An X server is a display. Use the right syntax:40orHOSTNAME:40, not40. X client and X server communicates with X11 protocol(over TCP or UDS), not nessacarily sockets because some platform doesn't have it. For linux, sockets or any file can't be owned by a process, linux doesn't have this concept.
– 炸鱼薯条德里克
27 mins ago
add a comment |
unix.stackexchange.com/questions/503870/… So most phrases used in your question is meaningless. An X server is a display. Use the right syntax:40orHOSTNAME:40, not40. X client and X server communicates with X11 protocol(over TCP or UDS), not nessacarily sockets because some platform doesn't have it. For linux, sockets or any file can't be owned by a process, linux doesn't have this concept.
– 炸鱼薯条德里克
27 mins ago
unix.stackexchange.com/questions/503870/… So most phrases used in your question is meaningless. An X server is a display. Use the right syntax
:40 or HOSTNAME:40, not 40. X client and X server communicates with X11 protocol(over TCP or UDS), not nessacarily sockets because some platform doesn't have it. For linux, sockets or any file can't be owned by a process, linux doesn't have this concept.– 炸鱼薯条德里克
27 mins ago
unix.stackexchange.com/questions/503870/… So most phrases used in your question is meaningless. An X server is a display. Use the right syntax
:40 or HOSTNAME:40, not 40. X client and X server communicates with X11 protocol(over TCP or UDS), not nessacarily sockets because some platform doesn't have it. For linux, sockets or any file can't be owned by a process, linux doesn't have this concept.– 炸鱼薯条德里克
27 mins ago
add a comment |
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unix.stackexchange.com/questions/503870/… So most phrases used in your question is meaningless. An X server is a display. Use the right syntax
:40orHOSTNAME:40, not40. X client and X server communicates with X11 protocol(over TCP or UDS), not nessacarily sockets because some platform doesn't have it. For linux, sockets or any file can't be owned by a process, linux doesn't have this concept.– 炸鱼薯条德里克
27 mins ago