How do I set a bash variable that contains another variable?
I am trying to set the variable service to be the value of
var1=first/second
echo $var1 | cut -d '/' -f 1
var2=$var1 | cut -d '/' -f 1"
echo $var2
The result of echo $var1 | cut -d '/' -f 1 is "first" which is correct. However, I haven't been able to set the result of this to another variable. In the case above, var2 is empty.
What would the correct syntax for line 3 be so that the part of the string before the is returned as the value of var2?
bash shell-script
asked 2 hours ago
fuzzifuzzi
64
New contributor
fuzzi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I am trying to set the variable service to be the value of
var1=first/second
echo $var1 | cut -d '/' -f 1
var2=$var1 | cut -d '/' -f 1"
echo $var2
The result of echo $var1 | cut -d '/' -f 1 is "first" which is correct. However, I haven't been able to set the result of this to another variable. In the case above, var2 is empty.
What would the correct syntax for line 3 be so that the part of the string before the is returned as the value of var2?
bash shell-script
asked 2 hours ago
fuzzifuzzi
64
New contributor
fuzzi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Possible duplicate of How can I assign the output of a command to a shell variable?
– G-Man
1 hour ago
See also Storing output of command in shell variable, Calculate variable and output it to another variable, Bash: Assign output of pipe to a variable, setting output of a command to a variable, and more.
– G-Man
1 hour ago
add a comment |
I am trying to set the variable service to be the value of
var1=first/second
echo $var1 | cut -d '/' -f 1
var2=$var1 | cut -d '/' -f 1"
echo $var2
The result of echo $var1 | cut -d '/' -f 1 is "first" which is correct. However, I haven't been able to set the result of this to another variable. In the case above, var2 is empty.
What would the correct syntax for line 3 be so that the part of the string before the is returned as the value of var2?
bash shell-script
asked 2 hours ago
fuzzifuzzi
64
New contributor
fuzzi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am trying to set the variable service to be the value of
var1=first/second
echo $var1 | cut -d '/' -f 1
var2=$var1 | cut -d '/' -f 1"
echo $var2
The result of echo $var1 | cut -d '/' -f 1 is "first" which is correct. However, I haven't been able to set the result of this to another variable. In the case above, var2 is empty.
What would the correct syntax for line 3 be so that the part of the string before the is returned as the value of var2?
bash shell-script
bash shell-script
asked 2 hours ago
fuzzifuzzi
64
New contributor
fuzzi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
fuzzifuzzi
64
New contributor
fuzzi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
fuzzifuzzi
64
New contributor
fuzzi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
fuzzifuzzi
64
asked 2 hours ago
fuzzifuzzi
64
64
New contributor
fuzzi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
fuzzi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
fuzzi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Possible duplicate of How can I assign the output of a command to a shell variable?
– G-Man
1 hour ago
See also Storing output of command in shell variable, Calculate variable and output it to another variable, Bash: Assign output of pipe to a variable, setting output of a command to a variable, and more.
– G-Man
1 hour ago
add a comment |
Possible duplicate of How can I assign the output of a command to a shell variable?
– G-Man
1 hour ago
See also Storing output of command in shell variable, Calculate variable and output it to another variable, Bash: Assign output of pipe to a variable, setting output of a command to a variable, and more.
– G-Man
1 hour ago
Possible duplicate of How can I assign the output of a command to a shell variable?
– G-Man
1 hour ago
Possible duplicate of How can I assign the output of a command to a shell variable?
– G-Man
1 hour ago
See also Storing output of command in shell variable, Calculate variable and output it to another variable, Bash: Assign output of pipe to a variable, setting output of a command to a variable, and more.
– G-Man
1 hour ago
See also Storing output of command in shell variable, Calculate variable and output it to another variable, Bash: Assign output of pipe to a variable, setting output of a command to a variable, and more.
– G-Man
1 hour ago
add a comment |
1 Answer
1
active
oldest
votes
You could use command substitution
var2=$(echo "$var1" | cut -d '/' -f 1)
However in this case it would be better to use the shell's parameter substitution directly:
$ var2=${var1%/*}
$ echo "$var2"
first
(removes the shortest trailing substring matching /*) and
$ var3=${var1#*/}
$ echo "$var3"
second
(removes the shortest leading substring matching */) should you need it as well.
answered 2 hours ago
steeldriversteeldriver
36.8k45287
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
active
oldest
votes
active
oldest
votes
You could use command substitution
var2=$(echo "$var1" | cut -d '/' -f 1)
However in this case it would be better to use the shell's parameter substitution directly:
$ var2=${var1%/*}
$ echo "$var2"
first
(removes the shortest trailing substring matching /*) and
$ var3=${var1#*/}
$ echo "$var3"
second
(removes the shortest leading substring matching */) should you need it as well.
answered 2 hours ago
steeldriversteeldriver
36.8k45287
add a comment |
You could use command substitution
var2=$(echo "$var1" | cut -d '/' -f 1)
However in this case it would be better to use the shell's parameter substitution directly:
$ var2=${var1%/*}
$ echo "$var2"
first
(removes the shortest trailing substring matching /*) and
$ var3=${var1#*/}
$ echo "$var3"
second
(removes the shortest leading substring matching */) should you need it as well.
answered 2 hours ago
steeldriversteeldriver
36.8k45287
add a comment |
You could use command substitution
var2=$(echo "$var1" | cut -d '/' -f 1)
However in this case it would be better to use the shell's parameter substitution directly:
$ var2=${var1%/*}
$ echo "$var2"
first
(removes the shortest trailing substring matching /*) and
$ var3=${var1#*/}
$ echo "$var3"
second
(removes the shortest leading substring matching */) should you need it as well.
answered 2 hours ago
steeldriversteeldriver
36.8k45287
You could use command substitution
var2=$(echo "$var1" | cut -d '/' -f 1)
However in this case it would be better to use the shell's parameter substitution directly:
$ var2=${var1%/*}
$ echo "$var2"
first
(removes the shortest trailing substring matching /*) and
$ var3=${var1#*/}
$ echo "$var3"
second
(removes the shortest leading substring matching */) should you need it as well.
answered 2 hours ago
steeldriversteeldriver
36.8k45287
answered 2 hours ago
steeldriversteeldriver
36.8k45287
answered 2 hours ago
steeldriversteeldriver
36.8k45287
answered 2 hours ago
steeldriversteeldriver
36.8k45287
36.8k45287
add a comment |
add a comment |
fuzzi is a new contributor. Be nice, and check out our Code of Conduct.
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Possible duplicate of How can I assign the output of a command to a shell variable?
– G-Man
1 hour ago
See also Storing output of command in shell variable, Calculate variable and output it to another variable, Bash: Assign output of pipe to a variable, setting output of a command to a variable, and more.
– G-Man
1 hour ago