sed - delete lines matching pattern if it is repeated
Say I have a config file:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[extra]
[footer]
[tail]
print = true
[end]
I want to print the headers ([text]
) only if there are options underneath. So the output should be:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[tail]
print = true
How do I achieve this using sed?
text-processing sed
add a comment |
Say I have a config file:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[extra]
[footer]
[tail]
print = true
[end]
I want to print the headers ([text]
) only if there are options underneath. So the output should be:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[tail]
print = true
How do I achieve this using sed?
text-processing sed
add a comment |
Say I have a config file:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[extra]
[footer]
[tail]
print = true
[end]
I want to print the headers ([text]
) only if there are options underneath. So the output should be:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[tail]
print = true
How do I achieve this using sed?
text-processing sed
Say I have a config file:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[extra]
[footer]
[tail]
print = true
[end]
I want to print the headers ([text]
) only if there are options underneath. So the output should be:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[tail]
print = true
How do I achieve this using sed?
text-processing sed
text-processing sed
asked 3 mins ago
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3,51432340
add a comment |
add a comment |
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