Looping 'find…-type f': Getting filenames by dir/subdir, ouputing a txt with name dir_subdir_fname.txt
My data structure is something like:
dir1/subdir1_level1/subdir1_level2.../subdir1_leveln
dir1/subdir2_level1/subdir2_level2.../subdir2_leveln
...
Which means that the levels I'm working with are not structured properly, nevertheless.
I managed to accomplish my objective of getting the filename according to the first 2 levels of the path, and output them to a text file named dirn_subdirn_fname.txt with:
find dir1/subdir1 -type f -printf "%fn">dir1_subdir1_fname.txt
But I was wondering if there was a way to Iterate this process across a list of several dir/subdir's
edit: I found a way to do the first part:
#!/bin/bash
shopt -s dotglob nullglob
topdir= './Dir1'
for subdir in "$topdir"; do
find "$subdir" -type f -printf "%fn"
done
bash shell-script awk perl
New contributor
add a comment |
My data structure is something like:
dir1/subdir1_level1/subdir1_level2.../subdir1_leveln
dir1/subdir2_level1/subdir2_level2.../subdir2_leveln
...
Which means that the levels I'm working with are not structured properly, nevertheless.
I managed to accomplish my objective of getting the filename according to the first 2 levels of the path, and output them to a text file named dirn_subdirn_fname.txt with:
find dir1/subdir1 -type f -printf "%fn">dir1_subdir1_fname.txt
But I was wondering if there was a way to Iterate this process across a list of several dir/subdir's
edit: I found a way to do the first part:
#!/bin/bash
shopt -s dotglob nullglob
topdir= './Dir1'
for subdir in "$topdir"; do
find "$subdir" -type f -printf "%fn"
done
bash shell-script awk perl
New contributor
Probably something likefor pathname in dir1/*/ ; do find "$pathname" -type f > "$pathname"_fname.txt; done
? Orfind dir1/ -type f -exec sh -c 'echo "$1" > "$(basename "$1" )"_fname.txt' sh {} ;
?
– Sergiy Kolodyazhnyy
14 mins ago
add a comment |
My data structure is something like:
dir1/subdir1_level1/subdir1_level2.../subdir1_leveln
dir1/subdir2_level1/subdir2_level2.../subdir2_leveln
...
Which means that the levels I'm working with are not structured properly, nevertheless.
I managed to accomplish my objective of getting the filename according to the first 2 levels of the path, and output them to a text file named dirn_subdirn_fname.txt with:
find dir1/subdir1 -type f -printf "%fn">dir1_subdir1_fname.txt
But I was wondering if there was a way to Iterate this process across a list of several dir/subdir's
edit: I found a way to do the first part:
#!/bin/bash
shopt -s dotglob nullglob
topdir= './Dir1'
for subdir in "$topdir"; do
find "$subdir" -type f -printf "%fn"
done
bash shell-script awk perl
New contributor
My data structure is something like:
dir1/subdir1_level1/subdir1_level2.../subdir1_leveln
dir1/subdir2_level1/subdir2_level2.../subdir2_leveln
...
Which means that the levels I'm working with are not structured properly, nevertheless.
I managed to accomplish my objective of getting the filename according to the first 2 levels of the path, and output them to a text file named dirn_subdirn_fname.txt with:
find dir1/subdir1 -type f -printf "%fn">dir1_subdir1_fname.txt
But I was wondering if there was a way to Iterate this process across a list of several dir/subdir's
edit: I found a way to do the first part:
#!/bin/bash
shopt -s dotglob nullglob
topdir= './Dir1'
for subdir in "$topdir"; do
find "$subdir" -type f -printf "%fn"
done
bash shell-script awk perl
bash shell-script awk perl
New contributor
New contributor
edited 13 mins ago
Faustino Delgado
New contributor
asked 50 mins ago
Faustino DelgadoFaustino Delgado
263
263
New contributor
New contributor
Probably something likefor pathname in dir1/*/ ; do find "$pathname" -type f > "$pathname"_fname.txt; done
? Orfind dir1/ -type f -exec sh -c 'echo "$1" > "$(basename "$1" )"_fname.txt' sh {} ;
?
– Sergiy Kolodyazhnyy
14 mins ago
add a comment |
Probably something likefor pathname in dir1/*/ ; do find "$pathname" -type f > "$pathname"_fname.txt; done
? Orfind dir1/ -type f -exec sh -c 'echo "$1" > "$(basename "$1" )"_fname.txt' sh {} ;
?
– Sergiy Kolodyazhnyy
14 mins ago
Probably something like
for pathname in dir1/*/ ; do find "$pathname" -type f > "$pathname"_fname.txt; done
? Or find dir1/ -type f -exec sh -c 'echo "$1" > "$(basename "$1" )"_fname.txt' sh {} ;
?– Sergiy Kolodyazhnyy
14 mins ago
Probably something like
for pathname in dir1/*/ ; do find "$pathname" -type f > "$pathname"_fname.txt; done
? Or find dir1/ -type f -exec sh -c 'echo "$1" > "$(basename "$1" )"_fname.txt' sh {} ;
?– Sergiy Kolodyazhnyy
14 mins ago
add a comment |
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Probably something like
for pathname in dir1/*/ ; do find "$pathname" -type f > "$pathname"_fname.txt; done
? Orfind dir1/ -type f -exec sh -c 'echo "$1" > "$(basename "$1" )"_fname.txt' sh {} ;
?– Sergiy Kolodyazhnyy
14 mins ago