delete lines matching pattern if it is repeated
0
Say I have a config file:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[extra]
[footer]
[tail]
print = true
[end]
I want to print the headers ([text]) only if there are options underneath. So the output should be:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[tail]
print = true
text-processing awk sed perl
asked 49 mins ago
DarkHeartDarkHeart
3,51432340
add a comment |
0
Say I have a config file:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[extra]
[footer]
[tail]
print = true
[end]
I want to print the headers ([text]) only if there are options underneath. So the output should be:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[tail]
print = true
text-processing awk sed perl
asked 49 mins ago
DarkHeartDarkHeart
3,51432340
Why must it be sed, rather than awk or perl?
– Ed Grimm
10 mins ago
@EdGrimm - It doesn't really. I just wanted some simple one-liner. I've removed sed from the question.
– DarkHeart
1 min ago
My attempt looks a bit crappysed 's/^[.*/nn&/' config.txt | perl -00 -nle 'print "$_" if split("n") > 1;'|grep -v '^$'
– DarkHeart
26 secs ago
add a comment |
0
0
0
Say I have a config file:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[extra]
[footer]
[tail]
print = true
[end]
I want to print the headers ([text]) only if there are options underneath. So the output should be:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[tail]
print = true
text-processing awk sed perl
asked 49 mins ago
DarkHeartDarkHeart
3,51432340
Say I have a config file:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[extra]
[footer]
[tail]
print = true
[end]
I want to print the headers ([text]) only if there are options underneath. So the output should be:
[main]
foo = bar
[option]
opt1 = opt2
opt3 = opt4
[tail]
print = true
text-processing awk sed perl
text-processing awk sed perl
asked 49 mins ago
DarkHeartDarkHeart
3,51432340
asked 49 mins ago
DarkHeartDarkHeart
3,51432340
edited 2 mins ago
DarkHeart
asked 49 mins ago
DarkHeartDarkHeart
3,51432340
asked 49 mins ago
DarkHeartDarkHeart
3,51432340
asked 49 mins ago
DarkHeartDarkHeart
3,51432340
3,51432340
Why must it be sed, rather than awk or perl?
– Ed Grimm
10 mins ago
@EdGrimm - It doesn't really. I just wanted some simple one-liner. I've removed sed from the question.
– DarkHeart
1 min ago
My attempt looks a bit crappysed 's/^[.*/nn&/' config.txt | perl -00 -nle 'print "$_" if split("n") > 1;'|grep -v '^$'
– DarkHeart
26 secs ago
add a comment |
Why must it be sed, rather than awk or perl?
– Ed Grimm
10 mins ago
@EdGrimm - It doesn't really. I just wanted some simple one-liner. I've removed sed from the question.
– DarkHeart
1 min ago
My attempt looks a bit crappysed 's/^[.*/nn&/' config.txt | perl -00 -nle 'print "$_" if split("n") > 1;'|grep -v '^$'
– DarkHeart
26 secs ago
Why must it be sed, rather than awk or perl?
– Ed Grimm
10 mins ago
Why must it be sed, rather than awk or perl?
– Ed Grimm
10 mins ago
@EdGrimm - It doesn't really. I just wanted some simple one-liner. I've removed sed from the question.
– DarkHeart
1 min ago
@EdGrimm - It doesn't really. I just wanted some simple one-liner. I've removed sed from the question.
– DarkHeart
1 min ago
My attempt looks a bit crappy
sed 's/^[.*/nn&/' config.txt | perl -00 -nle 'print "$_" if split("n") > 1;'|grep -v '^$'– DarkHeart
26 secs ago
My attempt looks a bit crappy
sed 's/^[.*/nn&/' config.txt | perl -00 -nle 'print "$_" if split("n") > 1;'|grep -v '^$'– DarkHeart
26 secs ago
add a comment |
0
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Why must it be sed, rather than awk or perl?
– Ed Grimm
10 mins ago
@EdGrimm - It doesn't really. I just wanted some simple one-liner. I've removed sed from the question.
– DarkHeart
1 min ago
My attempt looks a bit crappy
sed 's/^[.*/nn&/' config.txt | perl -00 -nle 'print "$_" if split("n") > 1;'|grep -v '^$'– DarkHeart
26 secs ago