bash + find specific word in space-delimited string












1















The parameter list include the following example values 



# echo $list

master01.montil131.com worker01.montil131.com worker02.montil131.com


In order to find the word that include master string I do the following



list=$( for i in ` echo  $list `; do [[ $i =~ master ]] && echo $i ; done )



echo $list

master01.montil131.com


but this approach to find the string with master word isn't elegant way



Any other suggestion how to find specific word in list ?






linux bash shell-script awk sed







share|improve this question

























  • is $list a variable that contains the string "master01.montil131.com worker01.montil131.com worker02.montil131.com" ? a space separated list of words stored in a variable?

    – glenn jackman
    7 hours ago











  • just one space between words ( no other comma separator )'

    – yael
    7 hours ago











  • Unrelated: Why do you store a list in a string? It would be better to have it in an array...

    – Kusalananda
    1 hour ago
















1















The parameter list include the following example values 



# echo $list

master01.montil131.com worker01.montil131.com worker02.montil131.com


In order to find the word that include master string I do the following



list=$( for i in ` echo  $list `; do [[ $i =~ master ]] && echo $i ; done )



echo $list

master01.montil131.com


but this approach to find the string with master word isn't elegant way



Any other suggestion how to find specific word in list ?






linux bash shell-script awk sed







share|improve this question

























  • is $list a variable that contains the string "master01.montil131.com worker01.montil131.com worker02.montil131.com" ? a space separated list of words stored in a variable?

    – glenn jackman
    7 hours ago











  • just one space between words ( no other comma separator )'

    – yael
    7 hours ago











  • Unrelated: Why do you store a list in a string? It would be better to have it in an array...

    – Kusalananda
    1 hour ago














1












1








1








The parameter list include the following example values 



# echo $list

master01.montil131.com worker01.montil131.com worker02.montil131.com


In order to find the word that include master string I do the following



list=$( for i in ` echo  $list `; do [[ $i =~ master ]] && echo $i ; done )



echo $list

master01.montil131.com


but this approach to find the string with master word isn't elegant way



Any other suggestion how to find specific word in list ?






linux bash shell-script awk sed







share|improve this question
















The parameter list include the following example values 



# echo $list

master01.montil131.com worker01.montil131.com worker02.montil131.com


In order to find the word that include master string I do the following



list=$( for i in ` echo  $list `; do [[ $i =~ master ]] && echo $i ; done )



echo $list

master01.montil131.com


but this approach to find the string with master word isn't elegant way



Any other suggestion how to find specific word in list ?






linux bash shell-script awk sed




linux bash shell-script awk sed






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 1 hour ago









Kusalananda

131k17249408




131k17249408










asked 7 hours ago









yaelyael

2,58712570




2,58712570













  • is $list a variable that contains the string "master01.montil131.com worker01.montil131.com worker02.montil131.com" ? a space separated list of words stored in a variable?

    – glenn jackman
    7 hours ago











  • just one space between words ( no other comma separator )'

    – yael
    7 hours ago











  • Unrelated: Why do you store a list in a string? It would be better to have it in an array...

    – Kusalananda
    1 hour ago



















  • is $list a variable that contains the string "master01.montil131.com worker01.montil131.com worker02.montil131.com" ? a space separated list of words stored in a variable?

    – glenn jackman
    7 hours ago











  • just one space between words ( no other comma separator )'

    – yael
    7 hours ago











  • Unrelated: Why do you store a list in a string? It would be better to have it in an array...

    – Kusalananda
    1 hour ago

















is $list a variable that contains the string "master01.montil131.com worker01.montil131.com worker02.montil131.com" ? a space separated list of words stored in a variable?

– glenn jackman
7 hours ago





is $list a variable that contains the string "master01.montil131.com worker01.montil131.com worker02.montil131.com" ? a space separated list of words stored in a variable?

– glenn jackman
7 hours ago













just one space between words ( no other comma separator )'

– yael
7 hours ago





just one space between words ( no other comma separator )'

– yael
7 hours ago













Unrelated: Why do you store a list in a string? It would be better to have it in an array...

– Kusalananda
1 hour ago





Unrelated: Why do you store a list in a string? It would be better to have it in an array...

– Kusalananda
1 hour ago










3 Answers
3






active

oldest

votes


















1














Why not use simple grep command, I am assuming there are no spaces in a word in the list.



 echo $list | tr ' ' 'n' | grep master


It will replace space with new line and will then grep word master.






share|improve this answer

































    2














    Use grep -o:



    grep -o "[^ ]*master[^ ]*" <<<"$list"


    If you know that you always have just master* and worker*, you can use Shell methods:



    echo "${list// *worker[^ ]*/}"





    share|improve this answer

































      0














      grep -ow 'master[^ ]*' <<<"$list"


      or, with GNU grep,



      grep -Pow 'masterS+' <<<"$list"


      The -o would extract the matching bit of the string in $list, and -w would ensure that we don't match themaster or some other word that does not start with master.



      The S in the second command is a PCRE that will match any non-space character.






      share|improve this answer























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        3 Answers
        3






        active

        oldest

        votes








        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        1














        Why not use simple grep command, I am assuming there are no spaces in a word in the list.



         echo $list | tr ' ' 'n' | grep master


        It will replace space with new line and will then grep word master.






        share|improve this answer






























          1














          Why not use simple grep command, I am assuming there are no spaces in a word in the list.



           echo $list | tr ' ' 'n' | grep master


          It will replace space with new line and will then grep word master.






          share|improve this answer




























            1












            1








            1







            Why not use simple grep command, I am assuming there are no spaces in a word in the list.



             echo $list | tr ' ' 'n' | grep master


            It will replace space with new line and will then grep word master.






            share|improve this answer















            Why not use simple grep command, I am assuming there are no spaces in a word in the list.



             echo $list | tr ' ' 'n' | grep master


            It will replace space with new line and will then grep word master.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 7 hours ago

























            answered 7 hours ago









            PRYPRY

            2,43031025




            2,43031025

























                2














                Use grep -o:



                grep -o "[^ ]*master[^ ]*" <<<"$list"


                If you know that you always have just master* and worker*, you can use Shell methods:



                echo "${list// *worker[^ ]*/}"





                share|improve this answer






























                  2














                  Use grep -o:



                  grep -o "[^ ]*master[^ ]*" <<<"$list"


                  If you know that you always have just master* and worker*, you can use Shell methods:



                  echo "${list// *worker[^ ]*/}"





                  share|improve this answer




























                    2












                    2








                    2







                    Use grep -o:



                    grep -o "[^ ]*master[^ ]*" <<<"$list"


                    If you know that you always have just master* and worker*, you can use Shell methods:



                    echo "${list// *worker[^ ]*/}"





                    share|improve this answer















                    Use grep -o:



                    grep -o "[^ ]*master[^ ]*" <<<"$list"


                    If you know that you always have just master* and worker*, you can use Shell methods:



                    echo "${list// *worker[^ ]*/}"






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 7 hours ago

























                    answered 7 hours ago









                    RoVoRoVo

                    3,161216




                    3,161216























                        0














                        grep -ow 'master[^ ]*' <<<"$list"


                        or, with GNU grep,



                        grep -Pow 'masterS+' <<<"$list"


                        The -o would extract the matching bit of the string in $list, and -w would ensure that we don't match themaster or some other word that does not start with master.



                        The S in the second command is a PCRE that will match any non-space character.






                        share|improve this answer




























                          0














                          grep -ow 'master[^ ]*' <<<"$list"


                          or, with GNU grep,



                          grep -Pow 'masterS+' <<<"$list"


                          The -o would extract the matching bit of the string in $list, and -w would ensure that we don't match themaster or some other word that does not start with master.



                          The S in the second command is a PCRE that will match any non-space character.






                          share|improve this answer


























                            0












                            0








                            0







                            grep -ow 'master[^ ]*' <<<"$list"


                            or, with GNU grep,



                            grep -Pow 'masterS+' <<<"$list"


                            The -o would extract the matching bit of the string in $list, and -w would ensure that we don't match themaster or some other word that does not start with master.



                            The S in the second command is a PCRE that will match any non-space character.






                            share|improve this answer













                            grep -ow 'master[^ ]*' <<<"$list"


                            or, with GNU grep,



                            grep -Pow 'masterS+' <<<"$list"


                            The -o would extract the matching bit of the string in $list, and -w would ensure that we don't match themaster or some other word that does not start with master.



                            The S in the second command is a PCRE that will match any non-space character.







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 49 mins ago









                            KusalanandaKusalananda

                            131k17249408




                            131k17249408






























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