awk: Add number of days to current date
By assigning the date to awk, I can get current date as following in yyyy-mm-dd:
awk -F, -v date="20$(date +%y-%m-%d)" '{print date}'
Output:
2019-02-17
Is there a way to add number of days to current date, let's say 7, so the output would be:
2019-02-24
Noting that using a method like below isn't providing the required output:
awk -F, -v date="20$(date +%y-%m-%d +7 days)" '{print date}'
text-processing awk
asked 4 mins ago
Eng7Eng7
8462822
add a comment |
By assigning the date to awk, I can get current date as following in yyyy-mm-dd:
awk -F, -v date="20$(date +%y-%m-%d)" '{print date}'
Output:
2019-02-17
Is there a way to add number of days to current date, let's say 7, so the output would be:
2019-02-24
Noting that using a method like below isn't providing the required output:
awk -F, -v date="20$(date +%y-%m-%d +7 days)" '{print date}'
text-processing awk
asked 4 mins ago
Eng7Eng7
8462822
add a comment |
By assigning the date to awk, I can get current date as following in yyyy-mm-dd:
awk -F, -v date="20$(date +%y-%m-%d)" '{print date}'
Output:
2019-02-17
Is there a way to add number of days to current date, let's say 7, so the output would be:
2019-02-24
Noting that using a method like below isn't providing the required output:
awk -F, -v date="20$(date +%y-%m-%d +7 days)" '{print date}'
text-processing awk
asked 4 mins ago
Eng7Eng7
8462822
By assigning the date to awk, I can get current date as following in yyyy-mm-dd:
awk -F, -v date="20$(date +%y-%m-%d)" '{print date}'
Output:
2019-02-17
Is there a way to add number of days to current date, let's say 7, so the output would be:
2019-02-24
Noting that using a method like below isn't providing the required output:
awk -F, -v date="20$(date +%y-%m-%d +7 days)" '{print date}'
text-processing awk
text-processing awk
asked 4 mins ago
Eng7Eng7
8462822
asked 4 mins ago
Eng7Eng7
8462822
asked 4 mins ago
Eng7Eng7
8462822
asked 4 mins ago
Eng7Eng7
8462822
asked 4 mins ago
Eng7Eng7
8462822
8462822
add a comment |
add a comment |
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