using awk with if and z option
when I want to check if a returned value is integer or not I use this in bash script:
if [ -z "$value" ]
then
echo 0
else
echo $value
fi
I was trying to use z
option in awk with if. for example i have this line:
PRIMARY SECONDARY CONNECTED 350 800
I tried using this:
/bin/awk '{if( -z $1){print "0"}else{print $1}}' script
no matter i replace $1
with $2
or $3
or $4
or $5
it always return 0
. am I using awk in a wrong way?
bash shell-script awk
add a comment |
when I want to check if a returned value is integer or not I use this in bash script:
if [ -z "$value" ]
then
echo 0
else
echo $value
fi
I was trying to use z
option in awk with if. for example i have this line:
PRIMARY SECONDARY CONNECTED 350 800
I tried using this:
/bin/awk '{if( -z $1){print "0"}else{print $1}}' script
no matter i replace $1
with $2
or $3
or $4
or $5
it always return 0
. am I using awk in a wrong way?
bash shell-script awk
add a comment |
when I want to check if a returned value is integer or not I use this in bash script:
if [ -z "$value" ]
then
echo 0
else
echo $value
fi
I was trying to use z
option in awk with if. for example i have this line:
PRIMARY SECONDARY CONNECTED 350 800
I tried using this:
/bin/awk '{if( -z $1){print "0"}else{print $1}}' script
no matter i replace $1
with $2
or $3
or $4
or $5
it always return 0
. am I using awk in a wrong way?
bash shell-script awk
when I want to check if a returned value is integer or not I use this in bash script:
if [ -z "$value" ]
then
echo 0
else
echo $value
fi
I was trying to use z
option in awk with if. for example i have this line:
PRIMARY SECONDARY CONNECTED 350 800
I tried using this:
/bin/awk '{if( -z $1){print "0"}else{print $1}}' script
no matter i replace $1
with $2
or $3
or $4
or $5
it always return 0
. am I using awk in a wrong way?
bash shell-script awk
bash shell-script awk
asked 1 min ago
BlackCrystalBlackCrystal
32311
32311
add a comment |
add a comment |
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