ksh variable substitution format?
I have variables named var1EMI, var2EMI, var1DDE, var2DDE, etc
and I need to be able to iterate over them like this;
for dir in var1 var2
do
echo "EMI value for " $dir " is " ${${dir}EMI}
echo "DDE value for " $dir " is " ${${dir}DDE}
done
I can't figure out how to get the ${${dir}EMI} substitutions to resolve.
ksh
edited Nov 4 '13 at 21:55
Joseph R.
28.1k374114
asked Nov 4 '13 at 21:48
user88710user88710
264
add a comment |
I have variables named var1EMI, var2EMI, var1DDE, var2DDE, etc
and I need to be able to iterate over them like this;
for dir in var1 var2
do
echo "EMI value for " $dir " is " ${${dir}EMI}
echo "DDE value for " $dir " is " ${${dir}DDE}
done
I can't figure out how to get the ${${dir}EMI} substitutions to resolve.
ksh
edited Nov 4 '13 at 21:55
Joseph R.
28.1k374114
asked Nov 4 '13 at 21:48
user88710user88710
264
what version of ksh?
– glenn jackman
Nov 4 '13 at 22:20
version is ksh88
– user88710
Nov 5 '13 at 19:04
add a comment |
I have variables named var1EMI, var2EMI, var1DDE, var2DDE, etc
and I need to be able to iterate over them like this;
for dir in var1 var2
do
echo "EMI value for " $dir " is " ${${dir}EMI}
echo "DDE value for " $dir " is " ${${dir}DDE}
done
I can't figure out how to get the ${${dir}EMI} substitutions to resolve.
ksh
edited Nov 4 '13 at 21:55
Joseph R.
28.1k374114
asked Nov 4 '13 at 21:48
user88710user88710
264
I have variables named var1EMI, var2EMI, var1DDE, var2DDE, etc
and I need to be able to iterate over them like this;
for dir in var1 var2
do
echo "EMI value for " $dir " is " ${${dir}EMI}
echo "DDE value for " $dir " is " ${${dir}DDE}
done
I can't figure out how to get the ${${dir}EMI} substitutions to resolve.
ksh
ksh
edited Nov 4 '13 at 21:55
Joseph R.
28.1k374114
asked Nov 4 '13 at 21:48
user88710user88710
264
edited Nov 4 '13 at 21:55
Joseph R.
28.1k374114
asked Nov 4 '13 at 21:48
user88710user88710
264
edited Nov 4 '13 at 21:55
Joseph R.
28.1k374114
edited Nov 4 '13 at 21:55
Joseph R.
28.1k374114
edited Nov 4 '13 at 21:55
Joseph R.
28.1k374114
28.1k374114
asked Nov 4 '13 at 21:48
user88710user88710
264
asked Nov 4 '13 at 21:48
user88710user88710
264
asked Nov 4 '13 at 21:48
user88710user88710
264
264
what version of ksh?
– glenn jackman
Nov 4 '13 at 22:20
version is ksh88
– user88710
Nov 5 '13 at 19:04
add a comment |
what version of ksh?
– glenn jackman
Nov 4 '13 at 22:20
version is ksh88
– user88710
Nov 5 '13 at 19:04
what version of ksh?
– glenn jackman
Nov 4 '13 at 22:20
what version of ksh?
– glenn jackman
Nov 4 '13 at 22:20
version is ksh88
– user88710
Nov 5 '13 at 19:04
version is ksh88
– user88710
Nov 5 '13 at 19:04
add a comment |
1 Answer
1
active
oldest
votes
ksh 93 has a nameref command that lets you create "aliases" to variables:
var1EMI=a
var2EMI=b
for v in var1 var2; do
nameref var=${v}EMI
echo "${v}EMI is $var"
done
var1EMI is a
var2EMI is b
For ksh88, you may be forced to use eval; replace:
nameref var=${v}EMI
with:
eval var=$${v}EMI
edited 13 hours ago
Jeff Schaller
39.5k1054126
answered Nov 4 '13 at 22:23
glenn jackmanglenn jackman
51k571110
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
ksh 93 has a nameref command that lets you create "aliases" to variables:
var1EMI=a
var2EMI=b
for v in var1 var2; do
nameref var=${v}EMI
echo "${v}EMI is $var"
done
var1EMI is a
var2EMI is b
For ksh88, you may be forced to use eval; replace:
nameref var=${v}EMI
with:
eval var=$${v}EMI
edited 13 hours ago
Jeff Schaller
39.5k1054126
answered Nov 4 '13 at 22:23
glenn jackmanglenn jackman
51k571110
add a comment |
ksh 93 has a nameref command that lets you create "aliases" to variables:
var1EMI=a
var2EMI=b
for v in var1 var2; do
nameref var=${v}EMI
echo "${v}EMI is $var"
done
var1EMI is a
var2EMI is b
For ksh88, you may be forced to use eval; replace:
nameref var=${v}EMI
with:
eval var=$${v}EMI
edited 13 hours ago
Jeff Schaller
39.5k1054126
answered Nov 4 '13 at 22:23
glenn jackmanglenn jackman
51k571110
add a comment |
ksh 93 has a nameref command that lets you create "aliases" to variables:
var1EMI=a
var2EMI=b
for v in var1 var2; do
nameref var=${v}EMI
echo "${v}EMI is $var"
done
var1EMI is a
var2EMI is b
For ksh88, you may be forced to use eval; replace:
nameref var=${v}EMI
with:
eval var=$${v}EMI
edited 13 hours ago
Jeff Schaller
39.5k1054126
answered Nov 4 '13 at 22:23
glenn jackmanglenn jackman
51k571110
ksh 93 has a nameref command that lets you create "aliases" to variables:
var1EMI=a
var2EMI=b
for v in var1 var2; do
nameref var=${v}EMI
echo "${v}EMI is $var"
done
var1EMI is a
var2EMI is b
For ksh88, you may be forced to use eval; replace:
nameref var=${v}EMI
with:
eval var=$${v}EMI
edited 13 hours ago
Jeff Schaller
39.5k1054126
answered Nov 4 '13 at 22:23
glenn jackmanglenn jackman
51k571110
edited 13 hours ago
Jeff Schaller
39.5k1054126
edited 13 hours ago
Jeff Schaller
39.5k1054126
edited 13 hours ago
Jeff Schaller
39.5k1054126
39.5k1054126
answered Nov 4 '13 at 22:23
glenn jackmanglenn jackman
51k571110
answered Nov 4 '13 at 22:23
glenn jackmanglenn jackman
51k571110
answered Nov 4 '13 at 22:23
glenn jackmanglenn jackman
51k571110
51k571110
add a comment |
add a comment |
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what version of ksh?
– glenn jackman
Nov 4 '13 at 22:20
version is ksh88
– user88710
Nov 5 '13 at 19:04