Are quotes needed for local variable assignment?
Can I safely omit quotes on the right side of a local assignment?
function foo {
local myvar=${bar}
stuff()
}
I'm mainly interested in bash
, but any info on corner cases in other shells are welcome.
shell-script quoting assignment
add a comment |
Can I safely omit quotes on the right side of a local assignment?
function foo {
local myvar=${bar}
stuff()
}
I'm mainly interested in bash
, but any info on corner cases in other shells are welcome.
shell-script quoting assignment
I think it makes no difference if it is on one line like you have it in your function. Assignments do not need quoting. See mpi-sb.mpg.de/departments/rg1/teaching/unixffb-ss98/…
– jirib
Oct 25 '13 at 13:48
add a comment |
Can I safely omit quotes on the right side of a local assignment?
function foo {
local myvar=${bar}
stuff()
}
I'm mainly interested in bash
, but any info on corner cases in other shells are welcome.
shell-script quoting assignment
Can I safely omit quotes on the right side of a local assignment?
function foo {
local myvar=${bar}
stuff()
}
I'm mainly interested in bash
, but any info on corner cases in other shells are welcome.
shell-script quoting assignment
shell-script quoting assignment
edited Apr 21 '17 at 23:08
Mateusz Piotrowski
1,96421542
1,96421542
asked Oct 25 '13 at 13:17
rahmurahmu
10.4k1970112
10.4k1970112
I think it makes no difference if it is on one line like you have it in your function. Assignments do not need quoting. See mpi-sb.mpg.de/departments/rg1/teaching/unixffb-ss98/…
– jirib
Oct 25 '13 at 13:48
add a comment |
I think it makes no difference if it is on one line like you have it in your function. Assignments do not need quoting. See mpi-sb.mpg.de/departments/rg1/teaching/unixffb-ss98/…
– jirib
Oct 25 '13 at 13:48
I think it makes no difference if it is on one line like you have it in your function. Assignments do not need quoting. See mpi-sb.mpg.de/departments/rg1/teaching/unixffb-ss98/…
– jirib
Oct 25 '13 at 13:48
I think it makes no difference if it is on one line like you have it in your function. Assignments do not need quoting. See mpi-sb.mpg.de/departments/rg1/teaching/unixffb-ss98/…
– jirib
Oct 25 '13 at 13:48
add a comment |
2 Answers
2
active
oldest
votes
Quotes are needed in export foo="$var"
or local foo="$var"
(or readonly
, typeset
, declare
and other variable declaring commands) in:
dash
- the
sh
of NetBSD (also based on the Almquist shell). - The
sh
of FreeBSD 9.2 or older (see the change in 9.3) yash
zsh
with versions prior to 5.1 inksh
orsh
emulation (or forexport var="$(cmd)"
wherezsh
would perform word splitting otherwise (not globbing)).
As otherwise the variable expansion would be subject to word splitting and/or filename generation like in any argument to any other command.
And are not needed in bash
or ksh
or the sh
of FreeBSD 9.3 or newer (where the command is somehow parsed like some sort of assignment) nor zsh
(where word splitting and filename generation is not done implicitly upon variable expansion).
They are needed in every shell (except zsh
) though in things like:
a="b=some value"
export "$a"
Or more generally, if anything left of the =
(including the =
) is quoted or the result of some expansion (like export 'foo'="$var"
, export foo="$var"
or export foo$((n+=1))="$var"
(that $((...))
should also be quoted actually)...). Or in other words when the argument to export
wouldn't be a valid variable assignment if written without the export
.
If the export
/local
command name itself is quoted (even in part like "export" a="$b"
, 'ex'port a="$b"
, export a="$b"
, or even ""export a="$b"
), the quotes around $b
are needed except in AT&T ksh and mksh
.
If export
/local
or some part of it is the result of some expansion (like in cmd=export; "$cmd" a="$b"
or even export$(:) a="$b"
) or if export
/local
is not the first word on the command line (as in dryrun=; $dryrun export a="$b"
), then the quotes are needed in every shell. In the case of > /dev/null export a="$b"
however, the quotes are not needed in bash
/AT&T ksh
and zsh
(they are in pdksh
and some of its derivatives).
For command export a="$b"
, the quotes are needed in every shell but mksh
and ksh93
(with the same caveats about command
and export
not being the result of some expansion).
They are not needed in any shell when written:
foo=$var export foo
(that syntax being also compatible with the Bourne shell but in the case of bash and zsh only working when in sh emulation).
(note that var=value local var
shouldn't be used as the behaviour varies across shells).
Also beware of this special case with bash
:
$ bash -c 'IFS=; export a="$*"; echo "$a"' bash a b
ab
$ bash -c 'IFS=; export a=$*; echo "$a"' bash a b
a b
My advise would be to always quote.
3
Note that inzsh
quotes are needed forlocal foo="$(cmd)"
because wordsplitting (but not filename generation) is performed for unquoted command substitutions (but not for unquoted parameter expansions), unlessKSH_TYPESET
is enabled, in which case quotes aren't needed. Make sense? No? Then always quote everything unless you know exactly what you're doing.
– Matt
Oct 25 '13 at 17:39
2
@Matt, I love your conclusion. :D It's funny, most of what I've learned of shell scripting came from this stackexchange, so that I didn't realize that always quote your variables is not common knowledge amongst script writers. I'm finding I have a lot of fixing up to do of existing production scripts written by people who didn't quote, and didn't know exactly what they were doing....
– Wildcard
Jan 6 '16 at 4:09
add a comment |
I generally quote any usage of variables where there might be characters such as white spaces. Otherwise you'll run into problems like this:
#!/bin/bash
bar="hi bye"
function foo {
local myvar=${bar}
printf "%sn" $myvar
printf "%sn" "$myvar"
}
foo
The usage of the variable in an assignment doesn't appear to need the quotes, but when you go to use it such as in the printf
you'll need it quoted there:
printf "%sn" "$myvar"
NOTE: Remember that the variable $IFS
is what governs what the separator characters are.
IFS The Internal Field Separator that is used for word splitting after
expansion and to split lines into words with the read builtin command.
The default value is ``<space><tab><newline>''.
Example
With debugging enabled in Bash we can see what's happening behind the scenes.
$ bash -x cmd.bash
+ bar='hi bye'
+ foo
+ local 'myvar=hi bye'
+ printf '%sn' hi bye
hi
bye
+ printf '%sn' 'hi bye'
hi bye
In the above we can see that the variable, $bar
was handed off fine to $myvar
but then when we went to use $myvar
we had to be cognoscente of the contents of $myvar
when we went to use it.
2
word splitting is not the only problem with unquoted variables, you have to consider filename generation (aka globbing) as well (though that (both) doesn't apply in variable assignments and forbash
andksh
inlocal
/typeset
... special builtins).
– Stéphane Chazelas
Oct 25 '13 at 13:58
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "106"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f97560%2fare-quotes-needed-for-local-variable-assignment%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Quotes are needed in export foo="$var"
or local foo="$var"
(or readonly
, typeset
, declare
and other variable declaring commands) in:
dash
- the
sh
of NetBSD (also based on the Almquist shell). - The
sh
of FreeBSD 9.2 or older (see the change in 9.3) yash
zsh
with versions prior to 5.1 inksh
orsh
emulation (or forexport var="$(cmd)"
wherezsh
would perform word splitting otherwise (not globbing)).
As otherwise the variable expansion would be subject to word splitting and/or filename generation like in any argument to any other command.
And are not needed in bash
or ksh
or the sh
of FreeBSD 9.3 or newer (where the command is somehow parsed like some sort of assignment) nor zsh
(where word splitting and filename generation is not done implicitly upon variable expansion).
They are needed in every shell (except zsh
) though in things like:
a="b=some value"
export "$a"
Or more generally, if anything left of the =
(including the =
) is quoted or the result of some expansion (like export 'foo'="$var"
, export foo="$var"
or export foo$((n+=1))="$var"
(that $((...))
should also be quoted actually)...). Or in other words when the argument to export
wouldn't be a valid variable assignment if written without the export
.
If the export
/local
command name itself is quoted (even in part like "export" a="$b"
, 'ex'port a="$b"
, export a="$b"
, or even ""export a="$b"
), the quotes around $b
are needed except in AT&T ksh and mksh
.
If export
/local
or some part of it is the result of some expansion (like in cmd=export; "$cmd" a="$b"
or even export$(:) a="$b"
) or if export
/local
is not the first word on the command line (as in dryrun=; $dryrun export a="$b"
), then the quotes are needed in every shell. In the case of > /dev/null export a="$b"
however, the quotes are not needed in bash
/AT&T ksh
and zsh
(they are in pdksh
and some of its derivatives).
For command export a="$b"
, the quotes are needed in every shell but mksh
and ksh93
(with the same caveats about command
and export
not being the result of some expansion).
They are not needed in any shell when written:
foo=$var export foo
(that syntax being also compatible with the Bourne shell but in the case of bash and zsh only working when in sh emulation).
(note that var=value local var
shouldn't be used as the behaviour varies across shells).
Also beware of this special case with bash
:
$ bash -c 'IFS=; export a="$*"; echo "$a"' bash a b
ab
$ bash -c 'IFS=; export a=$*; echo "$a"' bash a b
a b
My advise would be to always quote.
3
Note that inzsh
quotes are needed forlocal foo="$(cmd)"
because wordsplitting (but not filename generation) is performed for unquoted command substitutions (but not for unquoted parameter expansions), unlessKSH_TYPESET
is enabled, in which case quotes aren't needed. Make sense? No? Then always quote everything unless you know exactly what you're doing.
– Matt
Oct 25 '13 at 17:39
2
@Matt, I love your conclusion. :D It's funny, most of what I've learned of shell scripting came from this stackexchange, so that I didn't realize that always quote your variables is not common knowledge amongst script writers. I'm finding I have a lot of fixing up to do of existing production scripts written by people who didn't quote, and didn't know exactly what they were doing....
– Wildcard
Jan 6 '16 at 4:09
add a comment |
Quotes are needed in export foo="$var"
or local foo="$var"
(or readonly
, typeset
, declare
and other variable declaring commands) in:
dash
- the
sh
of NetBSD (also based on the Almquist shell). - The
sh
of FreeBSD 9.2 or older (see the change in 9.3) yash
zsh
with versions prior to 5.1 inksh
orsh
emulation (or forexport var="$(cmd)"
wherezsh
would perform word splitting otherwise (not globbing)).
As otherwise the variable expansion would be subject to word splitting and/or filename generation like in any argument to any other command.
And are not needed in bash
or ksh
or the sh
of FreeBSD 9.3 or newer (where the command is somehow parsed like some sort of assignment) nor zsh
(where word splitting and filename generation is not done implicitly upon variable expansion).
They are needed in every shell (except zsh
) though in things like:
a="b=some value"
export "$a"
Or more generally, if anything left of the =
(including the =
) is quoted or the result of some expansion (like export 'foo'="$var"
, export foo="$var"
or export foo$((n+=1))="$var"
(that $((...))
should also be quoted actually)...). Or in other words when the argument to export
wouldn't be a valid variable assignment if written without the export
.
If the export
/local
command name itself is quoted (even in part like "export" a="$b"
, 'ex'port a="$b"
, export a="$b"
, or even ""export a="$b"
), the quotes around $b
are needed except in AT&T ksh and mksh
.
If export
/local
or some part of it is the result of some expansion (like in cmd=export; "$cmd" a="$b"
or even export$(:) a="$b"
) or if export
/local
is not the first word on the command line (as in dryrun=; $dryrun export a="$b"
), then the quotes are needed in every shell. In the case of > /dev/null export a="$b"
however, the quotes are not needed in bash
/AT&T ksh
and zsh
(they are in pdksh
and some of its derivatives).
For command export a="$b"
, the quotes are needed in every shell but mksh
and ksh93
(with the same caveats about command
and export
not being the result of some expansion).
They are not needed in any shell when written:
foo=$var export foo
(that syntax being also compatible with the Bourne shell but in the case of bash and zsh only working when in sh emulation).
(note that var=value local var
shouldn't be used as the behaviour varies across shells).
Also beware of this special case with bash
:
$ bash -c 'IFS=; export a="$*"; echo "$a"' bash a b
ab
$ bash -c 'IFS=; export a=$*; echo "$a"' bash a b
a b
My advise would be to always quote.
3
Note that inzsh
quotes are needed forlocal foo="$(cmd)"
because wordsplitting (but not filename generation) is performed for unquoted command substitutions (but not for unquoted parameter expansions), unlessKSH_TYPESET
is enabled, in which case quotes aren't needed. Make sense? No? Then always quote everything unless you know exactly what you're doing.
– Matt
Oct 25 '13 at 17:39
2
@Matt, I love your conclusion. :D It's funny, most of what I've learned of shell scripting came from this stackexchange, so that I didn't realize that always quote your variables is not common knowledge amongst script writers. I'm finding I have a lot of fixing up to do of existing production scripts written by people who didn't quote, and didn't know exactly what they were doing....
– Wildcard
Jan 6 '16 at 4:09
add a comment |
Quotes are needed in export foo="$var"
or local foo="$var"
(or readonly
, typeset
, declare
and other variable declaring commands) in:
dash
- the
sh
of NetBSD (also based on the Almquist shell). - The
sh
of FreeBSD 9.2 or older (see the change in 9.3) yash
zsh
with versions prior to 5.1 inksh
orsh
emulation (or forexport var="$(cmd)"
wherezsh
would perform word splitting otherwise (not globbing)).
As otherwise the variable expansion would be subject to word splitting and/or filename generation like in any argument to any other command.
And are not needed in bash
or ksh
or the sh
of FreeBSD 9.3 or newer (where the command is somehow parsed like some sort of assignment) nor zsh
(where word splitting and filename generation is not done implicitly upon variable expansion).
They are needed in every shell (except zsh
) though in things like:
a="b=some value"
export "$a"
Or more generally, if anything left of the =
(including the =
) is quoted or the result of some expansion (like export 'foo'="$var"
, export foo="$var"
or export foo$((n+=1))="$var"
(that $((...))
should also be quoted actually)...). Or in other words when the argument to export
wouldn't be a valid variable assignment if written without the export
.
If the export
/local
command name itself is quoted (even in part like "export" a="$b"
, 'ex'port a="$b"
, export a="$b"
, or even ""export a="$b"
), the quotes around $b
are needed except in AT&T ksh and mksh
.
If export
/local
or some part of it is the result of some expansion (like in cmd=export; "$cmd" a="$b"
or even export$(:) a="$b"
) or if export
/local
is not the first word on the command line (as in dryrun=; $dryrun export a="$b"
), then the quotes are needed in every shell. In the case of > /dev/null export a="$b"
however, the quotes are not needed in bash
/AT&T ksh
and zsh
(they are in pdksh
and some of its derivatives).
For command export a="$b"
, the quotes are needed in every shell but mksh
and ksh93
(with the same caveats about command
and export
not being the result of some expansion).
They are not needed in any shell when written:
foo=$var export foo
(that syntax being also compatible with the Bourne shell but in the case of bash and zsh only working when in sh emulation).
(note that var=value local var
shouldn't be used as the behaviour varies across shells).
Also beware of this special case with bash
:
$ bash -c 'IFS=; export a="$*"; echo "$a"' bash a b
ab
$ bash -c 'IFS=; export a=$*; echo "$a"' bash a b
a b
My advise would be to always quote.
Quotes are needed in export foo="$var"
or local foo="$var"
(or readonly
, typeset
, declare
and other variable declaring commands) in:
dash
- the
sh
of NetBSD (also based on the Almquist shell). - The
sh
of FreeBSD 9.2 or older (see the change in 9.3) yash
zsh
with versions prior to 5.1 inksh
orsh
emulation (or forexport var="$(cmd)"
wherezsh
would perform word splitting otherwise (not globbing)).
As otherwise the variable expansion would be subject to word splitting and/or filename generation like in any argument to any other command.
And are not needed in bash
or ksh
or the sh
of FreeBSD 9.3 or newer (where the command is somehow parsed like some sort of assignment) nor zsh
(where word splitting and filename generation is not done implicitly upon variable expansion).
They are needed in every shell (except zsh
) though in things like:
a="b=some value"
export "$a"
Or more generally, if anything left of the =
(including the =
) is quoted or the result of some expansion (like export 'foo'="$var"
, export foo="$var"
or export foo$((n+=1))="$var"
(that $((...))
should also be quoted actually)...). Or in other words when the argument to export
wouldn't be a valid variable assignment if written without the export
.
If the export
/local
command name itself is quoted (even in part like "export" a="$b"
, 'ex'port a="$b"
, export a="$b"
, or even ""export a="$b"
), the quotes around $b
are needed except in AT&T ksh and mksh
.
If export
/local
or some part of it is the result of some expansion (like in cmd=export; "$cmd" a="$b"
or even export$(:) a="$b"
) or if export
/local
is not the first word on the command line (as in dryrun=; $dryrun export a="$b"
), then the quotes are needed in every shell. In the case of > /dev/null export a="$b"
however, the quotes are not needed in bash
/AT&T ksh
and zsh
(they are in pdksh
and some of its derivatives).
For command export a="$b"
, the quotes are needed in every shell but mksh
and ksh93
(with the same caveats about command
and export
not being the result of some expansion).
They are not needed in any shell when written:
foo=$var export foo
(that syntax being also compatible with the Bourne shell but in the case of bash and zsh only working when in sh emulation).
(note that var=value local var
shouldn't be used as the behaviour varies across shells).
Also beware of this special case with bash
:
$ bash -c 'IFS=; export a="$*"; echo "$a"' bash a b
ab
$ bash -c 'IFS=; export a=$*; echo "$a"' bash a b
a b
My advise would be to always quote.
edited 11 mins ago
answered Oct 25 '13 at 13:46
Stéphane ChazelasStéphane Chazelas
305k57577931
305k57577931
3
Note that inzsh
quotes are needed forlocal foo="$(cmd)"
because wordsplitting (but not filename generation) is performed for unquoted command substitutions (but not for unquoted parameter expansions), unlessKSH_TYPESET
is enabled, in which case quotes aren't needed. Make sense? No? Then always quote everything unless you know exactly what you're doing.
– Matt
Oct 25 '13 at 17:39
2
@Matt, I love your conclusion. :D It's funny, most of what I've learned of shell scripting came from this stackexchange, so that I didn't realize that always quote your variables is not common knowledge amongst script writers. I'm finding I have a lot of fixing up to do of existing production scripts written by people who didn't quote, and didn't know exactly what they were doing....
– Wildcard
Jan 6 '16 at 4:09
add a comment |
3
Note that inzsh
quotes are needed forlocal foo="$(cmd)"
because wordsplitting (but not filename generation) is performed for unquoted command substitutions (but not for unquoted parameter expansions), unlessKSH_TYPESET
is enabled, in which case quotes aren't needed. Make sense? No? Then always quote everything unless you know exactly what you're doing.
– Matt
Oct 25 '13 at 17:39
2
@Matt, I love your conclusion. :D It's funny, most of what I've learned of shell scripting came from this stackexchange, so that I didn't realize that always quote your variables is not common knowledge amongst script writers. I'm finding I have a lot of fixing up to do of existing production scripts written by people who didn't quote, and didn't know exactly what they were doing....
– Wildcard
Jan 6 '16 at 4:09
3
3
Note that in
zsh
quotes are needed for local foo="$(cmd)"
because wordsplitting (but not filename generation) is performed for unquoted command substitutions (but not for unquoted parameter expansions), unless KSH_TYPESET
is enabled, in which case quotes aren't needed. Make sense? No? Then always quote everything unless you know exactly what you're doing.– Matt
Oct 25 '13 at 17:39
Note that in
zsh
quotes are needed for local foo="$(cmd)"
because wordsplitting (but not filename generation) is performed for unquoted command substitutions (but not for unquoted parameter expansions), unless KSH_TYPESET
is enabled, in which case quotes aren't needed. Make sense? No? Then always quote everything unless you know exactly what you're doing.– Matt
Oct 25 '13 at 17:39
2
2
@Matt, I love your conclusion. :D It's funny, most of what I've learned of shell scripting came from this stackexchange, so that I didn't realize that always quote your variables is not common knowledge amongst script writers. I'm finding I have a lot of fixing up to do of existing production scripts written by people who didn't quote, and didn't know exactly what they were doing....
– Wildcard
Jan 6 '16 at 4:09
@Matt, I love your conclusion. :D It's funny, most of what I've learned of shell scripting came from this stackexchange, so that I didn't realize that always quote your variables is not common knowledge amongst script writers. I'm finding I have a lot of fixing up to do of existing production scripts written by people who didn't quote, and didn't know exactly what they were doing....
– Wildcard
Jan 6 '16 at 4:09
add a comment |
I generally quote any usage of variables where there might be characters such as white spaces. Otherwise you'll run into problems like this:
#!/bin/bash
bar="hi bye"
function foo {
local myvar=${bar}
printf "%sn" $myvar
printf "%sn" "$myvar"
}
foo
The usage of the variable in an assignment doesn't appear to need the quotes, but when you go to use it such as in the printf
you'll need it quoted there:
printf "%sn" "$myvar"
NOTE: Remember that the variable $IFS
is what governs what the separator characters are.
IFS The Internal Field Separator that is used for word splitting after
expansion and to split lines into words with the read builtin command.
The default value is ``<space><tab><newline>''.
Example
With debugging enabled in Bash we can see what's happening behind the scenes.
$ bash -x cmd.bash
+ bar='hi bye'
+ foo
+ local 'myvar=hi bye'
+ printf '%sn' hi bye
hi
bye
+ printf '%sn' 'hi bye'
hi bye
In the above we can see that the variable, $bar
was handed off fine to $myvar
but then when we went to use $myvar
we had to be cognoscente of the contents of $myvar
when we went to use it.
2
word splitting is not the only problem with unquoted variables, you have to consider filename generation (aka globbing) as well (though that (both) doesn't apply in variable assignments and forbash
andksh
inlocal
/typeset
... special builtins).
– Stéphane Chazelas
Oct 25 '13 at 13:58
add a comment |
I generally quote any usage of variables where there might be characters such as white spaces. Otherwise you'll run into problems like this:
#!/bin/bash
bar="hi bye"
function foo {
local myvar=${bar}
printf "%sn" $myvar
printf "%sn" "$myvar"
}
foo
The usage of the variable in an assignment doesn't appear to need the quotes, but when you go to use it such as in the printf
you'll need it quoted there:
printf "%sn" "$myvar"
NOTE: Remember that the variable $IFS
is what governs what the separator characters are.
IFS The Internal Field Separator that is used for word splitting after
expansion and to split lines into words with the read builtin command.
The default value is ``<space><tab><newline>''.
Example
With debugging enabled in Bash we can see what's happening behind the scenes.
$ bash -x cmd.bash
+ bar='hi bye'
+ foo
+ local 'myvar=hi bye'
+ printf '%sn' hi bye
hi
bye
+ printf '%sn' 'hi bye'
hi bye
In the above we can see that the variable, $bar
was handed off fine to $myvar
but then when we went to use $myvar
we had to be cognoscente of the contents of $myvar
when we went to use it.
2
word splitting is not the only problem with unquoted variables, you have to consider filename generation (aka globbing) as well (though that (both) doesn't apply in variable assignments and forbash
andksh
inlocal
/typeset
... special builtins).
– Stéphane Chazelas
Oct 25 '13 at 13:58
add a comment |
I generally quote any usage of variables where there might be characters such as white spaces. Otherwise you'll run into problems like this:
#!/bin/bash
bar="hi bye"
function foo {
local myvar=${bar}
printf "%sn" $myvar
printf "%sn" "$myvar"
}
foo
The usage of the variable in an assignment doesn't appear to need the quotes, but when you go to use it such as in the printf
you'll need it quoted there:
printf "%sn" "$myvar"
NOTE: Remember that the variable $IFS
is what governs what the separator characters are.
IFS The Internal Field Separator that is used for word splitting after
expansion and to split lines into words with the read builtin command.
The default value is ``<space><tab><newline>''.
Example
With debugging enabled in Bash we can see what's happening behind the scenes.
$ bash -x cmd.bash
+ bar='hi bye'
+ foo
+ local 'myvar=hi bye'
+ printf '%sn' hi bye
hi
bye
+ printf '%sn' 'hi bye'
hi bye
In the above we can see that the variable, $bar
was handed off fine to $myvar
but then when we went to use $myvar
we had to be cognoscente of the contents of $myvar
when we went to use it.
I generally quote any usage of variables where there might be characters such as white spaces. Otherwise you'll run into problems like this:
#!/bin/bash
bar="hi bye"
function foo {
local myvar=${bar}
printf "%sn" $myvar
printf "%sn" "$myvar"
}
foo
The usage of the variable in an assignment doesn't appear to need the quotes, but when you go to use it such as in the printf
you'll need it quoted there:
printf "%sn" "$myvar"
NOTE: Remember that the variable $IFS
is what governs what the separator characters are.
IFS The Internal Field Separator that is used for word splitting after
expansion and to split lines into words with the read builtin command.
The default value is ``<space><tab><newline>''.
Example
With debugging enabled in Bash we can see what's happening behind the scenes.
$ bash -x cmd.bash
+ bar='hi bye'
+ foo
+ local 'myvar=hi bye'
+ printf '%sn' hi bye
hi
bye
+ printf '%sn' 'hi bye'
hi bye
In the above we can see that the variable, $bar
was handed off fine to $myvar
but then when we went to use $myvar
we had to be cognoscente of the contents of $myvar
when we went to use it.
answered Oct 25 '13 at 13:26
slm♦slm
251k69529685
251k69529685
2
word splitting is not the only problem with unquoted variables, you have to consider filename generation (aka globbing) as well (though that (both) doesn't apply in variable assignments and forbash
andksh
inlocal
/typeset
... special builtins).
– Stéphane Chazelas
Oct 25 '13 at 13:58
add a comment |
2
word splitting is not the only problem with unquoted variables, you have to consider filename generation (aka globbing) as well (though that (both) doesn't apply in variable assignments and forbash
andksh
inlocal
/typeset
... special builtins).
– Stéphane Chazelas
Oct 25 '13 at 13:58
2
2
word splitting is not the only problem with unquoted variables, you have to consider filename generation (aka globbing) as well (though that (both) doesn't apply in variable assignments and for
bash
and ksh
in local
/typeset
... special builtins).– Stéphane Chazelas
Oct 25 '13 at 13:58
word splitting is not the only problem with unquoted variables, you have to consider filename generation (aka globbing) as well (though that (both) doesn't apply in variable assignments and for
bash
and ksh
in local
/typeset
... special builtins).– Stéphane Chazelas
Oct 25 '13 at 13:58
add a comment |
Thanks for contributing an answer to Unix & Linux Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f97560%2fare-quotes-needed-for-local-variable-assignment%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
I think it makes no difference if it is on one line like you have it in your function. Assignments do not need quoting. See mpi-sb.mpg.de/departments/rg1/teaching/unixffb-ss98/…
– jirib
Oct 25 '13 at 13:48