Problems with rounding giving too many digits
$begingroup$
My current code is:
round = .1;
f[x_] := x + 4 - Sqrt[3 x^2 - 5]
xx = Solve[f[x] == 0, Reals];
StringForm["x=`1`",
If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round],
"none"]]
x=5.800000000000001`
which i want to give me an output of "x = 5.8" instead.
Any advice would be appreciated.
formatting round
$endgroup$
add a comment |
$begingroup$
My current code is:
round = .1;
f[x_] := x + 4 - Sqrt[3 x^2 - 5]
xx = Solve[f[x] == 0, Reals];
StringForm["x=`1`",
If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round],
"none"]]
x=5.800000000000001`
which i want to give me an output of "x = 5.8" instead.
Any advice would be appreciated.
formatting round
$endgroup$
$begingroup$
StringForm["x=
1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
$endgroup$
– Bob Hanlon
2 hours ago
1
$begingroup$
Could round exactly and then useN
:N[Round[Max[xx[[All, 1, 2]]], 1/10]]
$endgroup$
– Daniel Lichtblau
2 hours ago
add a comment |
$begingroup$
My current code is:
round = .1;
f[x_] := x + 4 - Sqrt[3 x^2 - 5]
xx = Solve[f[x] == 0, Reals];
StringForm["x=`1`",
If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round],
"none"]]
x=5.800000000000001`
which i want to give me an output of "x = 5.8" instead.
Any advice would be appreciated.
formatting round
$endgroup$
My current code is:
round = .1;
f[x_] := x + 4 - Sqrt[3 x^2 - 5]
xx = Solve[f[x] == 0, Reals];
StringForm["x=`1`",
If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round],
"none"]]
x=5.800000000000001`
which i want to give me an output of "x = 5.8" instead.
Any advice would be appreciated.
formatting round
formatting round
edited 1 hour ago
Alexey Popkov
38.5k4108263
38.5k4108263
asked 2 hours ago
WomblesWombles
584
584
$begingroup$
StringForm["x=
1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
$endgroup$
– Bob Hanlon
2 hours ago
1
$begingroup$
Could round exactly and then useN
:N[Round[Max[xx[[All, 1, 2]]], 1/10]]
$endgroup$
– Daniel Lichtblau
2 hours ago
add a comment |
$begingroup$
StringForm["x=
1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
$endgroup$
– Bob Hanlon
2 hours ago
1
$begingroup$
Could round exactly and then useN
:N[Round[Max[xx[[All, 1, 2]]], 1/10]]
$endgroup$
– Daniel Lichtblau
2 hours ago
$begingroup$
StringForm["x=
1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
$endgroup$
– Bob Hanlon
2 hours ago
$begingroup$
StringForm["x=
1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
$endgroup$
– Bob Hanlon
2 hours ago
1
1
$begingroup$
Could round exactly and then use
N
: N[Round[Max[xx[[All, 1, 2]]], 1/10]]
$endgroup$
– Daniel Lichtblau
2 hours ago
$begingroup$
Could round exactly and then use
N
: N[Round[Max[xx[[All, 1, 2]]], 1/10]]
$endgroup$
– Daniel Lichtblau
2 hours ago
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
You could add a StandardForm
wrapper:
StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]
x=5.8
$endgroup$
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
2 hours ago
add a comment |
$begingroup$
StringForm["x=`1`", If[Length[xx] >= 1,
DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2],
"none"]]
x = 5.8
Same result with NumberForm
in place of DecimalForm
.
$endgroup$
$begingroup$
Thank you, this worked great
$endgroup$
– Wombles
1 hour ago
add a comment |
$begingroup$
StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]
x = 5.8
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You could add a StandardForm
wrapper:
StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]
x=5.8
$endgroup$
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
2 hours ago
add a comment |
$begingroup$
You could add a StandardForm
wrapper:
StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]
x=5.8
$endgroup$
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
2 hours ago
add a comment |
$begingroup$
You could add a StandardForm
wrapper:
StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]
x=5.8
$endgroup$
You could add a StandardForm
wrapper:
StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]
x=5.8
answered 2 hours ago
Carl WollCarl Woll
69.4k393179
69.4k393179
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
2 hours ago
add a comment |
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
2 hours ago
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
2 hours ago
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
2 hours ago
add a comment |
$begingroup$
StringForm["x=`1`", If[Length[xx] >= 1,
DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2],
"none"]]
x = 5.8
Same result with NumberForm
in place of DecimalForm
.
$endgroup$
$begingroup$
Thank you, this worked great
$endgroup$
– Wombles
1 hour ago
add a comment |
$begingroup$
StringForm["x=`1`", If[Length[xx] >= 1,
DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2],
"none"]]
x = 5.8
Same result with NumberForm
in place of DecimalForm
.
$endgroup$
$begingroup$
Thank you, this worked great
$endgroup$
– Wombles
1 hour ago
add a comment |
$begingroup$
StringForm["x=`1`", If[Length[xx] >= 1,
DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2],
"none"]]
x = 5.8
Same result with NumberForm
in place of DecimalForm
.
$endgroup$
StringForm["x=`1`", If[Length[xx] >= 1,
DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2],
"none"]]
x = 5.8
Same result with NumberForm
in place of DecimalForm
.
edited 2 hours ago
answered 2 hours ago
kglrkglr
187k10203421
187k10203421
$begingroup$
Thank you, this worked great
$endgroup$
– Wombles
1 hour ago
add a comment |
$begingroup$
Thank you, this worked great
$endgroup$
– Wombles
1 hour ago
$begingroup$
Thank you, this worked great
$endgroup$
– Wombles
1 hour ago
$begingroup$
Thank you, this worked great
$endgroup$
– Wombles
1 hour ago
add a comment |
$begingroup$
StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]
x = 5.8
$endgroup$
add a comment |
$begingroup$
StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]
x = 5.8
$endgroup$
add a comment |
$begingroup$
StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]
x = 5.8
$endgroup$
StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]
x = 5.8
answered 2 hours ago
mjwmjw
5328
5328
add a comment |
add a comment |
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$begingroup$
StringForm["x=
1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
$endgroup$
– Bob Hanlon
2 hours ago
1
$begingroup$
Could round exactly and then use
N
:N[Round[Max[xx[[All, 1, 2]]], 1/10]]
$endgroup$
– Daniel Lichtblau
2 hours ago