set -f inside function
I have a directory with files file1.c, file2.c and file3.c. The output of find is:
$ find -name "*.c"
./file1.c
./file2.c
./file3.c
I want to remove the quotes from the argument of -name. So I use set -f:
$ set -f
$ find -name *.c
./file1.c
./file2.c
./file3.c
$ set +f
Since this worked as expected I made a function in .bashrc based on the previous code:
find() {
set -f
eval command find $@
set +f
}
but testing it gave the error:
$ . ~/.bashrc && find -name *c
find: paths must precede expression: file1.c
Usage: find [-H] [-L] [-P] [-Olevel] [-D help|tree|search|stat|rates|opt|exec] [path...] [expression
Why did set -f; find -name *.c ; set +f give error when calling the function, but did not give error when entering the commands in the shell?
bash find function set
asked 2 mins ago
SergioSergio
1014
add a comment |
I have a directory with files file1.c, file2.c and file3.c. The output of find is:
$ find -name "*.c"
./file1.c
./file2.c
./file3.c
I want to remove the quotes from the argument of -name. So I use set -f:
$ set -f
$ find -name *.c
./file1.c
./file2.c
./file3.c
$ set +f
Since this worked as expected I made a function in .bashrc based on the previous code:
find() {
set -f
eval command find $@
set +f
}
but testing it gave the error:
$ . ~/.bashrc && find -name *c
find: paths must precede expression: file1.c
Usage: find [-H] [-L] [-P] [-Olevel] [-D help|tree|search|stat|rates|opt|exec] [path...] [expression
Why did set -f; find -name *.c ; set +f give error when calling the function, but did not give error when entering the commands in the shell?
bash find function set
asked 2 mins ago
SergioSergio
1014
add a comment |
I have a directory with files file1.c, file2.c and file3.c. The output of find is:
$ find -name "*.c"
./file1.c
./file2.c
./file3.c
I want to remove the quotes from the argument of -name. So I use set -f:
$ set -f
$ find -name *.c
./file1.c
./file2.c
./file3.c
$ set +f
Since this worked as expected I made a function in .bashrc based on the previous code:
find() {
set -f
eval command find $@
set +f
}
but testing it gave the error:
$ . ~/.bashrc && find -name *c
find: paths must precede expression: file1.c
Usage: find [-H] [-L] [-P] [-Olevel] [-D help|tree|search|stat|rates|opt|exec] [path...] [expression
Why did set -f; find -name *.c ; set +f give error when calling the function, but did not give error when entering the commands in the shell?
bash find function set
asked 2 mins ago
SergioSergio
1014
I have a directory with files file1.c, file2.c and file3.c. The output of find is:
$ find -name "*.c"
./file1.c
./file2.c
./file3.c
I want to remove the quotes from the argument of -name. So I use set -f:
$ set -f
$ find -name *.c
./file1.c
./file2.c
./file3.c
$ set +f
Since this worked as expected I made a function in .bashrc based on the previous code:
find() {
set -f
eval command find $@
set +f
}
but testing it gave the error:
$ . ~/.bashrc && find -name *c
find: paths must precede expression: file1.c
Usage: find [-H] [-L] [-P] [-Olevel] [-D help|tree|search|stat|rates|opt|exec] [path...] [expression
Why did set -f; find -name *.c ; set +f give error when calling the function, but did not give error when entering the commands in the shell?
bash find function set
bash find function set
asked 2 mins ago
SergioSergio
1014
asked 2 mins ago
SergioSergio
1014
asked 2 mins ago
SergioSergio
1014
asked 2 mins ago
SergioSergio
1014
asked 2 mins ago
SergioSergio
1014
1014
add a comment |
add a comment |
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