Split a string by some separator in bash?

I would like to split a string into substrings, separated by some separator (which is also a string itself).

How can I do that

using bash only? (for minimalism, and my main interest)

or If allowing some text processing program? (for convenience when the program is available)

Thanks.

Simple example,

split 1--123--23 by -- into 1, 123 and 23.

split 1?*123 by ?* into 1 and 123

edited Jul 14 '17 at 20:35

asked Jul 14 '17 at 20:25

Tim

26.4k75248457

Could you show an example of your input and expected output?

– choroba
Jul 14 '17 at 20:30

With a fixed number of substrings, or variable?

– Jeff Schaller
Jul 14 '17 at 20:32

No. The number of substrings in the result depends on the original string and the separator. @JeffSchaller

– Tim
Jul 14 '17 at 20:33

2

It wasn't a true/false question, I was asking what type of input you're asking about.

– Jeff Schaller
Jul 14 '17 at 20:35

You're better off using the external programs (sed, awk) that are precisely designed for such text processing. But that's for practicality and getting things done. If this is a question of academic interest as I suspect it is, of course, that wouldn't apply.

– Wildcard
Jul 14 '17 at 23:24

add a comment |

I would like to split a string into substrings, separated by some separator (which is also a string itself).

How can I do that

using bash only? (for minimalism, and my main interest)

or If allowing some text processing program? (for convenience when the program is available)

Thanks.

Simple example,

split 1--123--23 by -- into 1, 123 and 23.

split 1?*123 by ?* into 1 and 123

edited Jul 14 '17 at 20:35

asked Jul 14 '17 at 20:25

Tim

26.4k75248457

Could you show an example of your input and expected output?

– choroba
Jul 14 '17 at 20:30

With a fixed number of substrings, or variable?

– Jeff Schaller
Jul 14 '17 at 20:32

No. The number of substrings in the result depends on the original string and the separator. @JeffSchaller

– Tim
Jul 14 '17 at 20:33

2

It wasn't a true/false question, I was asking what type of input you're asking about.

– Jeff Schaller
Jul 14 '17 at 20:35

You're better off using the external programs (sed, awk) that are precisely designed for such text processing. But that's for practicality and getting things done. If this is a question of academic interest as I suspect it is, of course, that wouldn't apply.

– Wildcard
Jul 14 '17 at 23:24

add a comment |

I would like to split a string into substrings, separated by some separator (which is also a string itself).

How can I do that

using bash only? (for minimalism, and my main interest)

or If allowing some text processing program? (for convenience when the program is available)

Thanks.

Simple example,

split 1--123--23 by -- into 1, 123 and 23.

split 1?*123 by ?* into 1 and 123

edited Jul 14 '17 at 20:35

asked Jul 14 '17 at 20:25

Tim

26.4k75248457

I would like to split a string into substrings, separated by some separator (which is also a string itself).

How can I do that

using bash only? (for minimalism, and my main interest)

or If allowing some text processing program? (for convenience when the program is available)

Thanks.

Simple example,

split 1--123--23 by -- into 1, 123 and 23.

split 1?*123 by ?* into 1 and 123

bash text-processing

edited Jul 14 '17 at 20:35

asked Jul 14 '17 at 20:25

Tim

26.4k75248457

edited Jul 14 '17 at 20:35

asked Jul 14 '17 at 20:25

Tim

26.4k75248457

edited Jul 14 '17 at 20:35

asked Jul 14 '17 at 20:25

Tim

26.4k75248457

asked Jul 14 '17 at 20:25

Tim

26.4k75248457

asked Jul 14 '17 at 20:25

Tim

26.4k75248457

Could you show an example of your input and expected output?

– choroba
Jul 14 '17 at 20:30

With a fixed number of substrings, or variable?

– Jeff Schaller
Jul 14 '17 at 20:32

No. The number of substrings in the result depends on the original string and the separator. @JeffSchaller

– Tim
Jul 14 '17 at 20:33

2

It wasn't a true/false question, I was asking what type of input you're asking about.

– Jeff Schaller
Jul 14 '17 at 20:35

You're better off using the external programs (sed, awk) that are precisely designed for such text processing. But that's for practicality and getting things done. If this is a question of academic interest as I suspect it is, of course, that wouldn't apply.

– Wildcard
Jul 14 '17 at 23:24

add a comment |

Could you show an example of your input and expected output?

– choroba
Jul 14 '17 at 20:30

With a fixed number of substrings, or variable?

– Jeff Schaller
Jul 14 '17 at 20:32

No. The number of substrings in the result depends on the original string and the separator. @JeffSchaller

– Tim
Jul 14 '17 at 20:33

2

It wasn't a true/false question, I was asking what type of input you're asking about.

– Jeff Schaller
Jul 14 '17 at 20:35

You're better off using the external programs (sed, awk) that are precisely designed for such text processing. But that's for practicality and getting things done. If this is a question of academic interest as I suspect it is, of course, that wouldn't apply.

– Wildcard
Jul 14 '17 at 23:24

Could you show an example of your input and expected output?

– choroba
Jul 14 '17 at 20:30

With a fixed number of substrings, or variable?

– Jeff Schaller
Jul 14 '17 at 20:32

No. The number of substrings in the result depends on the original string and the separator. @JeffSchaller

– Tim
Jul 14 '17 at 20:33

It wasn't a true/false question, I was asking what type of input you're asking about.

– Jeff Schaller
Jul 14 '17 at 20:35

You're better off using the external programs (sed, awk) that are precisely designed for such text processing. But that's for practicality and getting things done. If this is a question of academic interest as I suspect it is, of course, that wouldn't apply.

– Wildcard
Jul 14 '17 at 23:24

add a comment |

5 Answers
5

active

oldest

votes

Pure bash solution, using IFS and read. Note that the strings shouldn't contain $'2' (or whatever else you use for IFS, unfortunately $'' doesn't work, but e.g. $'666' does):

#!/bin/bash



split_by () {

    string=$1

    separator=$2



    tmp=${string//"$separator"/$'2'}

    IFS=$'2' read -a arr <<< "$tmp"

    for substr in "${arr[@]}" ; do

        echo "<$substr>"

    done

    echo

}





split_by '1--123--23' '--'

split_by '1?*123' '?*'

Or use Perl:

perl -E 'say for split quotemeta shift, shift' -- "$separator" "$string"

edited Jul 14 '17 at 21:25

answered Jul 14 '17 at 20:41

choroba

26.4k44773

+1. personally, i'd have separator as the first arg, same as perl. also allows looping over all remaining args and splitting them too: separator="$1" ; shift ; for string in "$@" ; do ... ; done

– cas
Jul 17 '17 at 3:23

FYI, i wrote a join function for bash because I missed it from perl. unix.stackexchange.com/a/299362/7696

– cas
Jul 17 '17 at 3:26

Thanks. Is the purpose of tmp=${string//"$separator"/$'2'} to replace a separator $separator which might be more than one character long to a separator 2 just one character in length? If yes, why isn't it rewritten as tmp=${string/"$separator"/'2'} instead? What do // and /$ mean?

– Tim
Aug 1 '17 at 13:30

@Tim: exactly. That's how IFS works.

– choroba
Aug 1 '17 at 13:34

@Tim: '2' are 2 characters, $'2' is one. // is global replace, see Parameter Expansion in man bash.

– choroba
Aug 1 '17 at 13:35

|
show 2 more comments

Simply with awk:

str="1--123--23"

awk -F'--' '{ for(i=1;i<=NF;i++) print $i }' <<< $str

The output:

Another short Python solution:

splitter.py script:

import sys

print('n'.join(sys.argv[2].split(sys.argv[1])))

arguments order:

sys.argv[0] - script name (i.e. splitter.py)

sys.argv[1] - substring separator

sys.argv[2] - input string

Usage:

python splitter.py "?*" "1?*123"

1

123

python splitter.py "--" "1--23--123"

1

23

123

edited Jul 14 '17 at 21:20

answered Jul 14 '17 at 20:47

RomanPerekhrest

23k12346

But not pure bash. Nice solution though.

– Bob Eager
Jul 14 '17 at 21:14

add a comment |

Pure POSIX shell:

string="1--123--23"

del="--"



while test "${string#*$del}" != "$string" ; do

  echo "${string%%$del*}"

  string="${string#*$del}"

done

echo "$string"

Note that * or ? need to be escaped in the delimiter: del='*'

edited Sep 21 '17 at 6:24

answered Sep 21 '17 at 6:08

Philippos

6,00711547

add a comment |

Similar to above but say you just want to get the URI for example:

URL="http://something.com/backup/v/photos/path/to/"

URI="./$(echo $URL | awk -F'.com/' '{print $2}')"

echo $URI

edited Sep 20 '17 at 17:54

answered Sep 20 '17 at 14:05

Mike Q

1114

There already is an awk solution that even better addresses the problem.

– Philippos
Sep 20 '17 at 14:33

These other ones didn't really work for me so I just wanted to share something I was trying to do .. Is this not useful ?

– Mike Q
Sep 20 '17 at 17:54

1

The question was to cut a string into an unknown number of parts. Yours does only cut the last piece of the string and could be replaced by a simple URI="${URL#*.com}"

– Philippos
Sep 21 '17 at 5:51

add a comment |

#! /bin/bash

#  (GPL3+) Alberto Salvia Novella (es20490446e)





substring () {

    string=${1}

    separator=${2}

    position=${3}



    substring=${string//"${separator}"/$'2'}

    IFS=$'2' read -a substring <<< "${substring}"

    echo ${substring[${position}]}

}





substring ${@}

answered 14 hours ago

Alberto Salvia Novella

add a comment |

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5 Answers
5

active

oldest

votes

5 Answers
5

active

oldest

votes

Pure bash solution, using IFS and read. Note that the strings shouldn't contain $'2' (or whatever else you use for IFS, unfortunately $'' doesn't work, but e.g. $'666' does):

#!/bin/bash



split_by () {

    string=$1

    separator=$2



    tmp=${string//"$separator"/$'2'}

    IFS=$'2' read -a arr <<< "$tmp"

    for substr in "${arr[@]}" ; do

        echo "<$substr>"

    done

    echo

}





split_by '1--123--23' '--'

split_by '1?*123' '?*'

Or use Perl:

perl -E 'say for split quotemeta shift, shift' -- "$separator" "$string"

edited Jul 14 '17 at 21:25

answered Jul 14 '17 at 20:41

choroba

26.4k44773

+1. personally, i'd have separator as the first arg, same as perl. also allows looping over all remaining args and splitting them too: separator="$1" ; shift ; for string in "$@" ; do ... ; done

– cas
Jul 17 '17 at 3:23

FYI, i wrote a join function for bash because I missed it from perl. unix.stackexchange.com/a/299362/7696

– cas
Jul 17 '17 at 3:26

Thanks. Is the purpose of tmp=${string//"$separator"/$'2'} to replace a separator $separator which might be more than one character long to a separator 2 just one character in length? If yes, why isn't it rewritten as tmp=${string/"$separator"/'2'} instead? What do // and /$ mean?

– Tim
Aug 1 '17 at 13:30

@Tim: exactly. That's how IFS works.

– choroba
Aug 1 '17 at 13:34

@Tim: '2' are 2 characters, $'2' is one. // is global replace, see Parameter Expansion in man bash.

– choroba
Aug 1 '17 at 13:35

|
show 2 more comments

Pure bash solution, using IFS and read. Note that the strings shouldn't contain $'2' (or whatever else you use for IFS, unfortunately $'' doesn't work, but e.g. $'666' does):

#!/bin/bash



split_by () {

    string=$1

    separator=$2



    tmp=${string//"$separator"/$'2'}

    IFS=$'2' read -a arr <<< "$tmp"

    for substr in "${arr[@]}" ; do

        echo "<$substr>"

    done

    echo

}





split_by '1--123--23' '--'

split_by '1?*123' '?*'

Or use Perl:

perl -E 'say for split quotemeta shift, shift' -- "$separator" "$string"

edited Jul 14 '17 at 21:25

answered Jul 14 '17 at 20:41

choroba

26.4k44773

+1. personally, i'd have separator as the first arg, same as perl. also allows looping over all remaining args and splitting them too: separator="$1" ; shift ; for string in "$@" ; do ... ; done

– cas
Jul 17 '17 at 3:23

FYI, i wrote a join function for bash because I missed it from perl. unix.stackexchange.com/a/299362/7696

– cas
Jul 17 '17 at 3:26

Thanks. Is the purpose of tmp=${string//"$separator"/$'2'} to replace a separator $separator which might be more than one character long to a separator 2 just one character in length? If yes, why isn't it rewritten as tmp=${string/"$separator"/'2'} instead? What do // and /$ mean?

– Tim
Aug 1 '17 at 13:30

@Tim: exactly. That's how IFS works.

– choroba
Aug 1 '17 at 13:34

@Tim: '2' are 2 characters, $'2' is one. // is global replace, see Parameter Expansion in man bash.

– choroba
Aug 1 '17 at 13:35

|
show 2 more comments

Pure bash solution, using IFS and read. Note that the strings shouldn't contain $'2' (or whatever else you use for IFS, unfortunately $'' doesn't work, but e.g. $'666' does):

#!/bin/bash



split_by () {

    string=$1

    separator=$2



    tmp=${string//"$separator"/$'2'}

    IFS=$'2' read -a arr <<< "$tmp"

    for substr in "${arr[@]}" ; do

        echo "<$substr>"

    done

    echo

}





split_by '1--123--23' '--'

split_by '1?*123' '?*'

Or use Perl:

perl -E 'say for split quotemeta shift, shift' -- "$separator" "$string"

edited Jul 14 '17 at 21:25

answered Jul 14 '17 at 20:41

choroba

26.4k44773

Pure bash solution, using IFS and read. Note that the strings shouldn't contain $'2' (or whatever else you use for IFS, unfortunately $'' doesn't work, but e.g. $'666' does):

#!/bin/bash



split_by () {

    string=$1

    separator=$2



    tmp=${string//"$separator"/$'2'}

    IFS=$'2' read -a arr <<< "$tmp"

    for substr in "${arr[@]}" ; do

        echo "<$substr>"

    done

    echo

}





split_by '1--123--23' '--'

split_by '1?*123' '?*'

Or use Perl:

perl -E 'say for split quotemeta shift, shift' -- "$separator" "$string"

edited Jul 14 '17 at 21:25

answered Jul 14 '17 at 20:41

choroba

26.4k44773

edited Jul 14 '17 at 21:25

answered Jul 14 '17 at 20:41

choroba

26.4k44773

answered Jul 14 '17 at 20:41

choroba

26.4k44773

answered Jul 14 '17 at 20:41

choroba

26.4k44773

+1. personally, i'd have separator as the first arg, same as perl. also allows looping over all remaining args and splitting them too: separator="$1" ; shift ; for string in "$@" ; do ... ; done

– cas
Jul 17 '17 at 3:23

FYI, i wrote a join function for bash because I missed it from perl. unix.stackexchange.com/a/299362/7696

– cas
Jul 17 '17 at 3:26

Thanks. Is the purpose of tmp=${string//"$separator"/$'2'} to replace a separator $separator which might be more than one character long to a separator 2 just one character in length? If yes, why isn't it rewritten as tmp=${string/"$separator"/'2'} instead? What do // and /$ mean?

– Tim
Aug 1 '17 at 13:30

@Tim: exactly. That's how IFS works.

– choroba
Aug 1 '17 at 13:34

@Tim: '2' are 2 characters, $'2' is one. // is global replace, see Parameter Expansion in man bash.

– choroba
Aug 1 '17 at 13:35

|
show 2 more comments

+1. personally, i'd have separator as the first arg, same as perl. also allows looping over all remaining args and splitting them too: separator="$1" ; shift ; for string in "$@" ; do ... ; done

– cas
Jul 17 '17 at 3:23

FYI, i wrote a join function for bash because I missed it from perl. unix.stackexchange.com/a/299362/7696

– cas
Jul 17 '17 at 3:26

Thanks. Is the purpose of tmp=${string//"$separator"/$'2'} to replace a separator $separator which might be more than one character long to a separator 2 just one character in length? If yes, why isn't it rewritten as tmp=${string/"$separator"/'2'} instead? What do // and /$ mean?

– Tim
Aug 1 '17 at 13:30

@Tim: exactly. That's how IFS works.

– choroba
Aug 1 '17 at 13:34

@Tim: '2' are 2 characters, $'2' is one. // is global replace, see Parameter Expansion in man bash.

– choroba
Aug 1 '17 at 13:35

+1. personally, i'd have separator as the first arg, same as perl. also allows looping over all remaining args and splitting them too: separator="$1" ; shift ; for string in "$@" ; do ... ; done

– cas
Jul 17 '17 at 3:23

FYI, i wrote a join function for bash because I missed it from perl. unix.stackexchange.com/a/299362/7696

– cas
Jul 17 '17 at 3:26

Thanks. Is the purpose of tmp=${string//"$separator"/$'2'} to replace a separator $separator which might be more than one character long to a separator 2 just one character in length? If yes, why isn't it rewritten as tmp=${string/"$separator"/'2'} instead? What do // and /$ mean?

– Tim
Aug 1 '17 at 13:30

@Tim: exactly. That's how IFS works.

– choroba
Aug 1 '17 at 13:34

@Tim: '2' are 2 characters, $'2' is one. // is global replace, see Parameter Expansion in man bash.

– choroba
Aug 1 '17 at 13:35

|
show 2 more comments

Simply with awk:

str="1--123--23"

awk -F'--' '{ for(i=1;i<=NF;i++) print $i }' <<< $str

The output:

Another short Python solution:

splitter.py script:

import sys

print('n'.join(sys.argv[2].split(sys.argv[1])))

arguments order:

sys.argv[0] - script name (i.e. splitter.py)

sys.argv[1] - substring separator

sys.argv[2] - input string

Usage:

python splitter.py "?*" "1?*123"

1

123

python splitter.py "--" "1--23--123"

1

23

123

edited Jul 14 '17 at 21:20

answered Jul 14 '17 at 20:47

RomanPerekhrest

23k12346

But not pure bash. Nice solution though.

– Bob Eager
Jul 14 '17 at 21:14

add a comment |

Simply with awk:

str="1--123--23"

awk -F'--' '{ for(i=1;i<=NF;i++) print $i }' <<< $str

The output:

Another short Python solution:

splitter.py script:

import sys

print('n'.join(sys.argv[2].split(sys.argv[1])))

arguments order:

sys.argv[0] - script name (i.e. splitter.py)

sys.argv[1] - substring separator

sys.argv[2] - input string

Usage:

python splitter.py "?*" "1?*123"

1

123

python splitter.py "--" "1--23--123"

1

23

123

edited Jul 14 '17 at 21:20

answered Jul 14 '17 at 20:47

RomanPerekhrest

23k12346

But not pure bash. Nice solution though.

– Bob Eager
Jul 14 '17 at 21:14

add a comment |

Simply with awk:

str="1--123--23"

awk -F'--' '{ for(i=1;i<=NF;i++) print $i }' <<< $str

The output:

Another short Python solution:

splitter.py script:

import sys

print('n'.join(sys.argv[2].split(sys.argv[1])))

arguments order:

sys.argv[0] - script name (i.e. splitter.py)

sys.argv[1] - substring separator

sys.argv[2] - input string

Usage:

python splitter.py "?*" "1?*123"

1

123

python splitter.py "--" "1--23--123"

1

23

123

edited Jul 14 '17 at 21:20

answered Jul 14 '17 at 20:47

RomanPerekhrest

23k12346

Simply with awk:

str="1--123--23"

awk -F'--' '{ for(i=1;i<=NF;i++) print $i }' <<< $str

The output:

Another short Python solution:

splitter.py script:

import sys

print('n'.join(sys.argv[2].split(sys.argv[1])))

arguments order:

sys.argv[0] - script name (i.e. splitter.py)

sys.argv[1] - substring separator

sys.argv[2] - input string

Usage:

python splitter.py "?*" "1?*123"

1

123

python splitter.py "--" "1--23--123"

1

23

123

edited Jul 14 '17 at 21:20

answered Jul 14 '17 at 20:47

RomanPerekhrest

23k12346

edited Jul 14 '17 at 21:20

answered Jul 14 '17 at 20:47

RomanPerekhrest

23k12346

answered Jul 14 '17 at 20:47

RomanPerekhrest

23k12346

answered Jul 14 '17 at 20:47

RomanPerekhrest

23k12346

But not pure bash. Nice solution though.

– Bob Eager
Jul 14 '17 at 21:14

add a comment |

But not pure bash. Nice solution though.

– Bob Eager
Jul 14 '17 at 21:14

But not pure bash. Nice solution though.

– Bob Eager
Jul 14 '17 at 21:14

add a comment |

Pure POSIX shell:

string="1--123--23"

del="--"



while test "${string#*$del}" != "$string" ; do

  echo "${string%%$del*}"

  string="${string#*$del}"

done

echo "$string"

Note that * or ? need to be escaped in the delimiter: del='*'

edited Sep 21 '17 at 6:24

answered Sep 21 '17 at 6:08

Philippos

6,00711547

add a comment |

Pure POSIX shell:

string="1--123--23"

del="--"



while test "${string#*$del}" != "$string" ; do

  echo "${string%%$del*}"

  string="${string#*$del}"

done

echo "$string"

Note that * or ? need to be escaped in the delimiter: del='*'

edited Sep 21 '17 at 6:24

answered Sep 21 '17 at 6:08

Philippos

6,00711547

add a comment |

Pure POSIX shell:

string="1--123--23"

del="--"



while test "${string#*$del}" != "$string" ; do

  echo "${string%%$del*}"

  string="${string#*$del}"

done

echo "$string"

Note that * or ? need to be escaped in the delimiter: del='*'

edited Sep 21 '17 at 6:24

answered Sep 21 '17 at 6:08

Philippos

6,00711547

Pure POSIX shell:

string="1--123--23"

del="--"



while test "${string#*$del}" != "$string" ; do

  echo "${string%%$del*}"

  string="${string#*$del}"

done

echo "$string"

Note that * or ? need to be escaped in the delimiter: del='*'

edited Sep 21 '17 at 6:24

answered Sep 21 '17 at 6:08

Philippos

6,00711547

edited Sep 21 '17 at 6:24

answered Sep 21 '17 at 6:08

Philippos

6,00711547

answered Sep 21 '17 at 6:08

Philippos

6,00711547

answered Sep 21 '17 at 6:08

Philippos

6,00711547

add a comment |

Similar to above but say you just want to get the URI for example:

URL="http://something.com/backup/v/photos/path/to/"

URI="./$(echo $URL | awk -F'.com/' '{print $2}')"

echo $URI

edited Sep 20 '17 at 17:54

answered Sep 20 '17 at 14:05

Mike Q

1114

There already is an awk solution that even better addresses the problem.

– Philippos
Sep 20 '17 at 14:33

These other ones didn't really work for me so I just wanted to share something I was trying to do .. Is this not useful ?

– Mike Q
Sep 20 '17 at 17:54

1

The question was to cut a string into an unknown number of parts. Yours does only cut the last piece of the string and could be replaced by a simple URI="${URL#*.com}"

– Philippos
Sep 21 '17 at 5:51

add a comment |

Similar to above but say you just want to get the URI for example:

URL="http://something.com/backup/v/photos/path/to/"

URI="./$(echo $URL | awk -F'.com/' '{print $2}')"

echo $URI

edited Sep 20 '17 at 17:54

answered Sep 20 '17 at 14:05

Mike Q

1114

There already is an awk solution that even better addresses the problem.

– Philippos
Sep 20 '17 at 14:33

These other ones didn't really work for me so I just wanted to share something I was trying to do .. Is this not useful ?

– Mike Q
Sep 20 '17 at 17:54

1

The question was to cut a string into an unknown number of parts. Yours does only cut the last piece of the string and could be replaced by a simple URI="${URL#*.com}"

– Philippos
Sep 21 '17 at 5:51

add a comment |

Similar to above but say you just want to get the URI for example:

URL="http://something.com/backup/v/photos/path/to/"

URI="./$(echo $URL | awk -F'.com/' '{print $2}')"

echo $URI

edited Sep 20 '17 at 17:54

answered Sep 20 '17 at 14:05

Mike Q

1114

Similar to above but say you just want to get the URI for example:

URL="http://something.com/backup/v/photos/path/to/"

URI="./$(echo $URL | awk -F'.com/' '{print $2}')"

echo $URI

edited Sep 20 '17 at 17:54

answered Sep 20 '17 at 14:05

Mike Q

1114

edited Sep 20 '17 at 17:54

answered Sep 20 '17 at 14:05

Mike Q

1114

answered Sep 20 '17 at 14:05

Mike Q

1114

answered Sep 20 '17 at 14:05

Mike Q

1114

There already is an awk solution that even better addresses the problem.

– Philippos
Sep 20 '17 at 14:33

These other ones didn't really work for me so I just wanted to share something I was trying to do .. Is this not useful ?

– Mike Q
Sep 20 '17 at 17:54

1

The question was to cut a string into an unknown number of parts. Yours does only cut the last piece of the string and could be replaced by a simple URI="${URL#*.com}"

– Philippos
Sep 21 '17 at 5:51

add a comment |

There already is an awk solution that even better addresses the problem.

– Philippos
Sep 20 '17 at 14:33

These other ones didn't really work for me so I just wanted to share something I was trying to do .. Is this not useful ?

– Mike Q
Sep 20 '17 at 17:54

1

The question was to cut a string into an unknown number of parts. Yours does only cut the last piece of the string and could be replaced by a simple URI="${URL#*.com}"

– Philippos
Sep 21 '17 at 5:51

There already is an awk solution that even better addresses the problem.

– Philippos
Sep 20 '17 at 14:33

These other ones didn't really work for me so I just wanted to share something I was trying to do .. Is this not useful ?

– Mike Q
Sep 20 '17 at 17:54

The question was to cut a string into an unknown number of parts. Yours does only cut the last piece of the string and could be replaced by a simple URI="${URL#*.com}"

– Philippos
Sep 21 '17 at 5:51

add a comment |

#! /bin/bash

#  (GPL3+) Alberto Salvia Novella (es20490446e)





substring () {

    string=${1}

    separator=${2}

    position=${3}



    substring=${string//"${separator}"/$'2'}

    IFS=$'2' read -a substring <<< "${substring}"

    echo ${substring[${position}]}

}





substring ${@}

answered 14 hours ago

Alberto Salvia Novella

add a comment |

#! /bin/bash

#  (GPL3+) Alberto Salvia Novella (es20490446e)





substring () {

    string=${1}

    separator=${2}

    position=${3}



    substring=${string//"${separator}"/$'2'}

    IFS=$'2' read -a substring <<< "${substring}"

    echo ${substring[${position}]}

}





substring ${@}

answered 14 hours ago

Alberto Salvia Novella

add a comment |

#! /bin/bash

#  (GPL3+) Alberto Salvia Novella (es20490446e)





substring () {

    string=${1}

    separator=${2}

    position=${3}



    substring=${string//"${separator}"/$'2'}

    IFS=$'2' read -a substring <<< "${substring}"

    echo ${substring[${position}]}

}





substring ${@}

answered 14 hours ago

Alberto Salvia Novella

#! /bin/bash

#  (GPL3+) Alberto Salvia Novella (es20490446e)





substring () {

    string=${1}

    separator=${2}

    position=${3}



    substring=${string//"${separator}"/$'2'}

    IFS=$'2' read -a substring <<< "${substring}"

    echo ${substring[${position}]}

}





substring ${@}

answered 14 hours ago

Alberto Salvia Novella

answered 14 hours ago

Alberto Salvia Novella

answered 14 hours ago

Alberto Salvia Novella

answered 14 hours ago

Alberto Salvia Novella

add a comment |

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