awk + how to export value in awk












0















I use the following awk line in order to capture the remote machine that using the port 2181



netstat -nape | awk '{if ($4 == "43.64.56.36:2181") print $4, $5 ,$6 ,$9;}'

43.64.56.36:2181 43.64.56.60:40151 ESTABLISHED 9027/java


but when I use parameter - a that represented the ip address value in the awk
seems that a parameter not get the real ip address 



 netstat -nape | awk -v a="43.64.56.36"  '{if ($4 == a:2181) print $4, $5 ,$6 ,$9;}'


no output



when I am wrong here ?






awk variable







share|improve this question




















  • 2





    Are you sure it's the correct command? $4 == a:2181 will be syntax error. You want to use $4 == a":2181"

    – cuonglm
    14 hours ago











  • what I mean is that we want a contain the ip = 43.64.56.36

    – yael
    14 hours ago











  • yes thank you so much its works

    – yael
    14 hours ago
















0















I use the following awk line in order to capture the remote machine that using the port 2181



netstat -nape | awk '{if ($4 == "43.64.56.36:2181") print $4, $5 ,$6 ,$9;}'

43.64.56.36:2181 43.64.56.60:40151 ESTABLISHED 9027/java


but when I use parameter - a that represented the ip address value in the awk
seems that a parameter not get the real ip address 



 netstat -nape | awk -v a="43.64.56.36"  '{if ($4 == a:2181) print $4, $5 ,$6 ,$9;}'


no output



when I am wrong here ?






awk variable







share|improve this question




















  • 2





    Are you sure it's the correct command? $4 == a:2181 will be syntax error. You want to use $4 == a":2181"

    – cuonglm
    14 hours ago











  • what I mean is that we want a contain the ip = 43.64.56.36

    – yael
    14 hours ago











  • yes thank you so much its works

    – yael
    14 hours ago














0












0








0








I use the following awk line in order to capture the remote machine that using the port 2181



netstat -nape | awk '{if ($4 == "43.64.56.36:2181") print $4, $5 ,$6 ,$9;}'

43.64.56.36:2181 43.64.56.60:40151 ESTABLISHED 9027/java


but when I use parameter - a that represented the ip address value in the awk
seems that a parameter not get the real ip address 



 netstat -nape | awk -v a="43.64.56.36"  '{if ($4 == a:2181) print $4, $5 ,$6 ,$9;}'


no output



when I am wrong here ?






awk variable







share|improve this question
















I use the following awk line in order to capture the remote machine that using the port 2181



netstat -nape | awk '{if ($4 == "43.64.56.36:2181") print $4, $5 ,$6 ,$9;}'

43.64.56.36:2181 43.64.56.60:40151 ESTABLISHED 9027/java


but when I use parameter - a that represented the ip address value in the awk
seems that a parameter not get the real ip address 



 netstat -nape | awk -v a="43.64.56.36"  '{if ($4 == a:2181) print $4, $5 ,$6 ,$9;}'


no output



when I am wrong here ?






awk variable




awk variable






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 14 hours ago









Jeff Schaller

39.5k1054126




39.5k1054126










asked 14 hours ago









yaelyael

2,49612363




2,49612363








  • 2





    Are you sure it's the correct command? $4 == a:2181 will be syntax error. You want to use $4 == a":2181"

    – cuonglm
    14 hours ago











  • what I mean is that we want a contain the ip = 43.64.56.36

    – yael
    14 hours ago











  • yes thank you so much its works

    – yael
    14 hours ago














  • 2





    Are you sure it's the correct command? $4 == a:2181 will be syntax error. You want to use $4 == a":2181"

    – cuonglm
    14 hours ago











  • what I mean is that we want a contain the ip = 43.64.56.36

    – yael
    14 hours ago











  • yes thank you so much its works

    – yael
    14 hours ago








2




2





Are you sure it's the correct command? $4 == a:2181 will be syntax error. You want to use $4 == a":2181"

– cuonglm
14 hours ago





Are you sure it's the correct command? $4 == a:2181 will be syntax error. You want to use $4 == a":2181"

– cuonglm
14 hours ago













what I mean is that we want a contain the ip = 43.64.56.36

– yael
14 hours ago





what I mean is that we want a contain the ip = 43.64.56.36

– yael
14 hours ago













yes thank you so much its works

– yael
14 hours ago





yes thank you so much its works

– yael
14 hours ago










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we solved it by the following syntax



netstat -nape | awk -v a="43.64.56.36"  '{if ($4 == a":2181") print $4, $5 ,$6 ,$9;}'





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    we solved it by the following syntax



    netstat -nape | awk -v a="43.64.56.36"  '{if ($4 == a":2181") print $4, $5 ,$6 ,$9;}'





    share|improve this answer




























      0














      we solved it by the following syntax



      netstat -nape | awk -v a="43.64.56.36"  '{if ($4 == a":2181") print $4, $5 ,$6 ,$9;}'





      share|improve this answer


























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        0







        we solved it by the following syntax



        netstat -nape | awk -v a="43.64.56.36"  '{if ($4 == a":2181") print $4, $5 ,$6 ,$9;}'





        share|improve this answer













        we solved it by the following syntax



        netstat -nape | awk -v a="43.64.56.36"  '{if ($4 == a":2181") print $4, $5 ,$6 ,$9;}'






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 14 hours ago









        yaelyael

        2,49612363




        2,49612363






























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