How do I replace words with increasing numbers?
0
For example, the only thing in file.txt looks like this:
xxxxxxxxxHAHAxxxxxxHOHOxxxxxxx
I hope to replace HAHA with seq 1 3 and replace HOHO with seq 5 7, so the output should be:
xxxxxxxxx1xxxxxx5xxxxxxx
xxxxxxxxx2xxxxxx6xxxxxxx
xxxxxxxxx3xxxxxx7xxxxxxx
What I did:
for i in $(seq 1 3)
do sed "s/HAHA/$i/g" file.txt
for i in $(seq 5 7)
do sed "s/HOHO/$i/g" file.txt
done
done > new.txt
But new.txt doesn't show what I expected. How should I change the code?
bash shell-script text-processing
asked 56 mins ago
LittleGLittleG
31
New contributor
LittleG is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
0
For example, the only thing in file.txt looks like this:
xxxxxxxxxHAHAxxxxxxHOHOxxxxxxx
I hope to replace HAHA with seq 1 3 and replace HOHO with seq 5 7, so the output should be:
xxxxxxxxx1xxxxxx5xxxxxxx
xxxxxxxxx2xxxxxx6xxxxxxx
xxxxxxxxx3xxxxxx7xxxxxxx
What I did:
for i in $(seq 1 3)
do sed "s/HAHA/$i/g" file.txt
for i in $(seq 5 7)
do sed "s/HOHO/$i/g" file.txt
done
done > new.txt
But new.txt doesn't show what I expected. How should I change the code?
bash shell-script text-processing
asked 56 mins ago
LittleGLittleG
31
New contributor
LittleG is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
By the way, I added four spaces to each line of my code, but it doesn't format like what it should be like
– LittleG
55 mins ago
add a comment |
0
0
0
For example, the only thing in file.txt looks like this:
xxxxxxxxxHAHAxxxxxxHOHOxxxxxxx
I hope to replace HAHA with seq 1 3 and replace HOHO with seq 5 7, so the output should be:
xxxxxxxxx1xxxxxx5xxxxxxx
xxxxxxxxx2xxxxxx6xxxxxxx
xxxxxxxxx3xxxxxx7xxxxxxx
What I did:
for i in $(seq 1 3)
do sed "s/HAHA/$i/g" file.txt
for i in $(seq 5 7)
do sed "s/HOHO/$i/g" file.txt
done
done > new.txt
But new.txt doesn't show what I expected. How should I change the code?
bash shell-script text-processing
asked 56 mins ago
LittleGLittleG
31
New contributor
LittleG is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
For example, the only thing in file.txt looks like this:
xxxxxxxxxHAHAxxxxxxHOHOxxxxxxx
I hope to replace HAHA with seq 1 3 and replace HOHO with seq 5 7, so the output should be:
xxxxxxxxx1xxxxxx5xxxxxxx
xxxxxxxxx2xxxxxx6xxxxxxx
xxxxxxxxx3xxxxxx7xxxxxxx
What I did:
for i in $(seq 1 3)
do sed "s/HAHA/$i/g" file.txt
for i in $(seq 5 7)
do sed "s/HOHO/$i/g" file.txt
done
done > new.txt
But new.txt doesn't show what I expected. How should I change the code?
bash shell-script text-processing
bash shell-script text-processing
asked 56 mins ago
LittleGLittleG
31
New contributor
LittleG is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 56 mins ago
LittleGLittleG
31
New contributor
LittleG is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 51 mins ago
LittleG
asked 56 mins ago
LittleGLittleG
31
New contributor
LittleG is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 56 mins ago
LittleGLittleG
31
asked 56 mins ago
LittleGLittleG
31
31
New contributor
LittleG is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
LittleG is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
LittleG is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
By the way, I added four spaces to each line of my code, but it doesn't format like what it should be like
– LittleG
55 mins ago
add a comment |
By the way, I added four spaces to each line of my code, but it doesn't format like what it should be like
– LittleG
55 mins ago
By the way, I added four spaces to each line of my code, but it doesn't format like what it should be like
– LittleG
55 mins ago
By the way, I added four spaces to each line of my code, but it doesn't format like what it should be like
– LittleG
55 mins ago
add a comment |
1 Answer
1
active
oldest
votes
1
Here's one way you could do it, using the bash built-in read command's ability to read from different file descriptors:
while read -u3 i && read -u4 j; do
sed -e "s/HAHA/$i/" -e "s/HOHO/$j/" file.txt
done > new.txt 3< <(seq 1 3) 4< <(seq 5 7)
If you don't specifically need to use different seq processes, you could use a simple single loop + some shell arithmetic:
for i in $(seq 1 3); do
sed -e "s/HAHA/$i/" -e "s/HOHO/$((i+4))/" file.txt
done > new.txt
answered 38 mins ago
steeldriversteeldriver
36.5k35286
I wonder why you use 3 and 4 after the -u. Did you just choose these numbers randomly?
– LittleG
27 mins ago
@LittleG they are the first two numbers after the terminal's standard input / output / error streams (fd0,1,2) that are available as file descriptors
– steeldriver
21 mins ago
In the first solution, why do you add a space between the two <?
– LittleG
7 mins ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Here's one way you could do it, using the bash built-in read command's ability to read from different file descriptors:
while read -u3 i && read -u4 j; do
sed -e "s/HAHA/$i/" -e "s/HOHO/$j/" file.txt
done > new.txt 3< <(seq 1 3) 4< <(seq 5 7)
If you don't specifically need to use different seq processes, you could use a simple single loop + some shell arithmetic:
for i in $(seq 1 3); do
sed -e "s/HAHA/$i/" -e "s/HOHO/$((i+4))/" file.txt
done > new.txt
answered 38 mins ago
steeldriversteeldriver
36.5k35286
I wonder why you use 3 and 4 after the -u. Did you just choose these numbers randomly?
– LittleG
27 mins ago
@LittleG they are the first two numbers after the terminal's standard input / output / error streams (fd0,1,2) that are available as file descriptors
– steeldriver
21 mins ago
In the first solution, why do you add a space between the two <?
– LittleG
7 mins ago
add a comment |
1
Here's one way you could do it, using the bash built-in read command's ability to read from different file descriptors:
while read -u3 i && read -u4 j; do
sed -e "s/HAHA/$i/" -e "s/HOHO/$j/" file.txt
done > new.txt 3< <(seq 1 3) 4< <(seq 5 7)
If you don't specifically need to use different seq processes, you could use a simple single loop + some shell arithmetic:
for i in $(seq 1 3); do
sed -e "s/HAHA/$i/" -e "s/HOHO/$((i+4))/" file.txt
done > new.txt
answered 38 mins ago
steeldriversteeldriver
36.5k35286
I wonder why you use 3 and 4 after the -u. Did you just choose these numbers randomly?
– LittleG
27 mins ago
@LittleG they are the first two numbers after the terminal's standard input / output / error streams (fd0,1,2) that are available as file descriptors
– steeldriver
21 mins ago
In the first solution, why do you add a space between the two <?
– LittleG
7 mins ago
add a comment |
1
1
1
Here's one way you could do it, using the bash built-in read command's ability to read from different file descriptors:
while read -u3 i && read -u4 j; do
sed -e "s/HAHA/$i/" -e "s/HOHO/$j/" file.txt
done > new.txt 3< <(seq 1 3) 4< <(seq 5 7)
If you don't specifically need to use different seq processes, you could use a simple single loop + some shell arithmetic:
for i in $(seq 1 3); do
sed -e "s/HAHA/$i/" -e "s/HOHO/$((i+4))/" file.txt
done > new.txt
answered 38 mins ago
steeldriversteeldriver
36.5k35286
Here's one way you could do it, using the bash built-in read command's ability to read from different file descriptors:
while read -u3 i && read -u4 j; do
sed -e "s/HAHA/$i/" -e "s/HOHO/$j/" file.txt
done > new.txt 3< <(seq 1 3) 4< <(seq 5 7)
If you don't specifically need to use different seq processes, you could use a simple single loop + some shell arithmetic:
for i in $(seq 1 3); do
sed -e "s/HAHA/$i/" -e "s/HOHO/$((i+4))/" file.txt
done > new.txt
answered 38 mins ago
steeldriversteeldriver
36.5k35286
edited 17 mins ago
answered 38 mins ago
steeldriversteeldriver
36.5k35286
answered 38 mins ago
steeldriversteeldriver
36.5k35286
answered 38 mins ago
steeldriversteeldriver
36.5k35286
36.5k35286
I wonder why you use 3 and 4 after the -u. Did you just choose these numbers randomly?
– LittleG
27 mins ago
@LittleG they are the first two numbers after the terminal's standard input / output / error streams (fd0,1,2) that are available as file descriptors
– steeldriver
21 mins ago
In the first solution, why do you add a space between the two <?
– LittleG
7 mins ago
add a comment |
I wonder why you use 3 and 4 after the -u. Did you just choose these numbers randomly?
– LittleG
27 mins ago
@LittleG they are the first two numbers after the terminal's standard input / output / error streams (fd0,1,2) that are available as file descriptors
– steeldriver
21 mins ago
In the first solution, why do you add a space between the two <?
– LittleG
7 mins ago
I wonder why you use 3 and 4 after the -u. Did you just choose these numbers randomly?
– LittleG
27 mins ago
I wonder why you use 3 and 4 after the -u. Did you just choose these numbers randomly?
– LittleG
27 mins ago
@LittleG they are the first two numbers after the terminal's standard input / output / error streams (fd
0, 1, 2) that are available as file descriptors– steeldriver
21 mins ago
@LittleG they are the first two numbers after the terminal's standard input / output / error streams (fd
0, 1, 2) that are available as file descriptors– steeldriver
21 mins ago
In the first solution, why do you add a space between the two <?
– LittleG
7 mins ago
In the first solution, why do you add a space between the two <?
– LittleG
7 mins ago
add a comment |
LittleG is a new contributor. Be nice, and check out our Code of Conduct.
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By the way, I added four spaces to each line of my code, but it doesn't format like what it should be like
– LittleG
55 mins ago