I'm more than my brother but have less












16












$begingroup$



We are two brothers

bounded by a circle

I'm his double

but he has twice more legs than me




What are we?










share|improve this question







New contributor




HerrSerker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    This is my first riddle, and if anything should be unclear or two broad, I'd like to apologize for that in advance.
    $endgroup$
    – HerrSerker
    9 hours ago
















16












$begingroup$



We are two brothers

bounded by a circle

I'm his double

but he has twice more legs than me




What are we?










share|improve this question







New contributor




HerrSerker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    This is my first riddle, and if anything should be unclear or two broad, I'd like to apologize for that in advance.
    $endgroup$
    – HerrSerker
    9 hours ago














16












16








16


1



$begingroup$



We are two brothers

bounded by a circle

I'm his double

but he has twice more legs than me




What are we?










share|improve this question







New contributor




HerrSerker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$





We are two brothers

bounded by a circle

I'm his double

but he has twice more legs than me




What are we?







riddle






share|improve this question







New contributor




HerrSerker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




HerrSerker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




HerrSerker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 9 hours ago









HerrSerkerHerrSerker

2706




2706




New contributor




HerrSerker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





HerrSerker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






HerrSerker is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • $begingroup$
    This is my first riddle, and if anything should be unclear or two broad, I'd like to apologize for that in advance.
    $endgroup$
    – HerrSerker
    9 hours ago


















  • $begingroup$
    This is my first riddle, and if anything should be unclear or two broad, I'd like to apologize for that in advance.
    $endgroup$
    – HerrSerker
    9 hours ago
















$begingroup$
This is my first riddle, and if anything should be unclear or two broad, I'd like to apologize for that in advance.
$endgroup$
– HerrSerker
9 hours ago




$begingroup$
This is my first riddle, and if anything should be unclear or two broad, I'd like to apologize for that in advance.
$endgroup$
– HerrSerker
9 hours ago










1 Answer
1






active

oldest

votes


















17












$begingroup$

I think this is a play on something around




pi ($pi$) and tau ($tau$) both circle ratios.




I'm his double but he has twice more legs than me




$tau = 2pi$ but $pi$ has twice the number of legs of $tau$.







share|improve this answer









$endgroup$









  • 1




    $begingroup$
    That was even faster than I'm allowed to accept it
    $endgroup$
    – HerrSerker
    9 hours ago






  • 1




    $begingroup$
    Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
    $endgroup$
    – Tom
    9 hours ago













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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









17












$begingroup$

I think this is a play on something around




pi ($pi$) and tau ($tau$) both circle ratios.




I'm his double but he has twice more legs than me




$tau = 2pi$ but $pi$ has twice the number of legs of $tau$.







share|improve this answer









$endgroup$









  • 1




    $begingroup$
    That was even faster than I'm allowed to accept it
    $endgroup$
    – HerrSerker
    9 hours ago






  • 1




    $begingroup$
    Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
    $endgroup$
    – Tom
    9 hours ago


















17












$begingroup$

I think this is a play on something around




pi ($pi$) and tau ($tau$) both circle ratios.




I'm his double but he has twice more legs than me




$tau = 2pi$ but $pi$ has twice the number of legs of $tau$.







share|improve this answer









$endgroup$









  • 1




    $begingroup$
    That was even faster than I'm allowed to accept it
    $endgroup$
    – HerrSerker
    9 hours ago






  • 1




    $begingroup$
    Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
    $endgroup$
    – Tom
    9 hours ago
















17












17








17





$begingroup$

I think this is a play on something around




pi ($pi$) and tau ($tau$) both circle ratios.




I'm his double but he has twice more legs than me




$tau = 2pi$ but $pi$ has twice the number of legs of $tau$.







share|improve this answer









$endgroup$



I think this is a play on something around




pi ($pi$) and tau ($tau$) both circle ratios.




I'm his double but he has twice more legs than me




$tau = 2pi$ but $pi$ has twice the number of legs of $tau$.








share|improve this answer












share|improve this answer



share|improve this answer










answered 9 hours ago









TomTom

31k3106181




31k3106181








  • 1




    $begingroup$
    That was even faster than I'm allowed to accept it
    $endgroup$
    – HerrSerker
    9 hours ago






  • 1




    $begingroup$
    Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
    $endgroup$
    – Tom
    9 hours ago
















  • 1




    $begingroup$
    That was even faster than I'm allowed to accept it
    $endgroup$
    – HerrSerker
    9 hours ago






  • 1




    $begingroup$
    Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
    $endgroup$
    – Tom
    9 hours ago










1




1




$begingroup$
That was even faster than I'm allowed to accept it
$endgroup$
– HerrSerker
9 hours ago




$begingroup$
That was even faster than I'm allowed to accept it
$endgroup$
– HerrSerker
9 hours ago




1




1




$begingroup$
Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
$endgroup$
– Tom
9 hours ago






$begingroup$
Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
$endgroup$
– Tom
9 hours ago












HerrSerker is a new contributor. Be nice, and check out our Code of Conduct.










draft saved

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HerrSerker is a new contributor. Be nice, and check out our Code of Conduct.













HerrSerker is a new contributor. Be nice, and check out our Code of Conduct.












HerrSerker is a new contributor. Be nice, and check out our Code of Conduct.
















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