Setting variable with default value behaves differently when preceding a command?
Setting a variable with a fallback default value works...as long as we're using the variable in a subsequent command:
$ unset APP_ENV
$ echo $APP_ENV
$ APP_ENV="${APP_ENV:-production}"; echo $APP_ENV
production
$ APP_ENV=staging
$ APP_ENV="${APP_ENV:-production}"; echo $APP_ENV
staging
However, trying to set the variable immediately preceding the command that uses it behaves differently:
$ unset APP_ENV
$ echo $APP_ENV
$ APP_ENV="${APP_ENV:-production}" echo $APP_ENV
$ APP_ENV=staging
$ APP_ENV="${APP_ENV:-production}" echo $APP_ENV
staging
Why the second example behaves differently?
bash shell-script variable
add a comment |
Setting a variable with a fallback default value works...as long as we're using the variable in a subsequent command:
$ unset APP_ENV
$ echo $APP_ENV
$ APP_ENV="${APP_ENV:-production}"; echo $APP_ENV
production
$ APP_ENV=staging
$ APP_ENV="${APP_ENV:-production}"; echo $APP_ENV
staging
However, trying to set the variable immediately preceding the command that uses it behaves differently:
$ unset APP_ENV
$ echo $APP_ENV
$ APP_ENV="${APP_ENV:-production}" echo $APP_ENV
$ APP_ENV=staging
$ APP_ENV="${APP_ENV:-production}" echo $APP_ENV
staging
Why the second example behaves differently?
bash shell-script variable
add a comment |
Setting a variable with a fallback default value works...as long as we're using the variable in a subsequent command:
$ unset APP_ENV
$ echo $APP_ENV
$ APP_ENV="${APP_ENV:-production}"; echo $APP_ENV
production
$ APP_ENV=staging
$ APP_ENV="${APP_ENV:-production}"; echo $APP_ENV
staging
However, trying to set the variable immediately preceding the command that uses it behaves differently:
$ unset APP_ENV
$ echo $APP_ENV
$ APP_ENV="${APP_ENV:-production}" echo $APP_ENV
$ APP_ENV=staging
$ APP_ENV="${APP_ENV:-production}" echo $APP_ENV
staging
Why the second example behaves differently?
bash shell-script variable
Setting a variable with a fallback default value works...as long as we're using the variable in a subsequent command:
$ unset APP_ENV
$ echo $APP_ENV
$ APP_ENV="${APP_ENV:-production}"; echo $APP_ENV
production
$ APP_ENV=staging
$ APP_ENV="${APP_ENV:-production}"; echo $APP_ENV
staging
However, trying to set the variable immediately preceding the command that uses it behaves differently:
$ unset APP_ENV
$ echo $APP_ENV
$ APP_ENV="${APP_ENV:-production}" echo $APP_ENV
$ APP_ENV=staging
$ APP_ENV="${APP_ENV:-production}" echo $APP_ENV
staging
Why the second example behaves differently?
bash shell-script variable
bash shell-script variable
edited 11 hours ago
Rui F Ribeiro
41.3k1481140
41.3k1481140
asked Jul 16 '15 at 16:11
EvanKEvanK
1214
1214
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Let's replace the semicolon with a newline to make the first version clearer:
APP_ENV="${APP_ENV:-production}"
echo $APP_ENV
Line 1 executes completely before the shell looks at line 2.
Line 1 causes $APP_ENV
to be set equal to production
.
Line 2 accesses that variable and provided its value to the echo
command.
Now the single-command version:
APP_ENV="${APP_ENV:-production}" echo $APP_ENV
First the shell expands the command line according to parameter expansion and (not applicable in this case) other kinds of substitution. Since the current value of $APP_ENV
is empty, that expands to:
APP_ENV="${:-production}" echo
After performing expansions, it sets the variable $APP_ENV
to production
for this command invocation only, and invokes echo ""
with that value. But echo
doesn not care that it got an environment varible $APP_ENV
in its environment. It only looks at its command line, which consists of nothing. So it echoes nothing.
Here's how you prove that $APP_ENV
really is being set in this case:
$ APP_ENV="${APP_ENV:-production}" env |grep APP_ENV
APP_ENV=production
In summary, your second example does not do what you thought it would do because the parameter expansion happens too soon.
Thank you for breaking that down, it makes perfect sense to me now!
– EvanK
Jul 16 '15 at 18:32
add a comment |
The second form is behaving differently because you're missing a ;
after the variable initialization:
APP_ENV="${APP_ENV:-production}" echo $APP_ENV
should be:
APP_ENV="${APP_ENV:-production}"; echo $APP_ENV
^ semicolon that's missing
Fix that first, then restate your question.
2
Yes, it's a different command without the semicolon. That's the point of the question. The question is valid as it stands.
– Celada
Jul 16 '15 at 16:43
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "106"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f216498%2fsetting-variable-with-default-value-behaves-differently-when-preceding-a-command%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Let's replace the semicolon with a newline to make the first version clearer:
APP_ENV="${APP_ENV:-production}"
echo $APP_ENV
Line 1 executes completely before the shell looks at line 2.
Line 1 causes $APP_ENV
to be set equal to production
.
Line 2 accesses that variable and provided its value to the echo
command.
Now the single-command version:
APP_ENV="${APP_ENV:-production}" echo $APP_ENV
First the shell expands the command line according to parameter expansion and (not applicable in this case) other kinds of substitution. Since the current value of $APP_ENV
is empty, that expands to:
APP_ENV="${:-production}" echo
After performing expansions, it sets the variable $APP_ENV
to production
for this command invocation only, and invokes echo ""
with that value. But echo
doesn not care that it got an environment varible $APP_ENV
in its environment. It only looks at its command line, which consists of nothing. So it echoes nothing.
Here's how you prove that $APP_ENV
really is being set in this case:
$ APP_ENV="${APP_ENV:-production}" env |grep APP_ENV
APP_ENV=production
In summary, your second example does not do what you thought it would do because the parameter expansion happens too soon.
Thank you for breaking that down, it makes perfect sense to me now!
– EvanK
Jul 16 '15 at 18:32
add a comment |
Let's replace the semicolon with a newline to make the first version clearer:
APP_ENV="${APP_ENV:-production}"
echo $APP_ENV
Line 1 executes completely before the shell looks at line 2.
Line 1 causes $APP_ENV
to be set equal to production
.
Line 2 accesses that variable and provided its value to the echo
command.
Now the single-command version:
APP_ENV="${APP_ENV:-production}" echo $APP_ENV
First the shell expands the command line according to parameter expansion and (not applicable in this case) other kinds of substitution. Since the current value of $APP_ENV
is empty, that expands to:
APP_ENV="${:-production}" echo
After performing expansions, it sets the variable $APP_ENV
to production
for this command invocation only, and invokes echo ""
with that value. But echo
doesn not care that it got an environment varible $APP_ENV
in its environment. It only looks at its command line, which consists of nothing. So it echoes nothing.
Here's how you prove that $APP_ENV
really is being set in this case:
$ APP_ENV="${APP_ENV:-production}" env |grep APP_ENV
APP_ENV=production
In summary, your second example does not do what you thought it would do because the parameter expansion happens too soon.
Thank you for breaking that down, it makes perfect sense to me now!
– EvanK
Jul 16 '15 at 18:32
add a comment |
Let's replace the semicolon with a newline to make the first version clearer:
APP_ENV="${APP_ENV:-production}"
echo $APP_ENV
Line 1 executes completely before the shell looks at line 2.
Line 1 causes $APP_ENV
to be set equal to production
.
Line 2 accesses that variable and provided its value to the echo
command.
Now the single-command version:
APP_ENV="${APP_ENV:-production}" echo $APP_ENV
First the shell expands the command line according to parameter expansion and (not applicable in this case) other kinds of substitution. Since the current value of $APP_ENV
is empty, that expands to:
APP_ENV="${:-production}" echo
After performing expansions, it sets the variable $APP_ENV
to production
for this command invocation only, and invokes echo ""
with that value. But echo
doesn not care that it got an environment varible $APP_ENV
in its environment. It only looks at its command line, which consists of nothing. So it echoes nothing.
Here's how you prove that $APP_ENV
really is being set in this case:
$ APP_ENV="${APP_ENV:-production}" env |grep APP_ENV
APP_ENV=production
In summary, your second example does not do what you thought it would do because the parameter expansion happens too soon.
Let's replace the semicolon with a newline to make the first version clearer:
APP_ENV="${APP_ENV:-production}"
echo $APP_ENV
Line 1 executes completely before the shell looks at line 2.
Line 1 causes $APP_ENV
to be set equal to production
.
Line 2 accesses that variable and provided its value to the echo
command.
Now the single-command version:
APP_ENV="${APP_ENV:-production}" echo $APP_ENV
First the shell expands the command line according to parameter expansion and (not applicable in this case) other kinds of substitution. Since the current value of $APP_ENV
is empty, that expands to:
APP_ENV="${:-production}" echo
After performing expansions, it sets the variable $APP_ENV
to production
for this command invocation only, and invokes echo ""
with that value. But echo
doesn not care that it got an environment varible $APP_ENV
in its environment. It only looks at its command line, which consists of nothing. So it echoes nothing.
Here's how you prove that $APP_ENV
really is being set in this case:
$ APP_ENV="${APP_ENV:-production}" env |grep APP_ENV
APP_ENV=production
In summary, your second example does not do what you thought it would do because the parameter expansion happens too soon.
answered Jul 16 '15 at 16:50
CeladaCelada
31k46584
31k46584
Thank you for breaking that down, it makes perfect sense to me now!
– EvanK
Jul 16 '15 at 18:32
add a comment |
Thank you for breaking that down, it makes perfect sense to me now!
– EvanK
Jul 16 '15 at 18:32
Thank you for breaking that down, it makes perfect sense to me now!
– EvanK
Jul 16 '15 at 18:32
Thank you for breaking that down, it makes perfect sense to me now!
– EvanK
Jul 16 '15 at 18:32
add a comment |
The second form is behaving differently because you're missing a ;
after the variable initialization:
APP_ENV="${APP_ENV:-production}" echo $APP_ENV
should be:
APP_ENV="${APP_ENV:-production}"; echo $APP_ENV
^ semicolon that's missing
Fix that first, then restate your question.
2
Yes, it's a different command without the semicolon. That's the point of the question. The question is valid as it stands.
– Celada
Jul 16 '15 at 16:43
add a comment |
The second form is behaving differently because you're missing a ;
after the variable initialization:
APP_ENV="${APP_ENV:-production}" echo $APP_ENV
should be:
APP_ENV="${APP_ENV:-production}"; echo $APP_ENV
^ semicolon that's missing
Fix that first, then restate your question.
2
Yes, it's a different command without the semicolon. That's the point of the question. The question is valid as it stands.
– Celada
Jul 16 '15 at 16:43
add a comment |
The second form is behaving differently because you're missing a ;
after the variable initialization:
APP_ENV="${APP_ENV:-production}" echo $APP_ENV
should be:
APP_ENV="${APP_ENV:-production}"; echo $APP_ENV
^ semicolon that's missing
Fix that first, then restate your question.
The second form is behaving differently because you're missing a ;
after the variable initialization:
APP_ENV="${APP_ENV:-production}" echo $APP_ENV
should be:
APP_ENV="${APP_ENV:-production}"; echo $APP_ENV
^ semicolon that's missing
Fix that first, then restate your question.
edited Jul 17 '15 at 1:30
cuonglm
105k25207305
105k25207305
answered Jul 16 '15 at 16:18
David FavorDavid Favor
36314
36314
2
Yes, it's a different command without the semicolon. That's the point of the question. The question is valid as it stands.
– Celada
Jul 16 '15 at 16:43
add a comment |
2
Yes, it's a different command without the semicolon. That's the point of the question. The question is valid as it stands.
– Celada
Jul 16 '15 at 16:43
2
2
Yes, it's a different command without the semicolon. That's the point of the question. The question is valid as it stands.
– Celada
Jul 16 '15 at 16:43
Yes, it's a different command without the semicolon. That's the point of the question. The question is valid as it stands.
– Celada
Jul 16 '15 at 16:43
add a comment |
Thanks for contributing an answer to Unix & Linux Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f216498%2fsetting-variable-with-default-value-behaves-differently-when-preceding-a-command%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown