Memory between argv and top stack x86_64
Reading some articles on the memory layout of a program in memory, 3GiB-1 is the top of the stack in x86_32 and contains a NULL dword, preceded by the program name, preceded by env and argv.
This means (or should mean) I can reference 0xbfffffff - 4, - 5, ... and get the program name and so on.
Compiling even the following code for x86_64, it gets SIGSEGVd.
unsigned long *stack_top = (unsigned long*)0x7ffffffffff;
char *pname = (char *)(stack_top) - sizeof(void*);
printf("%cn", *pname);
And argv is at 0x7fff3e53cc18. Why?
virtual-memory stack
add a comment |
Reading some articles on the memory layout of a program in memory, 3GiB-1 is the top of the stack in x86_32 and contains a NULL dword, preceded by the program name, preceded by env and argv.
This means (or should mean) I can reference 0xbfffffff - 4, - 5, ... and get the program name and so on.
Compiling even the following code for x86_64, it gets SIGSEGVd.
unsigned long *stack_top = (unsigned long*)0x7ffffffffff;
char *pname = (char *)(stack_top) - sizeof(void*);
printf("%cn", *pname);
And argv is at 0x7fff3e53cc18. Why?
virtual-memory stack
You're not telling what system you're using. If that's Linux, you can get the actual layout of the virtual memory of a process from/proc/PID/maps
, and the address where argv0, env, etc from/proc/PID/stat
./proc/self/
gets you the current process. See the 2nd part here. Please edit the system details and your actual problem into your question.
– mosvy
6 hours ago
add a comment |
Reading some articles on the memory layout of a program in memory, 3GiB-1 is the top of the stack in x86_32 and contains a NULL dword, preceded by the program name, preceded by env and argv.
This means (or should mean) I can reference 0xbfffffff - 4, - 5, ... and get the program name and so on.
Compiling even the following code for x86_64, it gets SIGSEGVd.
unsigned long *stack_top = (unsigned long*)0x7ffffffffff;
char *pname = (char *)(stack_top) - sizeof(void*);
printf("%cn", *pname);
And argv is at 0x7fff3e53cc18. Why?
virtual-memory stack
Reading some articles on the memory layout of a program in memory, 3GiB-1 is the top of the stack in x86_32 and contains a NULL dword, preceded by the program name, preceded by env and argv.
This means (or should mean) I can reference 0xbfffffff - 4, - 5, ... and get the program name and so on.
Compiling even the following code for x86_64, it gets SIGSEGVd.
unsigned long *stack_top = (unsigned long*)0x7ffffffffff;
char *pname = (char *)(stack_top) - sizeof(void*);
printf("%cn", *pname);
And argv is at 0x7fff3e53cc18. Why?
virtual-memory stack
virtual-memory stack
edited 9 hours ago
ctrl-alt-delor
11.9k42260
11.9k42260
asked 10 hours ago
norakenorake
133
133
You're not telling what system you're using. If that's Linux, you can get the actual layout of the virtual memory of a process from/proc/PID/maps
, and the address where argv0, env, etc from/proc/PID/stat
./proc/self/
gets you the current process. See the 2nd part here. Please edit the system details and your actual problem into your question.
– mosvy
6 hours ago
add a comment |
You're not telling what system you're using. If that's Linux, you can get the actual layout of the virtual memory of a process from/proc/PID/maps
, and the address where argv0, env, etc from/proc/PID/stat
./proc/self/
gets you the current process. See the 2nd part here. Please edit the system details and your actual problem into your question.
– mosvy
6 hours ago
You're not telling what system you're using. If that's Linux, you can get the actual layout of the virtual memory of a process from
/proc/PID/maps
, and the address where argv0, env, etc from /proc/PID/stat
. /proc/self/
gets you the current process. See the 2nd part here. Please edit the system details and your actual problem into your question.– mosvy
6 hours ago
You're not telling what system you're using. If that's Linux, you can get the actual layout of the virtual memory of a process from
/proc/PID/maps
, and the address where argv0, env, etc from /proc/PID/stat
. /proc/self/
gets you the current process. See the 2nd part here. Please edit the system details and your actual problem into your question.– mosvy
6 hours ago
add a comment |
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You're not telling what system you're using. If that's Linux, you can get the actual layout of the virtual memory of a process from
/proc/PID/maps
, and the address where argv0, env, etc from/proc/PID/stat
./proc/self/
gets you the current process. See the 2nd part here. Please edit the system details and your actual problem into your question.– mosvy
6 hours ago