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I have a .zip created on a Windows machine (outside of my control). The zip file contains paths that I need to preserve when I unzip.

However, when I unzip, all files end up like:
unzip_dir/windowpathseparatormyfile.ext

I've tried both, with and without -j option.
My issue is that I need that path information under windowpathseparator. I need that file structure to be created when I unzip.

I can mv the file and flip the to / easily enough in a script, but then there are errors that the destination path directories do not exist. My workaround for now is to mkdir -p the paths (after converting to /) and then cp the files to those paths.

But there are a lot of files, and these redundant mkdir -p statements for every file really slows things down.

Is there any more elegant way to convert a zip file with Windows paths to Linux paths?

I think something went wrong with the creation of the zip file, because when I create a zip file on Windows is has (portable) forward slashes:

zip.exe -r pip pip

updating: pip/ (244 bytes security) (stored 0%)

  adding: pip/pip.log (164 bytes security) (deflated 66%)

But now that you have the files with file names that contain "paths" with backslashes, you can run the following program in unzip_dir:

#! /usr/bin/env python



# already created directories, walk works topdown, so a child dir

# never creates a directory if there is a parent dir with a file.

made_dirs = set()



for root, dir_names, file_names in os.walk('.'):

    for file_name in file_names:

        if '\' not in file_name:

            continue

        alt_file_name = file_name.replace('\', '/')

        if alt_file_name.startswith('/'):

            alt_file_name = alt_file_name[1:]  # cut of starting dir separator

        alt_dir_name, alt_base_name = alt_file_name.rsplit('/', 1)

        print 'alt_dir', alt_dir_name

        full_dir_name = os.path.join(root, alt_dir_name)

        if full_dir_name not in made_dirs:

            os.makedirs(full_dir_name)  # only create if not done yet

            made_dirs.add(full_dir_name)

        os.rename(os.path.join(root, file_name),

                  os.path.join(root, alt_file_name))

This handles files in any directory under the directory from where the program is started. Given the problem that you describe, the unzip_dir probably doesn't have any subdirectories to start with, and the program could just walk over the files in the current directory only.

Use 7z rn to rename the files within the archive so that they have a forward slash. Then when you extract the archive, directories will be created.

To rename the files, list the paths of the files within the archive containing slashes, and generate a list of replacement strings that change the backslash to a slash using awk, for example.

7z rn windows.zip $(7z l windows.zip | grep '\' | awk '{ print $6, gensub(/\/, "/", "g", $6); }' | paste -s)

This is just an update of @anton's answer which includes fixes by @madmuffin (FileExistsError: [Errno 17] File exists and missing os module import), a fix for python 3 (SyntaxError: Missing parentheses in call to 'print') and a fix for the missing errno module import (NameError: name 'errno' is not defined).

#! /usr/bin/env python



import os

import errno



# already created directories, walk works topdown, so a child dir

# never creates a directory if there is a parent dir with a file.

made_dirs = set()



for root, dir_names, file_names in os.walk('.'):

    for file_name in file_names:

        if '\' not in file_name:

            continue

        alt_file_name = file_name.replace('\', '/')

        if alt_file_name.startswith('/'):

            alt_file_name = alt_file_name[1:]  # cut of starting dir separator

        alt_dir_name, alt_base_name = alt_file_name.rsplit('/', 1)

        print('alt_dir', alt_dir_name)

        full_dir_name = os.path.join(root, alt_dir_name)

        if full_dir_name not in made_dirs:

            try:

                os.makedirs(full_dir_name)

            except OSError as exc:

                if exc.errno == errno.EEXIST and os.path.isdir(full_dir_name):

                    # the pass already exists and is a folder, let's just ignore it

                    pass

                else:

                    raise 

            made_dirs.add(full_dir_name)

        os.rename(os.path.join(root, file_name),

                  os.path.join(root, alt_file_name))

Had to make a few changes to @xn.'s answer for Mac. This worked for me:

1. brew install gawk


2. 7z rn windows.zip $(7z l windows.zip | grep '\' | gawk '{ print $6, gensub(/\/, "/", "g", $6); }' | paste -s -)