Compiling unistd.h's `crypt` on Ubuntu 18.10
When I try to compile the following code,
#include <unistd.h>
#include <stdio.h>
int main()
{
printf("%s", crypt("foobar", "sa"));
}
I'm getting the error
./crack.c: In function ‘main’:
./crack.c:10:15: warning: implicit declaration of function ‘crypt’; did you mean ‘chroot’? [-Wimplicit-function-declaration]
printf("%s", crypt("foobar", "sa"));
^~~~~
chroot
./crack.c:10:11: warning: format ‘%s’ expects argument of type ‘char *’, but argument 2 has type ‘int’ [-Wformat=]
printf("%s", crypt("foobar", "sa"));
~^ ~~~~~~~~~~~~~~~~~~~~~
%d
Out of desperation, I've tried adding this.
#define _XOPEN_VERSION 700
#define _POSIX_VERSION 200809L
#define __USE_MISC 1
This is a direct copy from the man page of crypt.h
though,
#define _XOPEN_SOURCE /* See feature_test_macros(7) */
#include <unistd.h>
char *crypt(const char *key, const char *salt);
ubuntu compiling gcc clang crypt
add a comment |
When I try to compile the following code,
#include <unistd.h>
#include <stdio.h>
int main()
{
printf("%s", crypt("foobar", "sa"));
}
I'm getting the error
./crack.c: In function ‘main’:
./crack.c:10:15: warning: implicit declaration of function ‘crypt’; did you mean ‘chroot’? [-Wimplicit-function-declaration]
printf("%s", crypt("foobar", "sa"));
^~~~~
chroot
./crack.c:10:11: warning: format ‘%s’ expects argument of type ‘char *’, but argument 2 has type ‘int’ [-Wformat=]
printf("%s", crypt("foobar", "sa"));
~^ ~~~~~~~~~~~~~~~~~~~~~
%d
Out of desperation, I've tried adding this.
#define _XOPEN_VERSION 700
#define _POSIX_VERSION 200809L
#define __USE_MISC 1
This is a direct copy from the man page of crypt.h
though,
#define _XOPEN_SOURCE /* See feature_test_macros(7) */
#include <unistd.h>
char *crypt(const char *key, const char *salt);
ubuntu compiling gcc clang crypt
add a comment |
When I try to compile the following code,
#include <unistd.h>
#include <stdio.h>
int main()
{
printf("%s", crypt("foobar", "sa"));
}
I'm getting the error
./crack.c: In function ‘main’:
./crack.c:10:15: warning: implicit declaration of function ‘crypt’; did you mean ‘chroot’? [-Wimplicit-function-declaration]
printf("%s", crypt("foobar", "sa"));
^~~~~
chroot
./crack.c:10:11: warning: format ‘%s’ expects argument of type ‘char *’, but argument 2 has type ‘int’ [-Wformat=]
printf("%s", crypt("foobar", "sa"));
~^ ~~~~~~~~~~~~~~~~~~~~~
%d
Out of desperation, I've tried adding this.
#define _XOPEN_VERSION 700
#define _POSIX_VERSION 200809L
#define __USE_MISC 1
This is a direct copy from the man page of crypt.h
though,
#define _XOPEN_SOURCE /* See feature_test_macros(7) */
#include <unistd.h>
char *crypt(const char *key, const char *salt);
ubuntu compiling gcc clang crypt
When I try to compile the following code,
#include <unistd.h>
#include <stdio.h>
int main()
{
printf("%s", crypt("foobar", "sa"));
}
I'm getting the error
./crack.c: In function ‘main’:
./crack.c:10:15: warning: implicit declaration of function ‘crypt’; did you mean ‘chroot’? [-Wimplicit-function-declaration]
printf("%s", crypt("foobar", "sa"));
^~~~~
chroot
./crack.c:10:11: warning: format ‘%s’ expects argument of type ‘char *’, but argument 2 has type ‘int’ [-Wformat=]
printf("%s", crypt("foobar", "sa"));
~^ ~~~~~~~~~~~~~~~~~~~~~
%d
Out of desperation, I've tried adding this.
#define _XOPEN_VERSION 700
#define _POSIX_VERSION 200809L
#define __USE_MISC 1
This is a direct copy from the man page of crypt.h
though,
#define _XOPEN_SOURCE /* See feature_test_macros(7) */
#include <unistd.h>
char *crypt(const char *key, const char *salt);
ubuntu compiling gcc clang crypt
ubuntu compiling gcc clang crypt
asked 2 mins ago
Evan CarrollEvan Carroll
5,504114381
5,504114381
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add a comment |
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