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With Bash and Dash, you can check for an empty directory using just the shell
(ignore dotfiles to keep things simple):

set *

if [ -e "$1" ]

then

  echo 'not empty'

else

  echo 'empty'

fi

However I recently learned that Zsh fails spectacularly in this case:

% set *

zsh: no matches found: *



% echo "$? $#"

1 0

So not only does the set command fail, but it doesn't even set $@. I suppose
I could test if $# is 0, but it appears that Zsh even stops execution:

% { set *; echo 2; }

zsh: no matches found: *

Compare with Bash and Dash:

$ { set *; echo 2; }

2

Can this be done in a way that works in bash, dash and zsh?

While zsh's default behaviour is to give an error, this is controlled by the nomatch option. You can unset the option to leave the * in place the way that bash and dash do:

setopt -o nonomatch

While that command won't work in either of the others, you can just ignore that:

setopt -o nonomatch 2>/dev/null || true ; set *

This runs setopt on zsh, and suppresses the error output (2>/dev/null) and return code (|| true) of the failed command on the others.

As written it's problematic if there is a file, for example, -e: then you will run set -e and change the shell options to terminate whenever a command fails; there are worse outcomes if you're creative. set -- * will be safer and prevent the option changes.

Zsh's syntax is not compatible with sh. It's close enough to look like sh, but not close enough that you can take sh code and run it unchanged.

If you want to run sh code in zsh, for example because you have an sh function or snippet written for sh that you want to use in a zsh script, you can use the emulate builtin. For example, to source a file written for sh in a zsh script:

emulate sh -c 'source /path/to/file.sh'

To write a function or script in sh syntax and make it possible to run it in zsh, put this near the beginning:

emulate -L sh 2>/dev/null || true

In sh syntax, zsh supports all POSIX constructs (it's about as POSIX compliant as bash --posix or ksh93 or mksh). It also supports some ksh and bash extensions such as arrays (0-indexed in ksh, in bash and under emulate sh, but 1-indexed in native zsh) and [[ … ]]. If you want POSIX sh plus ksh globs, use emulate … ksh … instead of emulate … sh …, and add if [[ -n $BASH ]]; then shopt -s extglob; fi for the sake of bash (note that this is not local to the script/function).

The native zsh way to enumerate all the entries in a directory except . and .. is

set -- *(DN)

This uses the glob qualifiers D to include dot files and N to produce an empty list if there are no matches.

The native zsh way to enumerate all the entries in a directory except . and .. is a lot more complicated. You need to list dot files, and if you're listing files in the current directory or in a path that isn't guaranteed to be absolute you need take care in case there is a file name that begins with a dash. Here's one way to do it, by using the patterns ..?* .[!.]* * to list all files except . and .. and removing unexpanded patterns.

set -- ..?*

if [ "$#" -eq 1 ] && ! [ -e "$1" ] && ! [ -L "$1" ]; then shift; fi

set -- .[!.]* "$@"

if [ "$#" -eq 1 ] && ! [ -e "$1" ] && ! [ -L "$1" ]; then shift; fi

set -- * "$@"

if [ "$#" -eq 1 ] && ! [ -e "$1" ] && ! [ -L "$1" ]; then shift; fi

If all you want to do is to test whether a directory is empty, there's a much easier way.

if ls -A /path/to/directory/ | grep -q '^'; then

  echo "/path/to/directory is not empty"

else

  echo "/path/to/directory is empty"

fi

Most portable way would be via set and globstar for all POSIX-compliant shells. This has been shown in Gilles's answer on a related question. I've adapted the method slightly into a function:

rm -rf empty_dir/

mkdir empty_dir/

pwd

cd empty_dir/

pwd

dir_empty(){



    # https://stackoverflow.com/a/9911082/3701431

    if [ -n "$ZSH_VERSION" ]; then

        # https://unix.stackexchange.com/a/310553/85039

        setopt +o nomatch 

    fi    



    set -- * .*

    echo "$@"

    for i; do

        [ "$i" = "." ] || [ "$i" = ".." ] && continue

        [ -e "$i" ] && echo "Not empty" && return 1

    done

    echo "Empty" && return 0

}

dir_empty

touch  '*'

dir_empty

The big problem with zsh is that while ksh and bash behave in more or less consistent manner - that is when we do set * .* you will have 3 positional parameters * . .. in really empty directory - in zsh you will get * .* as positional parameters. Luckily at least for i ; do ... done to iterate over positional parameters works consistently. The rest is just iteration and check for existence of the filename, with . and .. skipped.

Try it online in ksh!

Try it online in zsh!

There are several problems with that

set *

if [ -e "$1" ]

then

  echo 'not empty'

else

  echo 'empty'

fi

code:

• if the nullglob option (from zsh but now supported by most other shells) is enabled, set * becomes set which lists all the shell variables (and functions in some shells)


• if the first non-hidden file has a name that starts with - or +, it will be treated as an option by set. Those two issues can be fixed by using set -- * instead.


• 
  * expands only non-hidden files, so it's not a test whether the directory is empty or not but whether it contains non-hidden files or not. With some shells, you can use a dotglob or globdot option of play with a FIGNORE special variable to work around that.


• 
  [ -e "$1" ] tests whether a stat() system call succeeds or not. If the first file a symlink to an inaccessible location, that will return false. You shouldn't need to stat() (not even lstat()) any file to know whether a directory is empty or not, only check that it has some content.


• 
  * expansion involves opening the current directory, retrieving all the entries, storing all the non-hidden one and sorting them, which is also quite inefficient.

The most efficient way to check if a directory is non-empty (has any entry other than . and ..) in zsh is with the F glob qualifier (F for full):

if [ .(NF) ]; then

  echo . is not empty

fi

N is the nullglob glob qualifier. So .(NF) expands to . if . is full and nothing otherwise.

After the lstat() on the directory, if zsh finds it has a link-count greater than 2, then that means it has at least one subdirectory so is not empty, so we don't even need to open that directory. Otherwise, zsh opens the directory, and stops at the first entry that is neither . nor .. without having to read, store nor sort everything.

With POSIX shells (zsh only behaves (more) POSIXly in sh emulation), it is very awkward to check that a directory is non-empty with globs only.

One way is with:

set .[!.]* '.[!.]'[*] .[.]?* [*] *

if [ "$#$1$2$3$4$5" = '5.[!.]*.[!.][*].[.]?*[*]*' ]; then

  echo empty

else

  echo not empty

fi

The idea is that in POSIX shell (a misfeature introduced by the Bourne shell in the late 70s) when a glob doesn't match, it is left unexpanded. So with set -- * if we get $1 == *, we don't know whether it was because there was no match or whether there was a file called *.

Your (flawed) approach to work around that was to use [ -e "$1" ]. Here instead, we use set -- [*] *. That allows to disambiguate the two cases, because if there is no file, the above will stay [*] *, and if there is a file called *, that becomes * *. We do something similar for hidden files. That is a bit awkward because of yet another misfeature of the Bourne shell (also fixed by zsh, the Forsyth shell, pdksh and fish) whereby the expansion of .* does include the special (pseudo-)entries . and .. when reported by readdir().

So to make it work in all those shells, you could do:

cwd_empty()

  if [ -n "$ZSH_VERSION" ]; then

    eval '! [ .(NF) ]'

  else

    set .[!.]* '.[!.]'[*] .[.]?* [*] *

    [ "$#$1$2$3$4$5" = '5.[!.]*.[!.][*].[.]?*[*]*' ]

  fi