Number of occurences of letters in a word?
I would like to find out the number of occurrences of each of the alphabets in a word. Eg
input
aabbbddd
output
a@2 b@3 c@0 d@3
How can I perform this using shell script?
bash shell shell-script
add a comment |
I would like to find out the number of occurrences of each of the alphabets in a word. Eg
input
aabbbddd
output
a@2 b@3 c@0 d@3
How can I perform this using shell script?
bash shell shell-script
1
Is your input sorted by default?
– cuonglm
Nov 17 '14 at 6:28
Please clarify your question. Do you need c@0, since that is not a letter within the word?
– slm♦
Nov 17 '14 at 6:35
add a comment |
I would like to find out the number of occurrences of each of the alphabets in a word. Eg
input
aabbbddd
output
a@2 b@3 c@0 d@3
How can I perform this using shell script?
bash shell shell-script
I would like to find out the number of occurrences of each of the alphabets in a word. Eg
input
aabbbddd
output
a@2 b@3 c@0 d@3
How can I perform this using shell script?
bash shell shell-script
bash shell shell-script
edited Nov 17 '14 at 6:34
slm♦
249k66522680
249k66522680
asked Nov 17 '14 at 6:14
Rakesh R NairRakesh R Nair
901511
901511
1
Is your input sorted by default?
– cuonglm
Nov 17 '14 at 6:28
Please clarify your question. Do you need c@0, since that is not a letter within the word?
– slm♦
Nov 17 '14 at 6:35
add a comment |
1
Is your input sorted by default?
– cuonglm
Nov 17 '14 at 6:28
Please clarify your question. Do you need c@0, since that is not a letter within the word?
– slm♦
Nov 17 '14 at 6:35
1
1
Is your input sorted by default?
– cuonglm
Nov 17 '14 at 6:28
Is your input sorted by default?
– cuonglm
Nov 17 '14 at 6:28
Please clarify your question. Do you need c@0, since that is not a letter within the word?
– slm♦
Nov 17 '14 at 6:35
Please clarify your question. Do you need c@0, since that is not a letter within the word?
– slm♦
Nov 17 '14 at 6:35
add a comment |
3 Answers
3
active
oldest
votes
These solutions are case-insensitive:
start cmd:> echo aabbbddd |
awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
END {for (key in a) print key ": " a[key];}'
a: 2
b: 3
d: 3
Or for the complete alphabet:
start cmd:> echo Aabbbddd |
awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
END {chars="abcdefghijklmnopqrstuvwxyz";
for (i=1;i<27;i++) { key=substr(chars,i,1);print key ": " a[key]};}'
a: 2
b: 3
c:
d: 3
e:
f:
g:
h:
i:
j:
k:
l:
m:
n:
o:
p:
q:
r:
s:
t:
u:
v:
w:
x:
y:
z:
1
The output is missingc
as OP's desired output.
– cuonglm
Nov 17 '14 at 6:31
add a comment |
You could use sed
, uniq
, and sort
:
$ echo -n "aabbbddd" | sed 's/(.)/1n/g'| sort | uniq -c
2 a
3 b
3 d
The above uses sed
to take each character and replace it with itself + a newline (n
). Now with each character on a newline (and sorted) you can use uniq -c
to count the characters.
NOTE: This method will not show any of the characters in between that have zero occurrences.
Alternatively showing each letter's count
$ s="aabbbddd"; for i in {a..z}; do
v=$(echo -n "$s" | grep -oi $i | wc -l); echo "$i : $v"; done
a : 2
b : 3
c : 0
d : 3
e : 0
f : 0
g : 0
h : 0
i : 0
j : 0
k : 0
l : 0
m : 0
n : 0
o : 0
p : 0
q : 0
r : 0
s : 0
t : 0
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0
This works by looping through all the letters of the alphabet:
for i in {a..z}; do .... ; done
Each iteration of the loop we grep through the string looking for a specific character, and use the -o
option of grep
to only return these matches. We then use wc -l
to count how many occurrences of each letter we found, and store it in variable $v
. We then display each iteration:
echo "$i : $v"
NOTE: This approach can handle the strings being out of order.
add a comment |
Using only the shell (faster for short strings):
#! /bin/bash -
input=${*:-'aabbbddd'}
tmp=$input
arr=()
maxlen=0
maxchar=''
while ((${#tmp})); do
firstchar=${tmp:0:1}
next=${tmp//"$firstchar"}
len=$((${#tmp}-${#next}))
arr+=("$firstchar: $len")
if ((maxlen<len)); then
maxlen=$len
maxchar=$firstchar
fi
tmp=$next
done
printf '%sn' "${arr[@]}"
echo "The char "$maxchar" appear $maxlen times in "$input""
Called as:
$ ./script
a@2 b@3 d@3
The char "b" appear 3 times in "aabbbddd"
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
These solutions are case-insensitive:
start cmd:> echo aabbbddd |
awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
END {for (key in a) print key ": " a[key];}'
a: 2
b: 3
d: 3
Or for the complete alphabet:
start cmd:> echo Aabbbddd |
awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
END {chars="abcdefghijklmnopqrstuvwxyz";
for (i=1;i<27;i++) { key=substr(chars,i,1);print key ": " a[key]};}'
a: 2
b: 3
c:
d: 3
e:
f:
g:
h:
i:
j:
k:
l:
m:
n:
o:
p:
q:
r:
s:
t:
u:
v:
w:
x:
y:
z:
1
The output is missingc
as OP's desired output.
– cuonglm
Nov 17 '14 at 6:31
add a comment |
These solutions are case-insensitive:
start cmd:> echo aabbbddd |
awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
END {for (key in a) print key ": " a[key];}'
a: 2
b: 3
d: 3
Or for the complete alphabet:
start cmd:> echo Aabbbddd |
awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
END {chars="abcdefghijklmnopqrstuvwxyz";
for (i=1;i<27;i++) { key=substr(chars,i,1);print key ": " a[key]};}'
a: 2
b: 3
c:
d: 3
e:
f:
g:
h:
i:
j:
k:
l:
m:
n:
o:
p:
q:
r:
s:
t:
u:
v:
w:
x:
y:
z:
1
The output is missingc
as OP's desired output.
– cuonglm
Nov 17 '14 at 6:31
add a comment |
These solutions are case-insensitive:
start cmd:> echo aabbbddd |
awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
END {for (key in a) print key ": " a[key];}'
a: 2
b: 3
d: 3
Or for the complete alphabet:
start cmd:> echo Aabbbddd |
awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
END {chars="abcdefghijklmnopqrstuvwxyz";
for (i=1;i<27;i++) { key=substr(chars,i,1);print key ": " a[key]};}'
a: 2
b: 3
c:
d: 3
e:
f:
g:
h:
i:
j:
k:
l:
m:
n:
o:
p:
q:
r:
s:
t:
u:
v:
w:
x:
y:
z:
These solutions are case-insensitive:
start cmd:> echo aabbbddd |
awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
END {for (key in a) print key ": " a[key];}'
a: 2
b: 3
d: 3
Or for the complete alphabet:
start cmd:> echo Aabbbddd |
awk -v FS= '{for (i=1;i<=NF;i++) a[tolower($i)]++;};
END {chars="abcdefghijklmnopqrstuvwxyz";
for (i=1;i<27;i++) { key=substr(chars,i,1);print key ": " a[key]};}'
a: 2
b: 3
c:
d: 3
e:
f:
g:
h:
i:
j:
k:
l:
m:
n:
o:
p:
q:
r:
s:
t:
u:
v:
w:
x:
y:
z:
edited Nov 17 '14 at 15:42
answered Nov 17 '14 at 6:27
Hauke LagingHauke Laging
56.3k1285135
56.3k1285135
1
The output is missingc
as OP's desired output.
– cuonglm
Nov 17 '14 at 6:31
add a comment |
1
The output is missingc
as OP's desired output.
– cuonglm
Nov 17 '14 at 6:31
1
1
The output is missing
c
as OP's desired output.– cuonglm
Nov 17 '14 at 6:31
The output is missing
c
as OP's desired output.– cuonglm
Nov 17 '14 at 6:31
add a comment |
You could use sed
, uniq
, and sort
:
$ echo -n "aabbbddd" | sed 's/(.)/1n/g'| sort | uniq -c
2 a
3 b
3 d
The above uses sed
to take each character and replace it with itself + a newline (n
). Now with each character on a newline (and sorted) you can use uniq -c
to count the characters.
NOTE: This method will not show any of the characters in between that have zero occurrences.
Alternatively showing each letter's count
$ s="aabbbddd"; for i in {a..z}; do
v=$(echo -n "$s" | grep -oi $i | wc -l); echo "$i : $v"; done
a : 2
b : 3
c : 0
d : 3
e : 0
f : 0
g : 0
h : 0
i : 0
j : 0
k : 0
l : 0
m : 0
n : 0
o : 0
p : 0
q : 0
r : 0
s : 0
t : 0
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0
This works by looping through all the letters of the alphabet:
for i in {a..z}; do .... ; done
Each iteration of the loop we grep through the string looking for a specific character, and use the -o
option of grep
to only return these matches. We then use wc -l
to count how many occurrences of each letter we found, and store it in variable $v
. We then display each iteration:
echo "$i : $v"
NOTE: This approach can handle the strings being out of order.
add a comment |
You could use sed
, uniq
, and sort
:
$ echo -n "aabbbddd" | sed 's/(.)/1n/g'| sort | uniq -c
2 a
3 b
3 d
The above uses sed
to take each character and replace it with itself + a newline (n
). Now with each character on a newline (and sorted) you can use uniq -c
to count the characters.
NOTE: This method will not show any of the characters in between that have zero occurrences.
Alternatively showing each letter's count
$ s="aabbbddd"; for i in {a..z}; do
v=$(echo -n "$s" | grep -oi $i | wc -l); echo "$i : $v"; done
a : 2
b : 3
c : 0
d : 3
e : 0
f : 0
g : 0
h : 0
i : 0
j : 0
k : 0
l : 0
m : 0
n : 0
o : 0
p : 0
q : 0
r : 0
s : 0
t : 0
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0
This works by looping through all the letters of the alphabet:
for i in {a..z}; do .... ; done
Each iteration of the loop we grep through the string looking for a specific character, and use the -o
option of grep
to only return these matches. We then use wc -l
to count how many occurrences of each letter we found, and store it in variable $v
. We then display each iteration:
echo "$i : $v"
NOTE: This approach can handle the strings being out of order.
add a comment |
You could use sed
, uniq
, and sort
:
$ echo -n "aabbbddd" | sed 's/(.)/1n/g'| sort | uniq -c
2 a
3 b
3 d
The above uses sed
to take each character and replace it with itself + a newline (n
). Now with each character on a newline (and sorted) you can use uniq -c
to count the characters.
NOTE: This method will not show any of the characters in between that have zero occurrences.
Alternatively showing each letter's count
$ s="aabbbddd"; for i in {a..z}; do
v=$(echo -n "$s" | grep -oi $i | wc -l); echo "$i : $v"; done
a : 2
b : 3
c : 0
d : 3
e : 0
f : 0
g : 0
h : 0
i : 0
j : 0
k : 0
l : 0
m : 0
n : 0
o : 0
p : 0
q : 0
r : 0
s : 0
t : 0
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0
This works by looping through all the letters of the alphabet:
for i in {a..z}; do .... ; done
Each iteration of the loop we grep through the string looking for a specific character, and use the -o
option of grep
to only return these matches. We then use wc -l
to count how many occurrences of each letter we found, and store it in variable $v
. We then display each iteration:
echo "$i : $v"
NOTE: This approach can handle the strings being out of order.
You could use sed
, uniq
, and sort
:
$ echo -n "aabbbddd" | sed 's/(.)/1n/g'| sort | uniq -c
2 a
3 b
3 d
The above uses sed
to take each character and replace it with itself + a newline (n
). Now with each character on a newline (and sorted) you can use uniq -c
to count the characters.
NOTE: This method will not show any of the characters in between that have zero occurrences.
Alternatively showing each letter's count
$ s="aabbbddd"; for i in {a..z}; do
v=$(echo -n "$s" | grep -oi $i | wc -l); echo "$i : $v"; done
a : 2
b : 3
c : 0
d : 3
e : 0
f : 0
g : 0
h : 0
i : 0
j : 0
k : 0
l : 0
m : 0
n : 0
o : 0
p : 0
q : 0
r : 0
s : 0
t : 0
u : 0
v : 0
w : 0
x : 0
y : 0
z : 0
This works by looping through all the letters of the alphabet:
for i in {a..z}; do .... ; done
Each iteration of the loop we grep through the string looking for a specific character, and use the -o
option of grep
to only return these matches. We then use wc -l
to count how many occurrences of each letter we found, and store it in variable $v
. We then display each iteration:
echo "$i : $v"
NOTE: This approach can handle the strings being out of order.
edited Nov 17 '14 at 6:51
answered Nov 17 '14 at 6:32
slm♦slm
249k66522680
249k66522680
add a comment |
add a comment |
Using only the shell (faster for short strings):
#! /bin/bash -
input=${*:-'aabbbddd'}
tmp=$input
arr=()
maxlen=0
maxchar=''
while ((${#tmp})); do
firstchar=${tmp:0:1}
next=${tmp//"$firstchar"}
len=$((${#tmp}-${#next}))
arr+=("$firstchar: $len")
if ((maxlen<len)); then
maxlen=$len
maxchar=$firstchar
fi
tmp=$next
done
printf '%sn' "${arr[@]}"
echo "The char "$maxchar" appear $maxlen times in "$input""
Called as:
$ ./script
a@2 b@3 d@3
The char "b" appear 3 times in "aabbbddd"
add a comment |
Using only the shell (faster for short strings):
#! /bin/bash -
input=${*:-'aabbbddd'}
tmp=$input
arr=()
maxlen=0
maxchar=''
while ((${#tmp})); do
firstchar=${tmp:0:1}
next=${tmp//"$firstchar"}
len=$((${#tmp}-${#next}))
arr+=("$firstchar: $len")
if ((maxlen<len)); then
maxlen=$len
maxchar=$firstchar
fi
tmp=$next
done
printf '%sn' "${arr[@]}"
echo "The char "$maxchar" appear $maxlen times in "$input""
Called as:
$ ./script
a@2 b@3 d@3
The char "b" appear 3 times in "aabbbddd"
add a comment |
Using only the shell (faster for short strings):
#! /bin/bash -
input=${*:-'aabbbddd'}
tmp=$input
arr=()
maxlen=0
maxchar=''
while ((${#tmp})); do
firstchar=${tmp:0:1}
next=${tmp//"$firstchar"}
len=$((${#tmp}-${#next}))
arr+=("$firstchar: $len")
if ((maxlen<len)); then
maxlen=$len
maxchar=$firstchar
fi
tmp=$next
done
printf '%sn' "${arr[@]}"
echo "The char "$maxchar" appear $maxlen times in "$input""
Called as:
$ ./script
a@2 b@3 d@3
The char "b" appear 3 times in "aabbbddd"
Using only the shell (faster for short strings):
#! /bin/bash -
input=${*:-'aabbbddd'}
tmp=$input
arr=()
maxlen=0
maxchar=''
while ((${#tmp})); do
firstchar=${tmp:0:1}
next=${tmp//"$firstchar"}
len=$((${#tmp}-${#next}))
arr+=("$firstchar: $len")
if ((maxlen<len)); then
maxlen=$len
maxchar=$firstchar
fi
tmp=$next
done
printf '%sn' "${arr[@]}"
echo "The char "$maxchar" appear $maxlen times in "$input""
Called as:
$ ./script
a@2 b@3 d@3
The char "b" appear 3 times in "aabbbddd"
answered 16 mins ago
IsaacIsaac
11.6k11752
11.6k11752
add a comment |
add a comment |
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1
Is your input sorted by default?
– cuonglm
Nov 17 '14 at 6:28
Please clarify your question. Do you need c@0, since that is not a letter within the word?
– slm♦
Nov 17 '14 at 6:35