How to generate a high energy electromagnetic wave? Using high voltage or high current?
$begingroup$
I am about generating an electromagnetic wave which should be powerful enough. So I should manipulate its electric field and magnetic field simultaneously. As far as I know E amplitude depends on the voltage in the circuit and B amplitude depends on current intensity. I do not have any idea to generate EM wave. Which method is infeasible and efficient? (high voltage or high current)
power high-voltage electromagnetic high-current wave
asked 9 hours ago
Mohammad NakhaeeMohammad Nakhaee
111
New contributor
Mohammad Nakhaee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I am about generating an electromagnetic wave which should be powerful enough. So I should manipulate its electric field and magnetic field simultaneously. As far as I know E amplitude depends on the voltage in the circuit and B amplitude depends on current intensity. I do not have any idea to generate EM wave. Which method is infeasible and efficient? (high voltage or high current)
power high-voltage electromagnetic high-current wave
asked 9 hours ago
Mohammad NakhaeeMohammad Nakhaee
111
New contributor
Mohammad Nakhaee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
Your "high voltage" may be my low voltage. My "high current" may be your low current. I can answer this question for you (see below), but in general when asking an engineering question avoid statements like "powerful enough", "high", "low", "bright", "dim", etc. Ask in engineering units (amps, volts, kg, etc.) If you don't know how much of something you need (i.e., what is "powerful enough" then in a separate question describe your task and ask that (i.e. "how much heat do I need to light a candle")).
$endgroup$
– TimWescott
8 hours ago
$begingroup$
should be powerful enough... what does this mean?
$endgroup$
– jsotola
6 hours ago
$begingroup$
talk on your cell phone .... that generates EM waves
$endgroup$
– jsotola
6 hours ago
add a comment |
$begingroup$
I am about generating an electromagnetic wave which should be powerful enough. So I should manipulate its electric field and magnetic field simultaneously. As far as I know E amplitude depends on the voltage in the circuit and B amplitude depends on current intensity. I do not have any idea to generate EM wave. Which method is infeasible and efficient? (high voltage or high current)
power high-voltage electromagnetic high-current wave
asked 9 hours ago
Mohammad NakhaeeMohammad Nakhaee
111
New contributor
Mohammad Nakhaee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I am about generating an electromagnetic wave which should be powerful enough. So I should manipulate its electric field and magnetic field simultaneously. As far as I know E amplitude depends on the voltage in the circuit and B amplitude depends on current intensity. I do not have any idea to generate EM wave. Which method is infeasible and efficient? (high voltage or high current)
power high-voltage electromagnetic high-current wave
power high-voltage electromagnetic high-current wave
asked 9 hours ago
Mohammad NakhaeeMohammad Nakhaee
111
New contributor
Mohammad Nakhaee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 hours ago
Mohammad NakhaeeMohammad Nakhaee
111
New contributor
Mohammad Nakhaee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 hours ago
Mohammad NakhaeeMohammad Nakhaee
111
New contributor
Mohammad Nakhaee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 hours ago
Mohammad NakhaeeMohammad Nakhaee
111
asked 9 hours ago
Mohammad NakhaeeMohammad Nakhaee
111
111
New contributor
Mohammad Nakhaee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mohammad Nakhaee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Mohammad Nakhaee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
Your "high voltage" may be my low voltage. My "high current" may be your low current. I can answer this question for you (see below), but in general when asking an engineering question avoid statements like "powerful enough", "high", "low", "bright", "dim", etc. Ask in engineering units (amps, volts, kg, etc.) If you don't know how much of something you need (i.e., what is "powerful enough" then in a separate question describe your task and ask that (i.e. "how much heat do I need to light a candle")).
$endgroup$
– TimWescott
8 hours ago
$begingroup$
should be powerful enough... what does this mean?
$endgroup$
– jsotola
6 hours ago
$begingroup$
talk on your cell phone .... that generates EM waves
$endgroup$
– jsotola
6 hours ago
add a comment |
1
$begingroup$
Your "high voltage" may be my low voltage. My "high current" may be your low current. I can answer this question for you (see below), but in general when asking an engineering question avoid statements like "powerful enough", "high", "low", "bright", "dim", etc. Ask in engineering units (amps, volts, kg, etc.) If you don't know how much of something you need (i.e., what is "powerful enough" then in a separate question describe your task and ask that (i.e. "how much heat do I need to light a candle")).
$endgroup$
– TimWescott
8 hours ago
$begingroup$
should be powerful enough... what does this mean?
$endgroup$
– jsotola
6 hours ago
$begingroup$
talk on your cell phone .... that generates EM waves
$endgroup$
– jsotola
6 hours ago
1
1
$begingroup$
Your "high voltage" may be my low voltage. My "high current" may be your low current. I can answer this question for you (see below), but in general when asking an engineering question avoid statements like "powerful enough", "high", "low", "bright", "dim", etc. Ask in engineering units (amps, volts, kg, etc.) If you don't know how much of something you need (i.e., what is "powerful enough" then in a separate question describe your task and ask that (i.e. "how much heat do I need to light a candle")).
$endgroup$
– TimWescott
8 hours ago
$begingroup$
Your "high voltage" may be my low voltage. My "high current" may be your low current. I can answer this question for you (see below), but in general when asking an engineering question avoid statements like "powerful enough", "high", "low", "bright", "dim", etc. Ask in engineering units (amps, volts, kg, etc.) If you don't know how much of something you need (i.e., what is "powerful enough" then in a separate question describe your task and ask that (i.e. "how much heat do I need to light a candle")).
$endgroup$
– TimWescott
8 hours ago
$begingroup$
should be powerful enough ... what does this mean?$endgroup$
– jsotola
6 hours ago
$begingroup$
should be powerful enough ... what does this mean?$endgroup$
– jsotola
6 hours ago
$begingroup$
talk on your cell phone .... that generates EM waves
$endgroup$
– jsotola
6 hours ago
$begingroup$
talk on your cell phone .... that generates EM waves
$endgroup$
– jsotola
6 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
If you are generating an electromagnetic wave in free space then the ratio of the E field to the H field is fixed at 377$Omega$ (yes, ohms -- the units work out).
You would hope that would answer your question, but it doesn't because in order to generate a pulse or continuous waveform of electricity and turn it into an electromagnetic wave you need to couple from your circuit to free space (or to whatever material you want the electromagnetic wave to be in). The device that does this is an antenna, and depending on their design antennas can have very different input impedances and efficiencies, even though the EM field that they generate has a ratio of E to M of 377$Omega$ in free space, or the characteristic impedance of whatever material you're launching the EM pulse into.
So the actual answer to your question is "either one, depending on your antenna".
(Note: I looked at whether I should vote to close your question. I don't think I should, even though the answer to it as written is "this question is unanswerable". To really answer your question requires about as much information as you'd get if you got a Master's degree in RF circuit design with a lot of attention paid to antenna design.)
answered 8 hours ago
TimWescottTimWescott
3,7071211
$endgroup$
$begingroup$
Trying to take out drones at 80,000 feet?
$endgroup$
– analogsystemsrf
1 hour ago
add a comment |
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1 Answer
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$begingroup$
If you are generating an electromagnetic wave in free space then the ratio of the E field to the H field is fixed at 377$Omega$ (yes, ohms -- the units work out).
You would hope that would answer your question, but it doesn't because in order to generate a pulse or continuous waveform of electricity and turn it into an electromagnetic wave you need to couple from your circuit to free space (or to whatever material you want the electromagnetic wave to be in). The device that does this is an antenna, and depending on their design antennas can have very different input impedances and efficiencies, even though the EM field that they generate has a ratio of E to M of 377$Omega$ in free space, or the characteristic impedance of whatever material you're launching the EM pulse into.
So the actual answer to your question is "either one, depending on your antenna".
(Note: I looked at whether I should vote to close your question. I don't think I should, even though the answer to it as written is "this question is unanswerable". To really answer your question requires about as much information as you'd get if you got a Master's degree in RF circuit design with a lot of attention paid to antenna design.)
answered 8 hours ago
TimWescottTimWescott
3,7071211
$endgroup$
$begingroup$
Trying to take out drones at 80,000 feet?
$endgroup$
– analogsystemsrf
1 hour ago
add a comment |
$begingroup$
If you are generating an electromagnetic wave in free space then the ratio of the E field to the H field is fixed at 377$Omega$ (yes, ohms -- the units work out).
You would hope that would answer your question, but it doesn't because in order to generate a pulse or continuous waveform of electricity and turn it into an electromagnetic wave you need to couple from your circuit to free space (or to whatever material you want the electromagnetic wave to be in). The device that does this is an antenna, and depending on their design antennas can have very different input impedances and efficiencies, even though the EM field that they generate has a ratio of E to M of 377$Omega$ in free space, or the characteristic impedance of whatever material you're launching the EM pulse into.
So the actual answer to your question is "either one, depending on your antenna".
(Note: I looked at whether I should vote to close your question. I don't think I should, even though the answer to it as written is "this question is unanswerable". To really answer your question requires about as much information as you'd get if you got a Master's degree in RF circuit design with a lot of attention paid to antenna design.)
answered 8 hours ago
TimWescottTimWescott
3,7071211
$endgroup$
$begingroup$
Trying to take out drones at 80,000 feet?
$endgroup$
– analogsystemsrf
1 hour ago
add a comment |
$begingroup$
If you are generating an electromagnetic wave in free space then the ratio of the E field to the H field is fixed at 377$Omega$ (yes, ohms -- the units work out).
You would hope that would answer your question, but it doesn't because in order to generate a pulse or continuous waveform of electricity and turn it into an electromagnetic wave you need to couple from your circuit to free space (or to whatever material you want the electromagnetic wave to be in). The device that does this is an antenna, and depending on their design antennas can have very different input impedances and efficiencies, even though the EM field that they generate has a ratio of E to M of 377$Omega$ in free space, or the characteristic impedance of whatever material you're launching the EM pulse into.
So the actual answer to your question is "either one, depending on your antenna".
(Note: I looked at whether I should vote to close your question. I don't think I should, even though the answer to it as written is "this question is unanswerable". To really answer your question requires about as much information as you'd get if you got a Master's degree in RF circuit design with a lot of attention paid to antenna design.)
answered 8 hours ago
TimWescottTimWescott
3,7071211
$endgroup$
If you are generating an electromagnetic wave in free space then the ratio of the E field to the H field is fixed at 377$Omega$ (yes, ohms -- the units work out).
You would hope that would answer your question, but it doesn't because in order to generate a pulse or continuous waveform of electricity and turn it into an electromagnetic wave you need to couple from your circuit to free space (or to whatever material you want the electromagnetic wave to be in). The device that does this is an antenna, and depending on their design antennas can have very different input impedances and efficiencies, even though the EM field that they generate has a ratio of E to M of 377$Omega$ in free space, or the characteristic impedance of whatever material you're launching the EM pulse into.
So the actual answer to your question is "either one, depending on your antenna".
(Note: I looked at whether I should vote to close your question. I don't think I should, even though the answer to it as written is "this question is unanswerable". To really answer your question requires about as much information as you'd get if you got a Master's degree in RF circuit design with a lot of attention paid to antenna design.)
answered 8 hours ago
TimWescottTimWescott
3,7071211
answered 8 hours ago
TimWescottTimWescott
3,7071211
answered 8 hours ago
TimWescottTimWescott
3,7071211
answered 8 hours ago
TimWescottTimWescott
3,7071211
3,7071211
$begingroup$
Trying to take out drones at 80,000 feet?
$endgroup$
– analogsystemsrf
1 hour ago
add a comment |
$begingroup$
Trying to take out drones at 80,000 feet?
$endgroup$
– analogsystemsrf
1 hour ago
$begingroup$
Trying to take out drones at 80,000 feet?
$endgroup$
– analogsystemsrf
1 hour ago
$begingroup$
Trying to take out drones at 80,000 feet?
$endgroup$
– analogsystemsrf
1 hour ago
add a comment |
Mohammad Nakhaee is a new contributor. Be nice, and check out our Code of Conduct.
Mohammad Nakhaee is a new contributor. Be nice, and check out our Code of Conduct.
Mohammad Nakhaee is a new contributor. Be nice, and check out our Code of Conduct.
Mohammad Nakhaee is a new contributor. Be nice, and check out our Code of Conduct.
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1
$begingroup$
Your "high voltage" may be my low voltage. My "high current" may be your low current. I can answer this question for you (see below), but in general when asking an engineering question avoid statements like "powerful enough", "high", "low", "bright", "dim", etc. Ask in engineering units (amps, volts, kg, etc.) If you don't know how much of something you need (i.e., what is "powerful enough" then in a separate question describe your task and ask that (i.e. "how much heat do I need to light a candle")).
$endgroup$
– TimWescott
8 hours ago
$begingroup$
should be powerful enough... what does this mean?$endgroup$
– jsotola
6 hours ago
$begingroup$
talk on your cell phone .... that generates EM waves
$endgroup$
– jsotola
6 hours ago